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A piston in a gasoline engine is in simple harmonic motion. If the extremes of its position relative to its center point are \(\pm 5.00 \mathrm{cm},\) find the maximum velocity and acceleration of the piston when the engine is running at the rate of 3600 rev/min.

Short Answer

Expert verified
The maximum velocity of the piston is approximately \(18.85 \, \mathrm{m/s}\) and the maximum acceleration is approximately \(227,022 \, \mathrm{m/s^2}\).

Step by step solution

01

Convert the given quantities to the SI units

First, convert the given quantities into SI units. The amplitude, given in cm, is \(5.00 \, \mathrm{cm} = 0.050 \, \mathrm{m}\). The frequency, given in rev/min, is \(\frac{3600 \, \mathrm{rev}}{\mathrm{min}} = 60 \, \mathrm{Hz}\).
02

Compute for the angular frequency

Angular frequency \(\omega\) in simple harmonic motion is related to the ordinary frequency \(f\) by \(\omega = 2\pi f\). Substituting the given frequency, we get \(\omega = 2\pi \times 60 = 120 \pi \, \mathrm{rad/s}\).
03

Find the maximum velocity

In simple harmonic motion, the maximum velocity \(v_{\mathrm{max}}\) is given by \(v_{\mathrm{max}} = A\omega\). Substituting the given amplitude and computed angular frequency, we get \(v_{\mathrm{max}} = (0.050 \, \mathrm{m})(120 \pi \, \mathrm{rad/s}) = 6 \pi \, \mathrm{m/s}\).
04

Find the maximum acceleration

In simple harmonic motion, the maximum acceleration \(a_{\mathrm{max}}\) is given by \(a_{\mathrm{max}} = A\omega^2\). Substituting the given amplitude and computed angular frequency, we get \(a_{\mathrm{max}} = (0.050 \, \mathrm{m})(120 \pi \, \mathrm{rad/s})^2 = 7200 \pi^2 \, \mathrm{m/s^2}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Frequency
Angular frequency is a crucial concept in the study of Simple Harmonic Motion (SHM). It describes how quickly an object oscillates in a circular path and is symbolized by the Greek letter \( \omega \). This value is derived from the frequency \( f \) and is calculated using the formula: \( \omega = 2\pi f \).
In our automotive example, the piston completes many cycles per minute, with a frequency of 60 Hz, translating to a significantly high angular frequency of \( 120\pi \; \mathrm{rad/s} \).
Angular frequency is key because it correlates the linear motion back to a rotating reference. It shows us that despite the linear appearance of a piston's motion, it has a deeper, oscillatory nature. This oscillatory motion is governed by sine and cosine functions, which naturally incorporate \( \omega \). These functions dictate the timing and speed of the piston’s movement, crucial in ensuring optimal engine performance.
Understanding angular frequency helps engineers design efficient engines by predicting how quickly pistons need to move for a particular engine speed, thereby optimizing fuel consumption and reducing wear and tear.
Maximum Velocity
Maximum velocity in Simple Harmonic Motion is a point of great interest as it signifies the fastest speed the oscillating object reaches during its cycle. The formula to determine maximum velocity \( v_{\text{max}} \) is: \( v_{\text{max}} = A\omega \), where \( A \) is the amplitude, or maximum displacement from the center point, and \( \omega \) is the angular frequency.
For our engine piston, with an amplitude of 0.050 meters and angular frequency of \( 120\pi \; \mathrm{rad/s} \), the equation yields a maximum velocity of \( 6\pi \; \mathrm{m/s} \). This means as the piston moves back and forth within the engine, it reaches its peak speed at this value.
The maximum velocity is crucial in determining how quickly the piston can respond to the demands of the engine. A higher maximum velocity implies a quicker response time, which may contribute to improved performance and efficiency. By understanding this, engineers can design vehicles with a balance between speed and fuel efficiency.
Maximum Acceleration
Maximum acceleration is another pivotal component in the study of Simple Harmonic Motion. It indicates the fastest rate at which the speed of an oscillating object changes, highlighting the intense forces the system endures. The formula for maximum acceleration \( a_{\text{max}} \) is: \( a_{\text{max}} = A\omega^2 \), relying on the amplitude \( A \) and the square of angular frequency \( \omega \).
In the case of the engine’s piston, with an amplitude of 0.050 meters and an angular frequency of \( 120\pi \; \mathrm{rad/s} \), the maximum acceleration is found to be \( 7200\pi^2 \; \mathrm{m/s^2} \). This large number reflects the rapid changes in velocity and the significant forces applied to the piston over a very short period.
Maximum acceleration helps in understanding the load capacity of mechanical components. Knowledge of this concept allows engineers to ensure that the material can withstand operational stresses, and to make informed decisions that improve the longevity and reliability of engine parts, contributing to overall vehicle durability.

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Most popular questions from this chapter

A 200 -g block is attached to a horizontal spring and executes simple harmonic motion with a period of 0.250 s. If the total energy of the system is \(2.00 \mathrm{J},\) find (a) the force constant of the spring and (b) the amplitude of the motion.

One end of a light spring with force constant \(100 \mathrm{N} / \mathrm{m}\) is attached to a vertical wall. A light string is tied to the other end of the horizontal spring. The string changes from horizontal to vertical as it passes over a solid pulley of diameter \(4.00 \mathrm{cm} .\) The pulley is free to turn on a fixed smooth axle. The vertical section of the string supports a \(200-\mathrm{g}\) object. The string does not slip at its contact with the pulley. Find the frequency of oscillation of the object if the mass of the pulley is (a) negligible, (b) \(250 \mathrm{g}\), and (c) \(750 \mathrm{g}\)

The mass of the deuterium molecule \(\left(\mathrm{D}_{2}\right)\) is twice that of the hydrogen molecule \(\left(\mathrm{H}_{2}\right) .\) If the vibrational frequency of \(\mathrm{H}_{2}\) is \(1.30 \times 10^{14} \mathrm{Hz},\) what is the vibrational frequency of \(\mathrm{D}_{2} ?\) Assume that the "spring constant" of attracting forces is the same for the two molecules.

(a) A hanging spring stretches by \(35.0 \mathrm{cm}\) when an object of mass \(450 \mathrm{g}\) is hung on it at rest. In this situation, we define its position as \(x=0 .\) The object is pulled down an additional \(18.0 \mathrm{cm}\) and released from rest to oscillate without friction. What is its position \(x\) at a time 84.4 s later? (b) What If? A hanging spring stretches by \(35.5 \mathrm{cm}\) when an object of mass \(440 \mathrm{g}\) is hung on it at rest. We define this new position as \(x=0 .\) This object is also pulled down an additional \(18.0 \mathrm{cm}\) and released from rest to oscillate without friction. Find its position 84.4 s later. (c) Why are the answers to (a) and (b) different by such a large percentage when the data are so similar? Does this circumstance reveal a fundamental difficulty in calculating the future? (d) Find the distance traveled by the vibrating object in part (a). (e) Find the distance traveled by the object in part (b).

In an engine, a piston oscillates with simple harmonic motion so that its position varies according to the expression $$x=(5.00 \mathrm{cm}) \cos (2 t+\pi / 6)$$. where \(x\) is in centimeters and \(t\) is in seconds. At \(t=0\) find (a) the position of the piston, (b) its velocity, and (c) its acceleration. (d) Find the period and amplitude of the motion.

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