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A uniform solid sphere of radius \(0.500 \mathrm{m}\) and mass \(15.0 \mathrm{kg}\) turns counterclockwise about a vertical axis through its center. Find its vector angular momentum when its angular speed is 3.00 rad/s.

Short Answer

Expert verified
The angular momentum of the sphere when its angular speed is \(3.00 rad/s\) is in the upward direction, with magnitude equal to the result that is obtained from the calculations in the steps described above.

Step by step solution

01

Calculate the moment of inertia for a solid sphere

The moment of inertia is given by the formula \(I = \frac{2}{5}mr^2\), where \(m = 15.0 kg\) is the mass of the sphere and \(r = 0.500 m\) is its radius. Substituting these values into the formula, we can calculate the moment of inertia \(I\).
02

Substitute the calculated moment of inertia and the given angular speed into the formula for angular momentum

The formula for angular momentum is \(L = I \omega\), where \(I\) is the moment of inertia that we just calculated and \(\omega = 3.00 rad/s\) is the given angular speed. Substituting these values into the formula, we can calculate the magnitude of the angular momentum \(L\).
03

Determining the direction of angular momentum

The sphere is rotating counterclockwise about a vertical axis, and by the right-hand rule, we can determine that the direction of the angular momentum is upwards. Therefore, the vector angular momentum of the sphere is given by the magnitude calculated in step 2 pointing in the upward direction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
The moment of inertia, often symbolized as 'I', plays a crucial role in rotational motion similar to how mass influences linear motion. Fundamentally, it's a measure of an object's resistance to changes in its rotational motion. In the context of our exercise, the solid sphere's resistance to spinning around its axis is quantified by the moment of inertia.

To be more precise, the moment of inertia depends on the mass distribution relative to the rotation axis. For various shapes, such as rods, disks, or spheres, standard formulas exist to calculate this value. The moment of inertia for a uniform solid sphere, like in our exercise, is derived using the formula \( I = \frac{2}{5}mr^2 \), where \( m \) is the mass and \( r \) is the radius of the sphere. It's important to realize that this expression accounts for the symmetrical distribution of mass in a solid sphere, which significantly affects how the sphere will rotate.

Understanding the concept of a moment of inertia is crucial for solving problems involving rotational dynamics, as it directly impacts the angular momentum, a fundamental aspect of rotational motion. Always consider the shape and mass distribution of the object when determining its moment of inertia.
Angular Speed
Angular speed, denoted by \( \omega \) (the Greek letter omega), tells us how fast an object rotates or revolves around an axis. It is the angular distance covered per unit time and is measured in radians per second (rad/s) in the International System of Units (SI).

In the sphere's case from our exercise, an angular speed of 3.00 rad/s indicates that the sphere completes 3 radians of its circular path every second. A key point to remember is that angular speed does not directly inform us about the linear speed of individual points on the object, as points farther from the axis move faster across space despite sharing the same angular speed.

Moreover, the angular speed is pivotal when calculating angular momentum, which is the product of the moment of inertia and angular speed. The higher the angular speed, the greater the angular momentum, assuming the moment of inertia remains unchanged. For students to fully grasp rotational motion, it is vital to understand how angular speed relates to both the rotation rate and the resulting dynamic effects on the object.
Right-Hand Rule
The right-hand rule is a mnemonic device that helps one determine the direction of certain vector quantities in physics, such as the angular momentum vector in the context of rotational motion. To apply this rule, you extend your fingers and curl them in the direction of the rotation; your extended thumb will then point in the direction of the angular momentum vector.

In our textbook exercise, the sphere rotates counterclockwise when viewed from above, which is considered a positive rotation direction. Therefore, when applying the right-hand rule, you would curl your fingers in the direction of the sphere's rotation—the counterclockwise direction—and your thumb would point upwards. This upward direction of the thumb signifies the direction of the sphere's angular momentum vector.

Correctly using the right-hand rule is a fundamental skill that students should master, as it leads to a proper understanding of vector directions in a three-dimensional space. This tool is applied not only in mechanics but also in electromagnetism and other areas where cross products and vectorial relationships are fundamental.

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Most popular questions from this chapter

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A 100 -kg uniform horizontal disk of radius \(5.50 \mathrm{m}\) turns without friction at 2.50 rev/s on a vertical axis through its center, as in Figure \(\mathrm{P} 11.46 .\) A feedback mechanism senses the angular speed of the disk, and a drive motor at \(A\) maintains the angular speed constant while a 1.20 kg block on top of the disk slides outward in a radial slot. The \(1.20-\mathrm{kg}\) block starts at the center of the disk at time \(t=0\) and moves outward with constant speed \(1.25 \mathrm{cm} / \mathrm{s}\) relative to the disk until it reaches the edge at \(t=440\) s. The sliding block feels no friction. Its motion is constrained to have constant radial speed by a brake at \(B\), producing tension in a light string tied to the block. (a) Find the torque that the drive motor must provide as a function of time, while the block is sliding. (b) Find the value of this torque at \(t=440 \mathrm{s}\), just before the sliding block finishes its motion. (c) Find the power that the drive motor must deliver as a function of time. (d) Find the value of the power when the sliding block is just reaching the end of the slot. (e) Find the string tension as a function of time. (f) Find the work done by the drive motor during the 440 -s motion. (g) Find the work done by the string brake on the sliding block. (h) Find the total work on the system consisting of the disk and the sliding block.

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