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A simple harmonic oscillator takes \(12.0 \mathrm{s}\) to undergo five complete vibrations. Find (a) the period of its motion, (b) the frequency in hertz, and (c) the angular frequency in radians per second.

Short Answer

Expert verified
The period of the simple harmonic oscillator is \(2.4\) seconds, the frequency is \(0.42\) Hz, and the angular frequency is \(2.64\) radians per second.

Step by step solution

01

Determine the Time Period(T) of Oscillation

The period of oscillation is the time it takes for one cycle of vibration to complete. Given that it takes 12.0 seconds to undergo five complete vibrations, we can divide total time by the number of vibrations to find the time period. So, the Time period (T)= total time of oscillations / number of oscillations = \(12.0 / 5\) s = \(2.4\) s
02

Calculate the Frequency(f)

The frequency (f) of an oscillating object is the reciprocal of the period (T). It denotes how often a periodic event happens, and the standard unit of measurement is hertz (Hz). So, frequency (f) = \(1 / T\) = \(1 / 2.4\) = \(0.42\) Hz
03

Compute the Angular Frequency (ω)

The angular frequency (ω) is the rate at which an object vibrates and is calculated as \(2π\) times the frequency. So, angular frequency (ω) = \(2πf\) = \(2 * π * 0.42\) = \(2.64\) radians per second

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Oscillation Period
Understanding the oscillation period of a simple harmonic oscillator is crucial for students studying physics or engineering. It's the time it takes for one complete cycle of motion, which could be a swing of a pendulum, a cycle of a spring, or any repeating motion. From our problem, we know that it took the oscillator 12 seconds to make five complete vibrations. To find the period of motion, we divide the total time by the number of vibrations:

\[ T = \frac{12.0 \text{s}}{5} = 2.4 \text{s} \]
This straightforward division gives us the period (T), which is 2.4 seconds. It reflects how long the oscillator takes to return to its original position. For students, it is important to remember that this value represents the duration of one full cycle, regardless of the amplitude or the size of the oscillation. The amplitude doesn't affect the period in a simple harmonic oscillator, highlighting its unique isochronous property.
Frequency in Hertz
The next step in our understanding of oscillatory motion is the concept of frequency in hertz (Hz). Frequency describes how many cycles of oscillation occur in one second. It is the reciprocal of the period, meaning it’s calculated by dividing one by the period (T).

\[ f = \frac{1}{T} = \frac{1}{2.4 \text{s}} = 0.42 \text{ Hz} \]
In the context of our example, the oscillator completes 0.42 cycles per second. Therefore, its frequency is 0.42 Hz. This value tells us how 'fast' the oscillator is vibrating. Frequency in hertz is an essential concept in physics, as it is used in various applications ranging from music to electronics, indicating how frequent an event such as a wave or a vibration occurs within a second.
Angular Frequency
Lastly, let's delve into the concept of angular frequency, represented by the Greek letter omega (\(\omega\)). Angular frequency connects the concepts of time period and frequency to rotational motion, which is crucial when motions involve circular paths or angles. It is measured in radians per second and defined as the product of 2Ï€ and the frequency. The calculation for our oscillator's angular frequency is given by:

\[ \omega = 2\pi f = 2\pi \times 0.42 = 2.64 \text{ radians per second} \]
Angular frequency is highly relevant in contexts involving wave motion, electrical engineering, and any scenario where sinusoidal functions are used to model periodic behavior. It relates to how quickly an object moves through its angle in a circular path during oscillation.

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Most popular questions from this chapter

A ball dropped from a height of \(4.00 \mathrm{m}\) makes a perfectly elastic collision with the ground. Assuming no mechanical energy is lost due to air resistance, (a) show that the ensuing motion is periodic and (b) determine the period of the motion. (c) Is the motion simple harmonic? Explain.

A particle moving along the \(x\) axis in simple harmonic motion starts from its equilibrium position, the origin, at \(t=0\) and moves to the right. The amplitude of its motion is \(2.00 \mathrm{cm},\) and the frequency is \(1.50 \mathrm{Hz}\). (a) Show that the position of the particle is given by $$x=(2.00 \mathrm{cm}) \sin (3.00 \pi t)$$.Determine (b) the maximum speed and the earliest time \((t>0)\) at which the particle has this speed, (c) the maximum acceleration and the earliest time \((t>0)\) at which the particle has this acceleration, and (d) the total distance traveled between \(t=0\) and \(t=1.00 \mathrm{s}\).

A small object is attached to the end of a string to form a simple pendulum. The period of its harmonic motion is measured for small angular displacements and three lengths, each time clocking the motion with a stopwatch for 50 oscillations. For lengths of \(1.000 \mathrm{m}, 0.750 \mathrm{m}\) and \(0.500 \mathrm{m},\) total times of \(99.8 \mathrm{s}, 86.6 \mathrm{s},\) and \(71.1 \mathrm{s}\) are measured for 50 oscillations. (a) Determine the period of motion for each length. (b) Determine the mean value of \(g\) obtained from these three independent measurements, and compare it with the accepted value. (c) Plot \(T^{2}\) versus \(L,\) and obtain a value for \(g\) from the slope of your best-fit straight-line graph. Compare this value with that obtained in part (b).

An automobile having a mass of \(1000 \mathrm{kg}\) is driven into a brick wall in a safety test. The bumper behaves like a spring of force constant \(5.00 \times 10^{6} \mathrm{N} / \mathrm{m}\) and compresses \(3.16 \mathrm{cm}\) as the car is brought to rest. What was the speed of the car before impact, assuming that no mechanical energy is lost during impact with the wall?

A \(7.00-\mathrm{kg}\) object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of \(2.60 \mathrm{s}\). Find the force constant of the spring.

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