/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 You are given the dynamics equat... [FREE SOLUTION] | 91Ó°ÊÓ

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You are given the dynamics equations that are used to solve a problem. For each of these, you are to a. Write a realistic problem for which these are the correct equations. b. Draw the free-body diagram and the pictorial representation for your problem. c. Finish the solution of the problem. $$\begin{aligned}&(100 \mathrm{N}) \cos 30^{\circ}-f_{\mathrm{k}}=(20 \mathrm{kg}) a_{\mathrm{x}}\\\&n+(100 N) \sin 30^{\circ}-(20 k g)\left(9.80 m / s^{2}\right)=0\\\&f_{k}=0.20 n\end{aligned}$$

Short Answer

Expert verified
The constructed problem is a 20kg box sliding down an inclined plane with a 100N force acting at an inclined angle. The normal force and frictional force are 176N and 35.2N respectively. The acceleration of the box is \(1.85 m/s^2\).

Step by step solution

01

Construct a Realistic Problem

Consider a 20kg box sliding down a plane inclined at 30 degrees to the horizontal. A force of 100N is acting downward on the box at the angle of incline. The kinetic friction between the plane and the box is 20% of the normal force (f_k = 0.20n).
02

Free Body Diagram and Pictorial Representation

The diagram would show a box on an inclined plane with a specific angle of 30 degrees. The forces identified and illustrated are: (1) Gravitational force acting vertically downwards (2) Normal Force perpendicular to the plane's surface (3) Frictional force acting parallel to and up the plane (4) downforce of 100N on the box at an angle of 30 degrees to the plane.
03

Solve for the acceleration of the box and the normal force

First, express the normal force in terms of other variables using the second given equation: n = (20kg) * (9.80 m/s^2) - (100N) * \(\sin 30^{\circ}\), which results in n = 176N. Substitute the value of n into the third equation to find the kinetic friction: f_k = 0.20 * 176N = 35.2N. Finally, solve for the acceleration by substitifying the calculated n and f_k values into the first equation, then rearrange for acceleration: \(a_{x} = \frac{(100N) * \(\cos 30^{\circ}\) - 35.2N}{20kg}\), which results in \(a_x = 1.85 m/s^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free-Body Diagram
Visualizing the forces acting on an object is crucial in solving dynamics problems. This is where a free-body diagram (FBD) comes into play. An FBD is a graphical illustration used to depict all the forces acting upon a single object. To draw an effective diagram, follow these steps: Identify all the forces at work, which typically include gravity, normal force, friction, and any applied forces.

Next, represent the object by a dot or a simple shape, like a box. Then draw arrows around the object to represent each force, with arrow length suggesting the relative magnitude of the force. Ensure that the direction of the force arrows shows how the forces are actually acting on the object. For example, gravity will always act downward, while the normal force is perpendicular to the surface of contact.

In our 20kg box example, the FBD would show four main forces: the downward gravitational pull, the upward normal force from the inclined plane's surface, the kinetic friction resisting slide up the plane, and the 100N force acting at a 30-degree angle to the horizontal.
Kinetic Friction
Kinetic friction is the force that opposes the movement once an object has started sliding or is in motion. It's always directed opposite to the direction of motion and is proportional to the normal force acting on the object. The coefficient of kinetic friction (usually denoted as \( \mu_k \)) quantifies this relationship and is different for every pair of materials in contact.

To calculate the kinetic friction force (\( f_k \)), use the formula \( f_k = \mu_k \times n \), where \( n \)) is the normal force. In dynamics equations physics, understanding the effect of this force is vital because it significantly affects the net force and thus the acceleration of the object. As in our example, once you know the normal force, you can determine the kinetic friction force for the 20kg box. With a coefficient of 0.20, a substantial part of the force analysis in such problems involves finding out how much this friction force slows the object down.
Inclined Plane Problems
Dynamics equations pertaining to inclined plane scenarios are a mainstay in physics problems. The key to solving these problems lies in understanding how to decompose forces into components parallel and perpendicular to the surface of the incline.

