/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 What is the total energy, in MeV... [FREE SOLUTION] | 91Ó°ÊÓ

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What is the total energy, in MeV, of a. A proton traveling at \(99 \%\) of the speed of light? b. An electron traveling at \(99 \%\) of the speed of light? Hint: This problem uses relativity.

Short Answer

Expert verified
Given that the values for the mass and speed are in the correct units, the total energies of a proton and an electron would be calculated using the above steps. The specifics of these calculations are left up to the individual.

Step by step solution

01

Identify variables

Firstly, identify the necessary variables from the problem. In this case, we need rest mass energy (m) of the proton and the electron in MeV, the speed of light (c) in terms of \(1.0 \times 10^8\) m/s (to keep the units consistent), and the speed of the particles (v), which is \(99\%\) of the speed of light. The rest mass energy for a proton and an electron is around \(938.27 MeV\) and \(0.511 MeV\) respectively.
02

Substitute variables into the formula

Substitute these values into the total energy equation. Remember to square the ratios under the square root, and please ensure all units are compatible before proceeding with calculations.
03

Calculate Total Energy for a Proton

Perform the calculations for the total energy of a proton. Calculate v as \(0.99 \times c\). Insert these values as v and m respectively into the total energy equation, and compute the denominator using the formula \(\sqrt{1 - (v^2/c^2)}\). Now, divide the proton's mass energy by the denominator to get the total energy in MeV.
04

Calculate Total Energy for an Electron

Do the same for the electron. Use \(0.511 MeV\) as the rest mass energy of an electron and substitute this into the total energy equation. Compute the denominator. Divide the electron's mass energy by the denominator to find the total energy in MeV.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Special Relativity
The theory of special relativity, put forth by Albert Einstein in 1905, revolutionized the way we understand space, time, and energy. Special relativity is based on two postulates: the laws of physics are the same in all inertial frames of reference, and the speed of light in a vacuum is constant and independent of the motion of the light source or observer.

One of the most famous equations arising from special relativity is the equation for relativistic mass-energy equivalence, which shows that energy and mass are interchangeable. This equation, often expressed as \( E = mc^2 \), indicates that an object has a greater energy content as its velocity approaches the speed of light. When solving physics problems, such as calculating the total energy of a particle, we use the principles of special relativity to ensure our calculations are accurate at high velocities.
Rest Mass Energy
Every object with mass possesses an intrinsic energy, even when it is at rest. This energy is known as 'rest mass energy', symbolized by \( E_0 \) and given by the equation \( E_0 = m_0c^2 \), where \( m_0 \) is the rest mass of the object and \( c \) is the speed of light.

For subatomic particles like protons and electrons, the rest mass energy is a crucial aspect to consider when calculating their total energy. A proton’s rest mass energy is approximately \(938.27 \text{MeV}\), and an electron's is about \(0.511 \text{MeV}\). To acquire a complete understanding of a particle's energy, one must consider its kinetic energy in addition to its rest mass energy, especially at relativistic speeds.
Speed of Light
The speed of light, denoted by \( c \), is a fundamental physical constant important in many areas of physics. Its value is approximately \(3.00 \times 10^8 \text{m/s}\) in a vacuum. Under special relativity, the speed of light is the upper limit for the speed at which conventional matter, energy, or any signal carrying information can travel.

When dealing with high-velocity entities approaching the speed of light, ordinary Newtonian mechanics no longer suffice, and one must use relativistic mechanics to accurately describe their behavior. For instance, in our exercise, we consider particles traveling at \(99\%\) of the speed of light to understand the vast increase in energy due to such high velocities.
Relativistic Total Energy
The total energy of an object in the relativistic context is the sum of its rest mass energy and the kinetic energy it gains due to motion. It is given by the formula \( E = \gamma m_0c^2 \), where \( \gamma \) (Gamma) is the Lorentz factor, defined as \( \gamma = \frac{1}{\sqrt{1 - \left(\frac{v}{c}\right)^2}} \). Here \( v \) represents the velocity of the object, and \( c \) is the speed of light.

