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The radius of a circle is measured to be \((10.5 \pm 0.2) \mathrm{m}\) Calculate the (a) area and (b) circumference of the circle and give the uncertainty in each value.

Short Answer

Expert verified
The area is \( \pi (10.5^{2}) m^{2} \) with an uncertainty of \( | 2 \pi (10.5) (0.2) | m^{2} \). The circumference is \( 2 \pi (10.5) m \) with an uncertainty of \( | 2 \pi (0.2) | m \).

Step by step solution

01

Calculate the Area

First, calculate the area of the circle using the formula \(A = \pi r^{2}\). Here, \(r = 10.5 m\). So the area \(A = \pi (10.5^{2}) m^{2}\)
02

Calculate the Uncertainty in the Area

The uncertainty in the area \( \Delta A\) is determined using the propagation of errors formula. For quantities which are raised to a power, such as here where the radius is squared, this formula is: \( \Delta A = | 2 \pi r ∆ r | \). Here, \( ∆ r = 0.2 m\). So the uncertainty \( ∆ A = | 2 \pi (10.5) (0.2) | m^{2} \)
03

Calculate the Circumference

Next, calculate the circumference of the circle using the formula \(C = 2 \pi r\). So the circumference \(C = 2 \pi (10.5) m \)
04

Calculate the Uncertainty in the Circumference

The uncertainty in the circumference \( \Delta C\) is determined using the propagation of errors formula. For quantities which are multiplied or divided, this formula is: \( \Delta C = | 2 \pi ∆ r | \). So the uncertainty \( ∆ C = | 2 \pi (0.2) | m \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Uncertainty in Measurements
When we measure something, we seldom get the exact value. There’s almost always some uncertainty or error attached. This error can arise due to the limitations of the measuring instrument or the technique used. Understand that the term error in this context doesn't mean a mistake, but an inherent variation that comes with any form of measurement. Think of it as a way to indicate how accurate and precise your measurement is.

For instance, if you have a ruler graded only to the nearest millimeter, your measurement might not reflect the fraction of a millimeter that actually could be present. Thus, you'll report this as, say, \(15.3 \pm 0.1\text{ mm}\), where \(\pm 0.1\text{ mm}\) represents the uncertainty.

In more mathematical terms, if a physical quantity, like the radius of a circle, is measured as \(10.5 \pm 0.2\text{m}\), this means the true value of the radius lies somewhere between 10.3 m and 10.7 m. When we use this measured value to calculate other quantities, like the area or circumference in mathematical problems, the propagation of errors formula helps to estimate the resultant uncertainty in those derived values.
Area of a Circle
The area of a circle is the amount of space enclosed by its circumference and is given by the formula \( A = \pi r^2 \), where \(r\) is the radius of the circle and \(\pi\) is a constant approximately equal to 3.14159. If you have a circle with a radius of 10.5 m, the area would be \( \pi \times 10.5^2 \approx 346.36 \text{ m}^2\).

But what happens when the radius comes with an uncertainty? This is where the calculation gets more interesting. You have to consider that the smallest area, without the uncertainty, would result from the smallest possible radius, and the largest one would result from the largest possible radius.

The practical application of this concept allows for better planning and material estimation in fields like construction and manufacturing, where shapes often need to be within specific size tolerances.
Circumference of a Circle
The circumference of a circle is the distance around it, commonly measured in units such as meters or centimeters. To calculate it, you use the formula \( C = 2\pi r \), with \(r\) being the radius. So, for our circle with radius 10.5 m, the circumference will be \( 2\pi \times 10.5 \approx 65.97 \text{m}\).

Again, considering the uncertainty in the radius is crucial if you require precision for tasks such as cutting lengths of material for construction or crafts. It ensures you have enough material and helps prevent waste due to the shortfall. The calculated uncertainty in the circumference allows one to understand the possible variance in the dimension, aiding in making decisions that can accommodate the range of possible real-world outcomes.

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Most popular questions from this chapter

(a) A fundamental law of motion states that the acceleration of an object is directly proportional to the resultant force exerted on the object and inversely proportional to its mass. If the proportionality constant is defined to have no dimensions, determine the dimensions of force. (b) The newton is the SI unit of force. According to the results for (a), how can you express a force having units of newtons using the fundamental units of mass, length, and time?

(a) Find a conversion factor to convert from miles per hour to kilometers per hour. (b) In the past, a federal law mandated that highway speed limits would be \(55 \mathrm{mi} / \mathrm{h}\). Use the conversion factor of part (a) to find this speed in kilometers per hour. (c) The maximum highway speed is now \(65 \mathrm{mi} / \mathrm{h}\) in some places. In kilometers per hour, how much increase is this over the 55 mi/ hit?

A farmer measures the distance around a rectangular field. The length of the long sides of the rectangle is found to be \(38.44 \mathrm{m},\) and the length of the short sides is found to be \(19.5 \mathrm{m} .\) What is the total distance around the field?

In a situation where data are known to three significant digits, we write \(6.379 \mathrm{m}=6.38 \mathrm{m}\) and \(6.374 \mathrm{m}=6.37 \mathrm{m}\) When a number ends in \(5,\) we arbitrarily choose to write \(6.375 \mathrm{m}=6.38 \mathrm{m} .\) We could equally well write \(6.375 \mathrm{m}=\) \(6.37 \mathrm{m},\) "rounding down" instead of "rounding up," because we would change the number 6.375 by equal increments in both cases. Now consider an order-of-magnitude estimate, in which we consider factors rather than increments. We write \(500 \mathrm{m} \sim 10^{3} \mathrm{m}\) because 500 differs from 100 by a factor of 5 while it differs from 1000 by only a factor of \(2 .\) We write \(437 \mathrm{m} \sim 10^{3} \mathrm{m}\) and \(305 \mathrm{m} \sim 10^{2} \mathrm{m}\) What distance differs from \(100 \mathrm{m}\) and from \(1000 \mathrm{m}\) by equal factors, so that we could equally well choose to represent its order of magnitude either as \(\sim 10^{2} \mathrm{m}\) or as \(\sim 10^{3} \mathrm{m} ?\)

\- Two spheres are cut from a certain uniform rock. One has radius \(4.50 \mathrm{cm} .\) The mass of the other is five times greater. Find its radius.

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