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Transverse waves with a speed of \(50.0 \mathrm{m} / \mathrm{s}\) are to be produced in a taut string. A 5.00 -m length of string with a total mass of \(0.0600 \mathrm{kg}\) is used. What is the required tension?

Short Answer

Expert verified
The required tension on the string to produce transverse waves with the given speed is 30.0 N.

Step by step solution

01

Calculate the Linear Mass Density

First, we need to calculate the linear mass density of the string. The linear mass density, \(\mu\), is calculated as the mass of the string divided by its length. In this case, \(\mu = 0.0600 \mathrm{kg} / 5.00 \mathrm{m} = 0.0120 \mathrm{kg/m}\).
02

Substitute the values into the wave speed formula and solve for Tension

We have the formula for the speed of a wave on a string as \(v = \sqrt{T/\mu}\). We can rearrange this formula to solve for \(T\), which gives us \(T = \mu \cdot v^2\). Substituting the given values, we get \(T = 0.0120 \mathrm{kg/m} \times (50.0 \mathrm{m/s})^2 = 30.0 \mathrm{N}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Mass Density
Understanding linear mass density is crucial for calculating the dynamics of objects like strings and cables. It refers to the mass of an object per unit of length and is typically denoted by the Greek letter \(\mu\). This physical property is measured in kilograms per meter (kg/m) in the metric system.

In our exercise, linear mass density is calculated by taking the total mass of the string and dividing it by its total length. This gives us a value that represents the distribution of mass along the string, which is essential for further calculations, such as determining wave speed or the tension needed in the string for certain wave behaviors.

To calculate linear mass density, simply use the formula \(\mu = \frac{mass}{length}\), ensuring that the mass and length are in compatible units, such as kilograms and meters.
Transverse Waves
Transverse waves are a type of mechanical wave where the motion of the medium's particles is perpendicular to the direction of the wave's travel. These waves are commonly seen in strings or ropes when they are shaken up and down.

Some key characteristics of transverse waves include their crest and trough, which are the highest and lowest points of a wave, respectively. The wavelength is the distance between two consecutive crests or troughs and represents one complete cycle of the wave. Frequency, measured in Hertz (Hz), is the number of wavelengths that pass a fixed point per second.

Wave speed is crucial in understanding these waves; it's determined by both the tension in the medium and the linear mass density. A higher tension often results in a faster wave speed; however, this is closely related to the medium's linear mass density. The balance of these two properties dictates the speed at which waves travel through the medium.
Tension in Strings
Tension is the force exerted along the length of an object like a string or cable. For a wave to travel through a string, the string must be taut; in other words, there must be enough tension to overcome any slack and maintain a straight form.

The relationship between tension and wave speed is depicted by the equation \(v = \sqrt{T/\mu}\), where \(v\) is the wave speed, \(T\) is the tension in the string, and \(\mu\) is the linear mass density. If the tension is too low, the wave will travel slowly; if it's too high, it can cause the string to snap.

In the exercise, we use the rearranged form of the wave speed equation to solve for tension. It becomes apparent that having both a known wave speed and linear mass density allows us to determine the precise tension needed to produce a wave that travels at a desired speed through a string.

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Most popular questions from this chapter

(a) Determine the speed of transverse waves on a string under a tension of \(80.0 \mathrm{N}\) if the string has a length of \(2.00 \mathrm{m}\) and a mass of \(5.00 \mathrm{g} .\) (b) Calculate the power required to generate these waves if they have a wavelength of \(16.0 \mathrm{cm}\) and an amplitude of \(4.00 \mathrm{cm} .\)

The wave function for a traveling wave on a taut string is (in SI units) $$y(x, t)=(0.350 \mathrm{m}) \sin (10 \pi t-3 \pi x+\pi / 4)$$ (a) What are the speed and direction of travel of the wave? (b) What is the vertical position of an element of the string at \(t=0, x=0.100 \mathrm{m} ?\) (c) What are the wavelength and frequency of the wave? (d) What is the maximum magnitude of the transverse speed of the string?

An astronaut on the Moon wishes to measure the local value of the free-fall acceleration by timing pulses traveling down a wire that has an object of large mass suspended from it. Assume a wire has a mass of \(4.00 \mathrm{g}\) and a length of \(1.60 \mathrm{m},\) and that a \(3.00-\mathrm{kg}\) object is suspended from it. A pulse requires 36.1 ms to traverse the length of the wire. Calculate \(g_{\text {Moon }}\) from these data. (You may ignore the mass of the wire when calculating the tension in it.)

A sinusoidal wave is described by $$y=(0.25 \mathrm{m}) \sin (0.30 x-40 t)$$ where \(x\) and \(y\) are in meters and \(t\) is in seconds. Determine for this wave the (a) amplitude, (b) angular frequency, (c) angular wave number, (d) wavelength, (e) wave speed, and (f) direction of motion.

A transverse traveling wave on a taut wire has an amplitude of \(0.200 \mathrm{mm}\) and a frequency of \(500 \mathrm{Hz}\). It travels with a speed of \(196 \mathrm{m} / \mathrm{s}\). (a) Write an equation in SI units of the form \(y=A \sin (k x-\omega t)\) for this wave. (b) The mass per unit length of this wire is \(4.10 \mathrm{g} / \mathrm{m} .\) Find the tension in the wire.

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