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A shaft is turning at 65.0 rad/s at time \(t=0 .\) Thereafter, its angular acceleration is given by $$ \alpha=-10.0 \mathrm{rad} / \mathrm{s}^{2}-5.00 t \mathrm{rad} / \mathrm{s}^{3} $$ where \(t\) is the elapsed time. (a) Find its angular speed at \(t=3.00 \mathrm{s} .\) (b) How far does it turn in these \(3 \mathrm{s} ?\)

Short Answer

Expert verified
Thus, the final angular speed at \( t = 3\)s turns out to be \( \omega \) (value found in Step 3). The total angular displacement at \( t = 3\)s turns out to be \( \theta \) (value found in Step 6).

Step by step solution

01

Use formula for final angular speed

Using the formula \( \omega = \omega_0 + \int \alpha dt \) from \(0\) to \(3\) seconds, which represents that the final angular speed is equal to the initial angular speed plus the integral of angular acceleration with respect to time, substitute the given values to get: \( \omega = 65.0 + \int_0^3 (-10.0 - 5.00t) dt \).
02

Calculate the integral

Performing the integral: \(-10.0 \cdot t - \frac{5.0}{2} \cdot t^2 \) from 0 to 3, the result will be: \(-10.0 \cdot 3 - \frac{5.0}{2} \cdot 3^2\)
03

Get the final angular speed

After performing the calculations, subtract the obtained value from Step 2 from the initial angular speed to get the angular speed at time \(t = 3\)s.
04

Calculate total angular displacement

Using the formula for the angular displacement \(\theta = \omega_0 t + \frac{1}{2} \int \alpha dt^2 \), substitute the known values and do the integration which represents the initial angular speed times time plus half the integral of acceleration with respect to time squared.
05

Solve the integral

Performing integral calculation: \( -10.0 \cdot \frac{t^2}{2} - \frac{5.0}{3} \cdot t^3 \) from 0 to 3, the resulted value is plugged into the formula from Step 4 to calculate the total angular displacement.
06

Get the total angular displacement

Calculate the total angular displacement by subtracting the integral obtained in Step 5 from the product of initial angular velocity and elapsed time. This is the total angular displacement at time \( t = 3\)s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed
Angular speed is a measure of the rate at which an object rotates or revolves relative to another point, which is typically the center of rotation. Think of it like the speedometer in a car, but instead of telling you how fast you're going in miles per hour, it tells you how fast you're spinning, in radians per second (\rads).

In our given exercise, the initial angular speed (\rads) at time \(t=0\) is 65.0 rad/s. To find the angular speed at a different time, we can't just look at the speedometer; we need to consider how the speed is changing over time, which involves angular acceleration. So we integrate the given angular acceleration \rads^2) over time from 0 to 3 seconds. This step simply adds all the little changes in speed that happen every instant over the 3 seconds. The resulting answer tells us the angular speed at the exact moment of 3 seconds.
Angular Displacement
When an object spins, it covers a certain angle, just like when you travel from one city to another, you cover a certain distance. Angular displacement measures the angle through which an object has rotated about a fixed point in a given time and is represented in radians.

Now, to calculate how much our object has turned, we need the angular displacement equation which combines initial angular speed, time, and angular acceleration. The angular displacement can be found by multiplying the initial angular speed by time, then adding half of the integral of angular acceleration over time squared. It's like calculating the total distance in a road trip with varying speeds; by the end, we find out how far we've gone around the circle.
Time-Dependent Acceleration
Acceleration usually tells how much the speed of an object will increase or decrease in one second. But with time-dependent acceleration, the change in speed isn't constant; it changes as time goes by. Imagine pressing the gas pedal in your car more and more every second – that's time-dependent acceleration for you.

In our exercise, angular acceleration decreases over time, which is shown by the equation \( \alpha=-10.0 \mathrm{rad} / \mathrm{s}^{2}-5.00 t \mathrm{rad} /\mathrm{s}^{3} \). To figure out how this time-dependent acceleration affects angular speed and displacement, we have to perform an integration operation over the specific time interval. This tells us exactly how much the acceleration at each moment contributed to changing the angular speed and how far the object turned, which are parts we need to solve our overall problem.

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Most popular questions from this chapter

The combination of an applied force and a friction force produces a constant total torque of \(36.0 \mathrm{N} \cdot \mathrm{m}\) on a wheel rotating about a fixed axis. The applied force acts for \(6.00 \mathrm{s} .\) During this time the angular speed of the wheel increases from 0 to 10.0 rad/s. The applied force is then removed, and the wheel comes to rest in 60.0 s. Find (a) the moment of inertia of the wheel, (b) the magnitude of the frictional torque, and (c) the total number of revolutions of the wheel.

A disk \(8.00 \mathrm{cm}\) in radius rotates at a constant rate of 1 200 rev/min about its central axis. Determine (a) its angular speed, (b) the tangential speed at a point \(3.00 \mathrm{cm}\) from its center, (c) the radial acceleration of a point on the rim, and (d) the total distance a point on the rim moves in \(2.00 \mathrm{s}\)

An electric motor rotating a grinding wheel at \(100 \mathrm{rev} / \mathrm{min}\) is switched off. With constant negative angular acceleration of magnitude \(2.00 \mathrm{rad} / \mathrm{s}^{2},\) (a) how long does it take the wheel to stop? (b) Through how many radians does it turn while it is slowing down?

An airliner arrives at the terminal, and the engines are shut off. The rotor of one of the engines has an initial clockwise angular speed of 2000 rad/s. The engine's rotation slows with an angular acceleration of magnitude \(80.0 \mathrm{rad} / \mathrm{s}^{2} .\) (a) Determine the angular speed after \(10.0 \mathrm{s}\) (b) How long does it take the rotor to come to rest?

(a) Determine the acceleration of the center of mass of a uniform solid disk rolling down an incline making angle \(\theta\) with the horizontal. Compare this acceleration with that of a uniform hoop. (b) What is the minimum coefficient of friction required to maintain pure rolling motion for the disk?

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