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If \(|\mathbf{A} \times \mathbf{B}|=\mathbf{A} \cdot \mathbf{B},\) what is the angle between \(\mathbf{A}\) and \(\mathbf{B}\) ?

Short Answer

Expert verified
The angle between vectors \(\mathbf{A}\) and \(\mathbf{B}\) is \(\frac{\pi}{4}\).

Step by step solution

01

Use given equality

Given \(|\mathbf{A} \times \mathbf{B}| = \mathbf{A} \cdot \mathbf{B}\), we can replace the magnitude of the cross product and the dot product with their respective formulas: |\mathbf{A}||\mathbf{B}|\sin{\theta} = |\mathbf{A}||\mathbf{B}|\cos{\theta}.
02

Simplify the equality

Simplify the equality by dividing both sides by the magnitude of |\mathbf{A}||\mathbf{B}|, giving us the equation \sin{\theta} = \cos{\theta}.
03

Solve for \(\theta\)

Here we are looking for the angle \(\theta\) that satisfies the equation \sin{\theta} = \cos{\theta}. This is true whenever \sin{\theta} and \cos{\theta} are equal. Therefore, when we solve this equation, it will be seen that \(\theta\) equals \(\frac{\pi}{4}\) + n\pi, where n is an integer, to ensure the angle is within a range of 0 to 2\pi. Because we are seeking the range of values that \(\theta\) can be, rather than a specific value. However, the only angle within the range (0,2\pi) is \(\frac{\pi}{4}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cross Product
The cross product, also known as the vector product, is a binary operation on two vectors in three-dimensional space. If you have vectors \( \mathbf{A} \) and \( \mathbf{B} \), their cross product is a vector perpendicular to both \( \mathbf{A} \) and \( \mathbf{B} \), and is denoted as \( \mathbf{A} \times \mathbf{B} \). This product is specifically defined in three dimensions and results in another vector, not a scalar.

The magnitude of the cross product is given by the formula:
  • \( |\mathbf{A} \times \mathbf{B}| = |\mathbf{A}||\mathbf{B}|\sin{\theta} \)
Here, \( \theta \) is the angle between the two vectors. The sine function is used here because it represents the magnitude of the component of one vector in the perpendicular direction to the other.

Understanding this helps you see how the cross product captures the idea of the perpendicularity between two vectors, and why it results in a new vector that is orthogonal to the originals.
Dot Product
The dot product, or scalar product, is another operation you can perform on two vectors. Unlike the cross product, the dot product yields a scalar, not a vector. For vectors \( \mathbf{A} \) and \( \mathbf{B} \), the dot product is denoted as \( \mathbf{A} \cdot \mathbf{B} \) and defined as:
  • \( \mathbf{A} \cdot \mathbf{B} = |\mathbf{A}||\mathbf{B}|\cos{\theta} \)
This formulation involves the cosine of the angle between the vectors because it measures how much one vector extends in the direction of another.

The dot product is particularly useful in determining how parallel two vectors are. If \( \mathbf{A} \cdot \mathbf{B} \) equals zero, it implies that the vectors are orthogonal. Conversely, if the vectors are aligned parallel in the same or opposite directions, the dot product reaches its maximum absolute value.
Angle Between Vectors
The angle \( \theta \) between two vectors can give you profound insight into their spatial relationship. It's crucial to understand this angle when dealing with both the dot and cross products. In many exercises, as seen in the original exercise, finding this angle is key to solving vector-related problems.

The relationship between the dot product and cross product provides a way to determine this angle. From the formulae:
  • \( \sin{\theta} = \cos{\theta} \)
  • This simplifies to \( \theta = \frac{\pi}{4} + n\pi \)
where \( n \) is an integer, representing periodic angles due to the cyclic nature of trigonometric functions.

This angle is particularly important because it defines whether two vectors are perpendicular (\( \theta = \frac{\pi}{2} \)), parallel (\( \theta = 0 \) or \( \pi \)), or neither. In our given problem, the angle that matches the condition for both the dot and cross product magnitude being equal is \( \frac{\pi}{4} \).

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