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A sinusoidal wave on a string is described by $$y=(0.51 \mathrm{cm}) \sin (k x-\omega t)$$ where \(k=3.10 \mathrm{rad} / \mathrm{cm}\) and \(\omega=9.30 \mathrm{rad} / \mathrm{s} .\) How far does a wave crest move in 10.0 s? Does it move in the positive or negative \(x\) direction?

Short Answer

Expert verified
In 10.0 s, the wave crest moves 30.0 cm in the positive \(x\) direction.

Step by step solution

01

Identify Propagation Velocity

Firstly, identify propagation velocity of the wave. The velocity of propagation (v) of a sinusoidal wave is related to wave number (k) and angular frequency (\(\omega\)) via the relationship \(v = \omega / k\). Substitute given values to calculate the wave velocity.
02

Determine Distance

Then calculate the distance. When the time is given, the distance can be calculated by the simple formula : distance = speed * time. Substitute calculated velocity and given time to determine how far a wave crest moves in 10.0 s.
03

Determine Propagation Direction

Finally, determine propagation direction. The sign of \(\omega t\) in the wave equation determines the direction of propagation. If there is a negative sign in front of \(\omega t\) (as with this problem), the wave is moving in the positive \(x\) direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Propagation Velocity
Propagation velocity is an important concept when dealing with waves. It tells us how fast a wave is moving through a medium. For a sinusoidal wave, specifically, the propagation velocity is calculated by dividing the angular frequency by the wave number. This relationship can be expressed as:
  • \( v = \frac{\omega}{k} \)
Here, \( v \) is the propagation velocity, \( \omega \) is the angular frequency, and \( k \) is the wave number. This equation provides a straightforward way to find out how quickly a wave crest is moving.

In the context of our exercise, the angular frequency \( \omega \) is given as \( 9.30 \mathrm{rad} / \mathrm{s} \) and the wave number \( k \) is \( 3.10 \mathrm{rad} / \mathrm{cm} \). By substituting these values into our formula, we can determine the wave's propagation speed, which is essential to then calculate the distance it travels.
Wave Number
The wave number is a key aspect of wave physics. It tells us about the number of wave cycles in a unit distance. The wave number \( k \) is defined in terms of the spatial wavelength \( \lambda \) as follows:
  • \( k = \frac{2\pi}{\lambda} \)
This constant is expressed in radians per unit distance, indicating how many radians correspond to the physical distance of a single wave cycle.

In our problem, the wave number \( k \) is \( 3.10 \mathrm{rad/cm} \). This means every centimeter along the wave contains \( 3.10 \) radians, helping us understand the spatial frequency of our wave. It's a crucial factor for determining the wave's propagation velocity when combined with the angular frequency.
Angular Frequency
Angular frequency describes how fast the wave oscillates in time. It essentially tells you how many wave crests pass by a point in one second. It is connected to the time period \( T \) of the wave by the formula:
  • \( \omega = \frac{2\pi}{T} \)
Angular frequency is expressed in radians per second, signifying how many radians a wave completes for a given time interval.

In our specific exercise, \( \omega \) is \( 9.30 \mathrm{rad} / \mathrm{s} \). This means that within each second, a wave crest moves through \( 9.30 \) radians. This concept directly ties to how quickly the wave crests move along the string, making angular frequency a vital component alongside the wave number in assessing the wave's behavior.

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Most popular questions from this chapter

A taut rope has a mass of \(0.180 \mathrm{kg}\) and a length of \(3.60 \mathrm{m}\) What power must be supplied to the rope in order to generate sinusoidal waves having an amplitude of \(0.100 \mathrm{m}\) and a wavelength of \(0.500 \mathrm{m}\) and traveling with a speed of \(30.0 \mathrm{m} / \mathrm{s} ?\)

S and P waves, simultaneously radiated from the hypocenter of an earthquake, are received at a seismographic station \(17.3 \mathrm{s}\) apart. Assume the waves have traveled over the same path at speeds of \(4.50 \mathrm{km} / \mathrm{s}\) and \(7.80 \mathrm{km} / \mathrm{s} .\) Find the distance from the seismograph to the hypocenter of the quake.

A sinusoidal wave of wavelength \(2.00 \mathrm{m}\) and amplitude \(0.100 \mathrm{m}\) travels on a string with a speed of \(1.00 \mathrm{m} / \mathrm{s}\) to the right. Initially, the left end of the string is at the origin. Find (a) the frequency and angular frequency, (b) the angular wave number, and (c) the wave function for this wave. Determine the equation of motion for (d) the left end of the string and (e) the point on the string at \(x=\) \(1.50 \mathrm{m}\) to the right of the left end. (f) What is the maximum speed of any point on the string?

A transverse wave on a string is described by the wave function $$y=(0.120 \mathrm{m}) \sin [(\pi x / 8)+4 \pi t]$$ (a) Determine the transverse speed and acceleration at \(t=0.200 \mathrm{s}\) for the point on the string located at \(x=\) 1.60 \(\mathrm{m}\). (b) What are the wavelength, period, and speed of propagation of this wave?

A string on a musical instrument is held under tension \(T\) and extends from the point \(x=0\) to the point \(x=L .\) The string is overwound with wire in such a way that its mass per unit length \(\mu(x)\) increases uniformly from \(\mu_{0}\) at \(x=0\) to \(\mu_{L}\) at \(x=L .\) (a) Find an expression for \(\mu(x)\) as a function of \(x\) over the range \(0 \leq x \leq L\). (b) Show that the time interval required for a transverse pulse to travel the length of the string is given by $$\Delta t=\frac{2 L\left(\mu_{L}+\mu_{0}+\sqrt{\mu_{L} \mu_{0}}\right)}{3 \sqrt{T}(\sqrt{\mu_{L}}+\sqrt{\mu_{0}})}$$

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