/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 (a) Find the angular speed of th... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) Find the angular speed of the Earth's rotation on its axis. As the Earth turns toward the east, we see the sky turning toward the west at this same rate. (b) The rainy Pleiads wester And seek beyond the sea The head that I shall dream of That shall not dream of me. Cambridge, England, is at longitude \(0^{\circ},\) and Saskatoon, Saskatchewan, is at longitude \(107^{\circ}\) west. How much time elapses after the Pleiades set in Cambridge until these stars fall below the western horizon in Saskatoon?

Short Answer

Expert verified
Angular speed of the Earth's rotation is \( \frac{Ï€}{12} \) rad/hr. The time elapsed between the Pleiades setting in Cambridge and Saskatoon is approximately 7 hours and 8 minutes.

Step by step solution

01

Calculate the angular speed of the Earth's rotation

The Earth makes a complete rotation on its axis in approximately 24 hours, that is in one day. Therefore the angular speed (ω) of the Earth's rotation can be calculated using the formula \[ ω = \frac{Δθ}{t} \] where \( Δθ \) is the change in angle and \( t\) is the time. Since the Earth completes a 360 degrees (or \(2π\) radians) rotation in one day of time, we substitute these values into the formula: \[ ω = \frac{2π}{24} \] This will yield the angular speed in rad/hr.
02

Calculate the time difference between two locations

We know that the Earth rotates 360 degrees in approximately 24 hours. Given that Saskatoon and Cambridge have a difference of 107 degrees in longitude, we need to calculate the time for this 107 degrees. Using the ratio, where \( 360° : 24 hr = 107° : x hr\), we can solve for \( x\), the time elapsed for 107 degrees rotation.
03

Convert the time into hours and minutes

Since we are interested in the time elapsed (which is easier to relate to in hours and minutes rather than in decimal hours), the answer from Step 2 should be converted into minutes. Multiply the decimal portion by 60 to get the minute component of the time.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed
The Earth's rotation defines its angular speed, which describes how quickly it spins around its axis. This movement is crucial for determining the transition between day and night. But what exactly is angular speed? Simply put, it is the measure of the angle through which the Earth turns in a given time.
For Earth, a complete rotation takes about 24 hours. To find the angular speed (\(\omega\)), we use the formula:\[\omega = \frac{\Delta\theta}{t}\]where \(\Delta\theta\) is the angle in radians and \(t\) is the time in hours.
Since a full rotation is 360 degrees or \(2\pi\) radians, we can plug these values into the formula:\[\omega = \frac{2\pi}{24}\]This calculation gives us the angular speed in radians per hour (rad/hr). This speed ensures the Earth completes its daily rotation, a fundamental aspect of our time system.
Longitude Difference
Understanding longitude is vital for timekeeping and navigation. Longitudes are imaginary lines running from the North Pole to the South Pole, which help define time zones. The difference in longitude between two places can have significant effects, especially in how we experience time.
For instance, let’s consider Cambridge, England, at \(0^{\circ}\) longitude and Saskatoon, Canada, at \(107^{\circ}\) west longitude. The longitudinal difference between these two cities is 107 degrees. This difference is crucial in calculating the time difference due to Earth's rotation.
Since the Earth rotates 360 degrees in 24 hours, the time taken for a change in longitude can be worked out by setting up a proportion: 360 degrees corresponds to 24 hours, and 107 degrees corresponds to a certain amount of time (\(x\) hours). Solving this proportion:\[\frac{360}{24} = \frac{107}{x}\]allows us to calculate the time difference between the two locations, which is essential for synchronizing clocks and understanding local times across the globe.
Time Zone Conversion
Time zone conversion is a practical aspect of understanding the Earth's rotation and longitude differences. It allows us to determine the local time at any place on the planet, taking into account the time differences due to Earth's eastward rotation.
When converting time zones, it's helpful to calculate both the hour and minute changes to ensure accuracy. For instance, after determining the time difference arising from a longitude difference, such as between Cambridge and Saskatoon, we need to express this time in an easy-to-understand format.
After you find the total elapsed time in hours from your calculation (for instance, using the proportion from longitude differences), you might get a decimal. To convert this into hours and minutes:
  • Take the whole number part as the hour difference.
  • Multiply the decimal fraction by 60 to get the minutes.
This step ensures that you can easily understand and communicate the time difference, making it easier to manage schedules across different regions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Determine the acceleration of the center of mass of a uniform solid disk rolling down an incline making angle \(\theta\) with the horizontal. Compare this acceleration with that of a uniform hoop. (b) What is the minimum coefficient of friction required to maintain pure rolling motion for the disk?

Attention! About face! Compute an order-of-magnitude estimate for the moment of inertia of your body as you stand tall and turn about a vertical axis through the top of your head and the point halfway between your ankles. In your solution state the quantities you measure or estimate and their values.

During a certain period of time, the angular position of a swinging door is described by \(\theta=5.00+10.0 t+2.00 t^{2}\) where \(\theta\) is in radians and \(t\) is in seconds. Determine the angular position, angular speed, and angular acceleration of the door (a) at \(t=0\) (b) at \(t=3.00 \mathrm{s}\)

The density of the Earth, at any distance \(r\) from its center, is approximately $$ \rho=[14.2-11.6(r / R)] \times 10^{3} \mathrm{kg} / \mathrm{m}^{3} $$ where \(R\) is the radius of the Earth. Show that this density leads to a moment of inertia \(I=0.330 M R^{2}\) about an axis through the center, where \(M\) is the mass of the Earth.

A large, cylindrical roll of tissue paper of initial radius \(R\) lies on a long, horizontal surface with the outside end of the paper nailed to the surface. The roll is given a slight shove \(\left(v_{i} \approx 0\right)\) and commences to unroll. Assume the roll has a uniform density and that mechanical energy is conserved in the process. (a) Determine the speed of the center of mass of the roll when its radius has diminished to \(r\) (b) Calculate a numerical value for this speed at \(r=1.00 \mathrm{mm},\) assuming \(R=6.00 \mathrm{m} .\) (c) What If? What happens to the energy of the system when the paper is completely unrolled?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.