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A simple pendulum with a length of \(2.23 \mathrm{m}\) and a mass of \(6.74 \mathrm{kg}\) is given an initial speed of \(2.06 \mathrm{m} / \mathrm{s}\) at its equilibrium position. Assume it undergoes simple harmonic motion, and determine its (a) period, (b) total energy, and (c) maximum angular displacement.

Short Answer

Expert verified
The period of the pendulum is approximately \( T = 2\pi\sqrt{\frac{2.23}{9.8}} \) seconds, with a total energy of \( E = 0.5*6.74*(2.06)^2 \) Joules. Given the total energy, the maximum angular displacement is computed using \(\cos^{-1}(1-\frac{E_{total}}{mgl})\).

Step by step solution

01

Find the Period

To calculate the pendulum's period, we will use the formula \(T=2\pi\sqrt{\frac{l}{g}}\). The length \(l\) of the pendulum is 2.23m and acceleration due to gravity \(g\) is 9.8 m/s^2. Substituting in these values, we get \(T=2\pi\sqrt{\frac{2.23}{9.8}} \).
02

Calculate the Total Energy

Next, calculate the total energy of the pendulum using the kinetic energy formula, \(E=0.5mv^2\), because initially the pendulum has only kinetic energy. The mass \(m\) of the pendulum is 6.74kg and the velocity \(v\) is 2.06 m/s. Therefore, substituting these values into the formula we get \(E=0.5*6.74*(2.06)^2\).
03

Compute the Maximum Angular Displacement

To find maximum angular displacement, we know that \(E_{total}= mgh_{maximum}\) where \(h_{maximum}\) can be calculated as \(l(1-\cos(\theta_{max}))\). With some rearrangement, \(\theta_{max}\) becomes \(\cos^{-1}(1-\frac{E_{total}}{mgl})\). Thus, angular displacement can be measured.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pendulum Period
Understanding the pendulum's period is crucial for analyzing its motion. The period, denoted by 'T', is the time it takes for the pendulum to complete one full swing back and forth. In the context of a simple pendulum, we can determine this period using the formula: \[ T = 2\textpi \times \textsqrt{\frac{l}{g}} \]where 'l' represents the length of the pendulum, and 'g' is the acceleration due to gravity, commonly accepted as 9.8 m/s2 on Earth's surface. For the given pendulum with a length of 2.23m, the calculation is straightforward.By plugging in the numbers, we find that the period does not depend on the mass of the bob or its initial speed, but solely on the length of the string and the acceleration due to gravity. It's a powerful insight because it means that, for small angles, every pendulum of the same length swings with the same rhythm, regardless of the weight attached. This concept is pivotal to clocks with pendulum mechanisms, allowing for consistent timekeeping.To enhance student comprehension, one might perform a hands-on experiment by varying the length of a pendulum to observe the changes in the period, providing practical reinforcement of the concept.
Mechanical Energy
The concept of mechanical energy in relation to a pendulum is a blend of kinetic and potential energy. Initially, when the pendulum is released from a certain height, it possesses maximum potential energy and no kinetic energy. As it moves through its equilibrium position, the potential energy is converted into kinetic energy. The total mechanical energy of the pendulum remains constant throughout its motion, assuming there is no air resistance or other forms of energy loss.The total mechanical energy ('E') is calculated as the sum of kinetic energy ('KE') and potential energy ('PE'), expressed as:\[ E = KE + PE \]For a simple pendulum in the exercise, the kinetic energy is calculated when the pendulum passes through its equilibrium point using the formula:\[ KE = 0.5 \times m \times v^2 \]where 'm' is mass and 'v' is velocity. Because the pendulum starts with a push and has only kinetic energy at the equilibrium position, this becomes the total mechanical energy which remains constant throughout its motion.Understanding this interplay of energy conversion is essential for students, particularly when discussing energy conservation in physics. Knowing that the energy at the lowest point translates into potential energy at the highest point provides a powerful illustration of energy conservation in oscillatory systems like pendulums.
Angular Displacement
Angular displacement, often represented by the Greek letter theta (\(\theta\)), measures the angle through which the pendulum swings from its equilibrium position. It is a crucial parameter in describing the motion of the pendulum and can be tied directly to its kinetic and potential energy distributions. For a simple pendulum, the maximum angular displacement - the furthest angle from the vertical - occurs at the peak of its swing where the speed is zero.To calculate the maximum angular displacement, the relationship between the pendulum's energy and its position can be used. From the provided exercise, we see that the total energy of the pendulum at its maximum height can also be described by the formula:\[ E_{total} = mgh_{maximum} \]Here, 'h' represents the height which corresponds to the length of the pendulum and the maximum angle, given by:\[ h_{maximum} = l(1 - \textcos(\theta_{max})) \]By using conservation of energy, you can rearrange this to solve for \(\theta_{max}\), the maximum angular displacement.In the classroom or for individual study, visualizing this maximum displacement could be aided by using a protractor or a mobile app that measures angles. Students might also experimentally determine angular displacement by releasing a pendulum from different heights and measuring the angle it swings. These hands-on activities solidify the understanding of angular displacement in oscillatory motion.

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Most popular questions from this chapter

A particle executes simple harmonic motion with an amplitude of \(3.00 \mathrm{cm} .\) At what position does its speed equal half its maximum speed?

Damping is negligible for a \(0.150-\mathrm{kg}\) object hanging from a light \(6.30-\mathrm{N} / \mathrm{m}\) spring. A sinusoidal force with an amplitude of \(1.70 \mathrm{N}\) drives the system. At what frequency will the force make the object vibrate with an amplitude of \(0.440 \mathrm{m} ?\)

A small object is attached to the end of a string to form a simple pendulum. The period of its harmonic motion is measured for small angular displacements and three lengths, each time clocking the motion with a stopwatch for 50 oscillations. For lengths of \(1.000 \mathrm{m}, 0.750 \mathrm{m}\) and \(0.500 \mathrm{m},\) total times of \(99.8 \mathrm{s}, 86.6 \mathrm{s},\) and \(71.1 \mathrm{s}\) are measured for 50 oscillations. (a) Determine the period of motion for each length. (b) Determine the mean value of \(g\) obtained from these three independent measurements, and compare it with the accepted value. (c) Plot \(T^{2}\) versus \(L,\) and obtain a value for \(g\) from the slope of your best-fit straight-line graph. Compare this value with that obtained in part (b).

A particle moving along the \(x\) axis in simple harmonic motion starts from its equilibrium position, the origin, at \(t=0\) and moves to the right. The amplitude of its motion is \(2.00 \mathrm{cm},\) and the frequency is \(1.50 \mathrm{Hz}\). (a) Show that the position of the particle is given by $$x=(2.00 \mathrm{cm}) \sin (3.00 \pi t)$$.Determine (b) the maximum speed and the earliest time \((t>0)\) at which the particle has this speed, (c) the maximum acceleration and the earliest time \((t>0)\) at which the particle has this acceleration, and (d) the total distance traveled between \(t=0\) and \(t=1.00 \mathrm{s}\).

A 50.0 -g object connected to a spring with a force constant of \(35.0 \mathrm{N} / \mathrm{m}\) oscillates on a horizontal, frictionless surface with an amplitude of \(4.00 \mathrm{cm} .\) Find (a) the total energy of the system and (b) the speed of the object when the position is \(1.00 \mathrm{cm} .\) Find \((\mathrm{c})\) the kinetic energy and \((\mathrm{d})\) the potential energy when the position is \(3.00 \mathrm{cm} .\)

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