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Determine the speed and direction of propagation of each of the following sinusoidal waves, assuming that \(x\) and \(y\) are measured in meters and \(t\) in seconds. (a) \(y=0.60 \cos (3.0 x-15 t+2)\) (b) \(y=0.40 \cos (3.0 x+15 t-2)\) (c) \(y=1.2 \sin (15 t+2.0 x)\) (d) \(y=0.20 \sin [12 t-(x / 2)+\pi]\)

Short Answer

Expert verified
The speed and direction of propagation are: (a) 5 m/s in the positive x direction, (b) 5 m/s in the negative x direction, (c) 7.5 m/s in the negative x direction, and (d) 24 m/s in the negative x direction.

Step by step solution

01

Recognizing the Standard Waveform

The standard forms of sinusoidal waves are \(y = A \cos(kx - wt + φ )\) and \(y = A \sin(kx - wt + φ )\) for cosine and sine waves respectively with a phase shift, where• \(A\) is the amplitude;• \(k\) is the wave number;• \(w\) is the angular frequency;• \(φ \) is the initial phase angle.
02

Identify \(-wt\) in the Equation

Identifying the sign of \(wt\) (angular frequency times time) is crucial for determining direction. If the coefficient \(wt\) is negative, the wave moves in the positive x direction. If the coefficient \(wt\) is positive, the wave moves in the negative x direction.
03

Calculate Speed of the Waves

The speed of a wave can be calculated using the formula \(v = w/k\), where \(v\) is the speed of the wave, \(w\) is the angular frequency and \(k\) is the wave number.
04

Calculating the propagation for (a)

For \(y=0.60 \cos (3.0 x-15 t+2)\),The wave number \(k = 3.0\), the angular frequency \(w=15\). The term \(-15t\) indicates that the wave is moving in positive x direction. By using the formula \(v = w/k\), the speed \(v = 15/3.0 = 5 m/s\). Therefore, for (a), the wave moves in positive x direction with speed 5 m/s.
05

Calculating the propagation for (b)

For \(y=0.40 \cos (3.0 x+15 t-2)\),The wave number \(k = 3.0\), the angular frequency \(w=15\). The term \(15t\) indicates that the wave is moving in negative x direction. By using the formula \(v = w/k\), the speed \(v = 15/3.0 = 5 m/s\). Therefore, for (b), the wave moves in negative x direction with speed 5 m/s.
06

Calculating the propagation for (c)

For \(y = 1.2 \sin (15 t+2.0 x)\),The wave number \(k = 2.0\), the angular frequency \(w=15\). The term \(15t\) indicates that the wave is moving in negative x direction. By using the formula \(v = w/k\), the speed \(v = 15/2.0 = 7.5 m/s\). Therefore, for (c), the wave moves in negative x direction with speed 7.5 m/s.
07

Calculating the propagation for (d)

For \(y=0.20 \sin [12 t-(x / 2) +\pi]\),The wave number \(k = 1/2\), the angular frequency \(w = 12\). The term \(12t\) indicates that the wave is moving in negative x direction. By using the formula \(v = w/k\), the speed \(v = 12/(1/2)= 24 m/s\). Therefore, for (d), the wave moves in negative x direction with speed 24 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sinusoidal Waves
Sinusoidal waves are a fundamental concept in physics, representing a periodic oscillation that travels through space and time. They are characterized by their smooth, repetitive waveforms, which can be described by either a sine or cosine function, depending on the initial conditions.

When looking at a mathematical expression for a sinusoidal wave, you typically see it in the form of
\(y=A\cos(kx-\omega t +\phi)\) or \(y=A\sin(kx-\omega t +\phi)\), where:\(A\) represents the amplitude, \(k\) is the wave number, \(\omega\) is the angular frequency, and \(\phi\) is the phase shift. These components all relate to physical properties of the wave such as its height, how often it oscillates, the speed at which it propagates, and where it starts in its cycle.

Understanding sinusoidal waves is crucial because they serve as simplified models for more complex phenomena, ranging from sound and light to quantum mechanics.
Angular Frequency
Angular frequency (often denoted by the Greek letter \(\omega\)) is a measure of how quickly a wave oscillates in time. It is directly related to the frequency (\(f\)), which represents the number of oscillations per second. The relationship between angular frequency and frequency is given by the formula \(\omega = 2\pi f\).