This equation shows that as an object moves faster, its total energy increases dramatically. For velocities approaching the speed of light, the denominator of the Lorentz factor becomes very small, leading to a huge increase in the object's total energy. In solving our exercise, we calculate the total energy for a proton and an electron at \(99\%\) of the speed of light, demonstrating the significant impact of relativistic speeds on the total energy of particles.

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Most popular questions from this chapter

Consider an oil droplet of mass \(m\) and charge \(q .\) We want to determine the charge on the droplet in a Millikan-type experiment. We will do this in several steps. Assume, for simplicity, that the charge is positive and that the electric field between the plates points upward. a. An electric field is established by applying a potential difference to the plates. It is found that a field of strength \(E_{0}\) will cause the droplet to be suspended motionless. Write an expression for the droplet's charge in terms of the suspending field \(E_{0}\) and the droplet's weight \(m g .\) b. The field \(E_{0}\) is easily determined by knowing the plate spacing and measuring the potential difference applied to them. The larger problem is to determine the mass of a microscopic droplet. Consider a mass \(m\) falling through viscous medium in which there is a retarding or drag force. For very small particles, the retarding force is given by \(F_{\text {dag } g}=-b v\) where \(b\) is a constant and \(v\) the droplet's velocity. The sign recognizes that the drag force vector points upward when the droplet is falling (negative v). A falling droplet quickly reaches a constant speed, called the terminal speed. Write an expression for the terminal speed \(v_{\text {lem }}\) in terms of \(m, g,\) and \(b\) c. A spherical object of radius \(r\) moving slowly through the air is known to experience a retarding force \(F_{\text {dasg }}=-6 \pi \eta r v\) where \(\eta\) is the viscosity of the air. Use this and your answer to part b to show that a spherical droplet of density \(\rho\) falling with a terminal velocity \(v_{\text {lema }}\) has a radius $$r=\sqrt{\frac{9 \eta v_{\mathrm{temn}}}{2 \rho g}}$$ d. Oil has a density \(860 \mathrm{kg} / \mathrm{m}^{3} .\) An oil droplet is suspended between two plates \(1.0 \mathrm{cm}\) apart by adjusting the potential difference between them to 1177 V. When the voltage is removed, the droplet falls and quickly reaches constant speed. It is timed with a stopwatch, and falls \(3.00 \mathrm{mm}\) in 7.33 s. The viscosity of air is \(1.83 \times 10^{-5} \mathrm{kg} / \mathrm{ms}\). What is the droplet's charge? \- How many units of the fundamental electric charge does this droplet possess?

An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths \(187,500 \mathrm{V} / \mathrm{m}\) and \(0.125 \mathrm{T},\) respectively. The particle passes out of the electric field, but the magnetic field continues, and the particle makes a semicircle of diameter \(25.05 \mathrm{cm} .\) What is the particle's charge-to-mass ratio? Can you identify the particle?

The diameter of an aluminum atom is approximately \(1.2 \times\) \(10^{-10} \mathrm{m} .\) The diameter of the nucleus of an aluminum atom is approximately \(8 \times 10^{-15} \mathrm{m} .\) The density of solid aluminum is \(2700 \mathrm{kg} / \mathrm{m}^{3}\) a. What is the average density of an aluminum atom? b. Your answer to part a was similar to but larger than the density of solid aluminum. This suggests that the atoms in solid aluminum have spaces between them rather than being tightly packed together. What is the average volume per atom in solid aluminum? If this volume is a sphere, what is the radius? What can you conclude about the average spacing between atoms compared to the size of the atoms? Hint: The volume per atom is not the same as the volume of an atom. c. What is the density of the aluminum nucleus? By what factor is the nuclear density larger than the density of solid aluminum?

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