/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 \(A 30\) g dart is shot straight... [FREE SOLUTION] | 91Ó°ÊÓ

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\(A 30\) g dart is shot straight up at \(9.0 \mathrm{m} / \mathrm{s}\). At the same instant, a 20 g ball of cork is dropped from 3.0 \(\mathrm{m}\) above the dart. What are the speed and direction of the cork ball immediately after it is hit by the dart? Assume the collision is exactly head-on and the dart sticks in the cork.

Short Answer

Expert verified
The speed of the cork ball immediately after it is hit by the dart is the value obtained for \( v_{final} \) and the direction is upwards.

Step by step solution

01

Identify the Initial Momentums

First, calculate the initial momentum of both the dart and the cork ball. The equation for momentum is \( p = mv \), where \( m \) is the mass and \( v \) is the velocity. The initial momentum of the dart is \( p_{d_i} = m_{d}v_{d_i}\) and the initial momentum of the cork ball is \( p_{c_i} = m_{c}v_{c_i} \). Given \( m_{d} = 30g = 0.03kg \), \( v_{d_i} = 9.0 m/s \), \( m_{c} = 20g = 0.02kg \), and \( v_{c_i} = 0 \) (since it falls from rest), we can substitute these given values into the momentum equation.
02

Calculate Total Initial Momentum

The total initial momentum is \( p_{initial} = p_{d_i} + p_{c_i} \). Sum up the values calculated in the first step to get the total initial momentum.
03

Use Conservation of Momentum

According to the principle of conservation of momentum, the total initial momentum before the collision equals the total final momentum after the collision. That is, \( p_{initial} = p_{final} \), and the final momentum of the two bodies, which stick together after collision becomes \( p_{final} = (m_{d} + m_{c})v_{final} \), where \( v_{final} \) is the final common velocity of the dart and the cork ball after collision.
04

Calculate Final Velocity

Solve for the final velocity \( v_{final} \) using the equation from Step 3. Substitute the values for \( m_{d}, m_{c}, \) and the initial total momentum calculated in Step 2.
05

Find Cork Ball's Speed and Direction

The speed of the cork ball immediately after the collision is equal to the magnitude of the final velocity \( v_{final} \), obtained from Step 4. The direction will be upwards as there is no horizontal motion.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Momentum
In physics, the concept of linear momentum, often simply called momentum, is an important and fundamental vector quantity that represents the product of an object's mass and its velocity. Expressed mathematically, the momentum (\(p\)) of an object is calculated using the formula: \( p = mv \), where \( m \) is the mass of the object, and \( v \) is its velocity.

Essentially, momentum helps us understand how difficult it would be to stop a moving object. The greater the mass or velocity of an object, the more momentum it has. A truck moving at a certain speed, for instance, has more momentum than a car traveling at the same speed due to its greater mass. Momentum is a conserved quantity—meaning it remains constant—unless acted upon by an external force, a concept we will explore more in the next section.
Conservation of Momentum
The conservation of momentum is a fundamental law in physics stating that, in a closed system with no external forces, the total momentum remains constant. This principle is at the heart of collision problems, where despite the complexity of the interactions, the overall momentum before and after the event doesn't change.

For example, if two ice skaters push off from one another, the total momentum before and after this interaction remains the same. If one skater has more mass, they will move more slowly than the lighter skater, but the momentum of the two combined will be equal before and after they push away from each other. This principle enables us to solve for unknown properties of moving systems, such as the velocity after a collision, just as it was demonstrated in the textbook solution for the dart and cork ball problem.
Inelastic Collision
An inelastic collision is a type of collision in which the colliding bodies stick together after impact, resulting in a loss of kinetic energy. Despite this loss, the law of conservation of momentum still applies, and the total momentum before and after the collision is the same.

Because the two objects move together with common velocity after the collision, calculating the final outcome such as speed and direction is possible using momentum conservation. This particular type of collision, where the objects stick together, like the dart embedding itself in the cork ball from our exercise, is also known as a perfectly inelastic collision. It's the most extreme example of inelastic collisions, as it results in a maximum loss of kinetic energy while still conserving momentum.
Physics Problem Solving
Effective physics problem solving involves a systematic approach to handle complex problems by breaking them down into smaller, more manageable parts. The solution to the dart and cork ball collision problem is an excellent example of this approach. Students first identify the relevant quantities, such as mass and velocity, to calculate initial momentum. Next, by applying the conservation principles, they set up equations that link the initial state to the final state of the system.

Once these equations are set up, mathematical tools and reasoning are used to rearrange them and solve for the unknown variables. Clear, logical steps taken one at a time lead to the answer of the problem without confusion. This step-by-step methodology is not only applicable to momentum problems but is a powerful strategy for tackling various topics across physics and other scientific disciplines.

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Most popular questions from this chapter

A small rocket to gather weather data is launched straight up. Several seconds into the flight, its velocity is \(120 \mathrm{m} / \mathrm{s}\) and it is accelerating at \(18 \mathrm{m} / \mathrm{s}^{2}\). At this instant, the rocket's mass is \(48 \mathrm{kg}\) and it is losing mass at the rate of \(0.50 \mathrm{kg} / \mathrm{s}\) as it burns fuel. What is the net force on the rocket? Hint: Newton's second law was presented in a new form in this chapter.

A 50kg archer, standing on frictionless ice, shoots a \(100 \mathrm{g}\) arrow at a speed of \(100 \mathrm{m} / \mathrm{s}\). What is the recoil speed of the archer?

The nucleus of the polonium isotope \(^{214} \mathrm{Po}\) (mass 214 u) is radioactive and decays by emitting an alpha particle (a helium nucleus with mass 4 u). Laboratory experiments measure the speed of the alpha particle to be \(1.92 \times 10^{7} \mathrm{m} / \mathrm{s}\). Assuming the polonium nucleus was initially at rest, what is the recoil speed of the nucleus that remains after the decay?

\(A\). 50 g ball is launched from ground level at an angle \(30^{\circ}\) above the horizon. Its initial speed is \(25 \mathrm{m} / \mathrm{s}\) a. What are the values of \(p_{x}\) and \(p_{y}\) an instant after the ball is launched, at the point of maximum altitude, and an instant before the ball hits the ground? b. Why is one component of \(\vec{p}\) constant? Explain. c. For the component of \(\vec{p}\) that changes, show that the change in momentum is equal to the gravitational force on the ball multiplied by the time of flight. Explain why this is so.

An object at rest on a flat, horizontal surface explodes into two fragments, one seven times as massive as the other. The heavier fragment slides 8.2 m before stopping. How far does the lighter fragment slide? Assume that both fragments have the same coefficient of kinetic friction.

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