For an inclined plane, typically you need to consider the gravitational force component parallel to the incline because it's the force causing the motion or contributing to it. Similarly, while the normal force is perpendicular to the inclined surface, it affects the frictional force since it partly determines its magnitude.

In the given problem, the initial step is to break down the 100N force into components parallel and perpendicular to the inclined plane. Then, by applying Newton's second law along the plane's axis, determine the acceleration and additional forces in play. Carefully analyze how these components interact to calculate the net force and, consequently, the motion of the object.
Newton's Second Law
At the heart of many dynamics problems is Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object times its acceleration (\( F = ma \)). This fundamental principle is crucial in solving for the motion of objects when they're subject to various forces.

What makes Newton's second law so powerful is its applicability in different forms of motion and conditions. Whether dealing with forces in a straight line, on an inclined plane, or any other path, the second law gives us the method to find out how those forces will affect the motion of the object.

For example, in our inclined plane problem, careful application of Newton's second law allows us to solve for the box's acceleration by considering all the forces along the axis of motion, including the components of the applied force, the kinetic friction, and the weight component parallel to the incline. By aligning your analysis with this law, you can predict how the object will move given certain forces.

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Most popular questions from this chapter

A horizontal rope is tied to a \(50 \mathrm{kg}\) box on frictionless ice. What is the tension in the rope if: a. The box is at rest? b. The box moves at a steady \(5.0 \mathrm{m} / \mathrm{s} ?\) c. The box has \(v_{x}=5.0 \mathrm{m} / \mathrm{s}\) and \(a_{x}=5.0 \mathrm{m} / \mathrm{s}^{2} ?\)

You are given the dynamics equations that are used to solve a problem. For each of these, you are to a. Write a realistic problem for which these are the correct equations. b. Draw the free-body diagram and the pictorial representation for your problem. c. Finish the solution of the problem. $$\begin{array}{l} T-0.20 n-(20 \mathrm{kg})\left(9.80 \mathrm{m} / \mathrm{s}^{2}\right) \sin 20^{\circ} \\\=(20 \mathrm{kg})\left(2.0 \mathrm{m} / \mathrm{s}^{2}\right) \\\n-(20 \mathrm{kg})\left(9.80 \mathrm{m} / \mathrm{s}^{2}\right) \cos 20^{\circ}=0\end{array}$$

It takes the elevator in a skyscraper \(4.0 \mathrm{s}\) to reach its cruising speed of \(10 \mathrm{m} / \mathrm{s} .\) A \(60 \mathrm{kg}\) passenger gets aboard on the ground floor. What is the passenger's weight a. Before the elevator starts moving? b. While the elevator is speeding up? c. After the elevator reaches its cruising speed?

Try this! Hold your right hand out with your palm perpendicular to the ground, as if you were getting ready to shake hands. You can't hold anything in your palm this way because it would fall straight down. Use your left hand to hold a small object, such as a ball or a coin, against your outstretched palm, then let go as you quickly swing your hand to the left across your body, parallel to the ground. You'll find that the object stays against your palm; it doesn't slip or fall. a. Is the condition for keeping the object against your palm one of maintaining a certain minimum velocity \(v_{\min } ?\) Or one of maintaining a certain minimum acceleration \(a_{\min } ?\) Explain. b. Suppose the object's mass is \(50 \mathrm{g},\) with \(\mu_{3}=0.80\) and \(\mu_{\mathrm{k}}=0.40 .\) Determine either \(v_{\min }\) or \(a_{\mathrm{min}},\) whichever you answered in part a.

You've entered a "slow ski race" where the winner is the skier who takes the longest time to go down a \(15^{\circ}\) slope without ever stopping. You need to choose the best wax to apply to your skis. Red wax has a coefficient of kinetic friction \(0.25,\) yellow is 0.20 green is \(0.15,\) and blue is \(0.10 .\) Having just finished taking physics, you realize that a wax too slippery will cause you to accelerate down the slope and lose the race. But a wax that's too sticky will cause you to stop and be disqualified. You know that a strong headwind will apply a \(50 \mathrm{N}\) horizontal force against you as you ski, and you know that your mass is 75 kg. Which wax do you choose?

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