An important aspect of angular frequency is its role in determining the wave's speed and direction. In particular, the formula \(v=\frac{\omega}{k}\) shows that the speed (\(v\)) of the wave is the ratio of the angular frequency to the wave number. This formula is pivotal in solving problems dealing with wave motion and propagation. It can help to discern why waves described by equations such as \(y=0.60\cos(3.0x-15t+2)\) and \(y=0.40\cos(3.0x+15t-2)\) share the same speed but move in opposite directions.
Wave Number
The wave number (represented by the symbol \(k\)) is a spatial counterpart to the angular frequency, expressing how many wave cycles occur over a given distance. It is often defined as the number of radians per unit length, or mathematically as \(k=\frac{2\pi}{\lambda}\), where \(\lambda\) is the wavelength - the physical distance over which the wave repeats itself.

As identified in the step-by-step solutions, the wave number plays a pivotal role in determining the speed of a wave's propagation through the space. By assessing \(k\) in conjunction with \(\omega\), one can use the formula \(v=\frac{\omega}{k}\) to find velocity, regardless of whether the wave in question is expressed using the sine function, like \(y=1.2\sin(15t+2.0x)\), or cosine function.
Phase Shift
Phase shift, denoted by \(\phi\), refers to the horizontal shift of the wave relative to its standard position. It indicates at what point in the oscillation cycle the wave begins. A positive phase shift means the wave starts later, while a negative phase shift signifies an earlier start than a standard sine or cosine wave.

The impact of phase shift becomes evident when comparing waves with identical angular frequencies and wave numbers but different initial positions. For example, in the equations \(y=0.60\cos(3.0x-15t+2)\) and \(y=0.40\cos(3.0x+15t-2)\), the phase shifts are +2 and -2 respectively. Although the phase shift does not affect the wave speed or direction, it is crucial for accurately representing the physical situation the wave describes, such as in applications involving interference and wave superposition.

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Most popular questions from this chapter

It is found that a \(6.00-\mathrm{m}\) segment of a long string contains four complete waves and has a mass of \(180 \mathrm{g} .\) The string is vibrating sinusoidally with a frequency of \(50.0 \mathrm{Hz}\) and a peak-to-valley distance of \(15.0 \mathrm{cm} .\) (The "peak-to-valley" distance is the vertical distance from the farthest positive position to the farthest negative position.) (a) Write the function that describes this wave traveling in the positive \(x\) direction. (b) Determine the power being supplied to the string.

S and P waves, simultaneously radiated from the hypocenter of an earthquake, are received at a seismographic station \(17.3 \mathrm{s}\) apart. Assume the waves have traveled over the same path at speeds of \(4.50 \mathrm{km} / \mathrm{s}\) and \(7.80 \mathrm{km} / \mathrm{s} .\) Find the distance from the seismograph to the hypocenter of the quake.

A wire of density \(\rho\) is tapered so that its cross-sectional area varies with \(x\) according to $$A=\left(1.0 \times 10^{-3} x+0.010\right) \mathrm{cm}^{2}$$ (a) If the wire is subject to a tension \(T\), derive a relationship for the speed of a wave as a function of position. (b) What If? If the wire is aluminum and is subject to a tension of \(24.0 \mathrm{N},\) determine the speed at the origin and at \(x=10.0 \mathrm{m}\).

A string on a musical instrument is held under tension \(T\) and extends from the point \(x=0\) to the point \(x=L .\) The string is overwound with wire in such a way that its mass per unit length \(\mu(x)\) increases uniformly from \(\mu_{0}\) at \(x=0\) to \(\mu_{L}\) at \(x=L .\) (a) Find an expression for \(\mu(x)\) as a function of \(x\) over the range \(0 \leq x \leq L\). (b) Show that the time interval required for a transverse pulse to travel the length of the string is given by $$\Delta t=\frac{2 L\left(\mu_{L}+\mu_{0}+\sqrt{\mu_{L} \mu_{0}}\right)}{3 \sqrt{T}(\sqrt{\mu_{L}}+\sqrt{\mu_{0}})}$$

For a certain transverse wave, the distance between two successive crests is \(1.20 \mathrm{m},\) and eight crests pass a given point along the direction of travel every 12.0 s. Calculate the wave speed.

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