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The true weight of an object can be measured in a vacuum, where buoyant forces are absent. An object of volume \(V\) is weighed in air on a balance with the use of weights of density \(\rho .\) If the density of air is \(\rho_{\text {air }}\) and the balance reads \(F_{g}^{\prime},\) show that the true weight \(F_{g}\) is $$F_{R}=F_{R}^{\prime}+\left(V-\frac{F_{R}^{\prime}}{\rho g}\right) \rho_{\operatorname{ain}} g$$

Short Answer

Expert verified
The true weight \( F_g \) of an object measured in a vacuum is given by the formula \( F_g = F_g' + \rho_{air} \cdot V \cdot g \), where \( F_g' \) is the reading of the balance in air, \( \rho_{air} \) is the density of air, \( V \) is the volume of the object, and \( g \) is the gravitational acceleration.

Step by step solution

01

Understanding the formula for buoyant force

Recall that the buoyant force (\( B \)) on an object submerged in a fluid is given by \( B = \rho_{fluid} \cdot V \cdot g \), where \( \rho_{fluid} \) is the density of the fluid, \( V \) is the volume of the object, and \( g \) is the acceleration due to gravity.
02

Finding the apparent weight

The weight of an object in a fluid (or apparent weight) is the true weight (\( F_g \)) minus the buoyant force (\( B \)). Therefore, we could write it as \( F_g' = F_g - B \). Substituting the buoyant force expression from Step 1, we get \( F_g' = F_g - \rho_{air} \cdot V \cdot g \). Let's express \( F_g \) as the density of the object (\( \rho \)) times the volume (\( V \)) times gravity (\( g \)). Hence, the equation becomes \( F_g' = \rho \cdot V \cdot g - \rho_{air} \cdot V \cdot g \).
03

Solving for the true weight \( F_g \)

Rearranging the equation from Step 2 for \( F_g \), we get \( F_g = F_g' + \rho_{air} \cdot V \cdot g \). This is the relationship asked for in the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Apparent Weight in Fluid
When an object is submerged in a fluid, it experiences an upward force known as buoyant force, which makes the object feel lighter. The weight of the object that we measure when it's in a fluid is called the apparent weight. The apparent weight can be quite deceptive because it's influenced by the buoyancy effect, which reduces the overall force acting on the object due to gravity. This is why, for example, when you try to lift a heavy stone in water, it feels lighter than it does in air.

To calculate the apparent weight, you subtract the buoyant force from the true weight of the object. In a formula:
\[ F_g' = F_g - (\rho_{fluid} \times V \times g) \]
where \( F_g' \) is the apparent weight, \( F_g \) is the true weight, \( \rho_{fluid} \) is the density of the fluid, \( V \) is the volume of the object, and \( g \) is the acceleration due to gravity. Remember, the apparent weight is always less than the true weight unless the fluid's density is negligible, like in a vacuum or air if its effect is minimal.
True Weight Measurement
True weight refers to the actual force due to gravity acting on an object. It can be measured most accurately in a vacuum where there are no buoyant forces to consider. However, such conditions are not always practical, hence we commonly measure weight in air. The true weight of an object can be represented by:
\[ F_g = \rho \times V \times g \]
where \( \rho \) is the density of the object, \( V \) is the volume, and \( g \) is the acceleration due to gravity. When we measure the weight of an object in air, we typically record a value that has to be corrected for the buoyant force exerted by the air, consequently leading to an apparent weight. Calculating the true weight from an apparent weight measurement requires adding the buoyant force back to the apparent weight as demonstrated in the textbook exercise:
Density and Buoyancy
The principle of buoyancy reveals a fascinating relationship between an object's density and the fluid in which it is immersed. The buoyant force on an object in a fluid is calculated by the product of the fluid's density, the volume of the object, and the acceleration due to gravity. This relationship is mathematically represented by Archimedes' principle as:
\[ B = \rho_{fluid} \times V \times g \]
The density of a fluid is a crucial factor in determining the buoyant force. A fluid with higher density exerts a more substantial buoyant force, causing objects to appear more 'buoyant' or 'floaty' in it. Conversely, objects tend to sink in fluids of lower densities if their density is high enough.

It's the reason why ships, for instance, can float on the sea but would sink if they were in a body of a less dense fluid. When the density of an object is less than the density of the fluid, it will float; if the two densities are equal, it will remain suspended; if the object's density is more, it will sink. Understanding how density impacts buoyancy is crucial not just in academic problems but also in various real-world applications, including marine engineering and fluid mechanics.

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Most popular questions from this chapter

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