/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 A quarter-pound hamburger with a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A quarter-pound hamburger with all the fixings has a mass of \(200 \mathrm{g}\). The food energy of the hamburger (480 food calories) is \(2 \mathrm{MJ}.\) a. What is the energy equivalent of the mass of the hamburger? b. By what factor does the energy equivalent exceed the food energy?

Short Answer

Expert verified
The energy equivalent of the mass of the hamburger is \(18*10^9 \mathrm{MJ}\). The factor by which this energy equivalent exceeds the food energy of the hamburger is \(9*10^9\).

Step by step solution

01

Calculate mass in kilograms

Start by converting the mass of the hamburger from grams to kilograms. Remember that there are \(1000 \mathrm{g}\) in a kilogram. So, the mass of the burger in kilograms is \(200 \mathrm{g} / 1000 = 0.2 \mathrm{kg}\).
02

Calculate energy equivalent of mass

Now use Einstein's equation \(E=mc^2\) to calculate the energy equivalent of the mass. Here \(m = 0.2 \mathrm{kg}\) and \(c = 3*10^8 \mathrm{m/s}\). Substituting these values we obtain \(E = 0.2 \mathrm{kg} * (3*10^8 \mathrm{m/s})^2 = 18*10^{15} \mathrm{J}\).
03

Convert energy from joules to megajoules

The energy calculated in the previous step is in joules. Convert to megajoules (MJ) because the food energy of the hamburger is given in this unit. Remember that there are \(10^6 \mathrm{J}\) in a MJ. The equivalent energy is therefore \(18*10^{15} \mathrm{J} / 10^6 = 18*10^9 \mathrm{MJ}\).
04

Calculate the factor

Finally, calculate the factor by which the energy equivalent calculated in step 3 exceeds the actual food energy of the hamburger. This factor is given by \(18*10^9 \mathrm{MJ} / 2 \mathrm{MJ} = 9*10^9\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Einstein's equation
Einstein's equation, also known as the mass-energy equivalence equation, expresses a profound relation between mass and energy. This fundamental formula is written as \( E=mc^2 \), where \( E \) is energy, \( m \) is mass, and \( c \) is the speed of light in a vacuum, approximately \( 3 \times 10^8 \) meters per second. Einstein's equation shows that mass can be converted into a tremendous amount of energy due to the multiplication by the speed of light squared, a very large number.

In practical terms, even a small mass can be converted into a large amount of energy. That's why, in our hamburger exercise, despite its modest mass of 200 grams, the energy equivalent calculated is immense. This principle lies at the heart of nuclear reactions and provides insight into energy production at the atomic level.
  • \( E \) is the energy equivalent of a given mass.
  • \( m \) is the mass of the object.
  • \( c \) is the constant speed of light.
mass-energy equivalence
Mass-energy equivalence is a principle articulated by Einstein, captured through his famous equation \( E=mc^2 \). This principle establishes that mass and energy are two forms of the same thing and can be converted into one another.

The implication of this is enormous for fields like nuclear physics, where small amounts of matter release vast amounts of energy. When considering the hamburger described in the problem, the mass-energy equivalence helps us understand how the mass of a relatively small object like a hamburger could represent an immense source of energy, vastly greater than the chemical energy it provides when consumed.

For instance, the hamburger with a mass of 0.2 kilograms, by mass-energy equivalence, has an energy equivalent of \(18 \times 10^{15}\) joules. This illustrates the vast potential energy encapsulated in even ordinary objects. However, in everyday terms, this potential is not typically accessible as it requires specific conditions, like those found in nuclear reactions, to convert mass to energy.
joules to megajoules conversion
Converting energy units is crucial to properly understanding and comparing energy values, especially when dealing with very large or small quantities. In many physics problems, energy is expressed in joules, but sometimes it is more convenient to use megajoules, particularly when dealing with large amounts of energy.

One megajoule (MJ) equals \(10^6\) joules (J). This conversion is simply done by dividing the number of joules by \(10^6\). Let's look at the problem example: after finding the energy equivalent of the hamburger's mass using Einstein's equation, we have \(18 \times 10^{15}\) joules. Converting to megajoules involves dividing \(18 \times 10^{15}\) by \(10^6\), resulting in \(18 \times 10^9\) megajoules.

Knowing how to effectively convert between these units helps understand the scale of energy involved and allows for a consistent framework for comparing different energy measurements. This also facilitates clear communication in scientific and engineering fields.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At what speed is a particle's total energy twice its rest energy?

Section 37.6 Time Dilation A cosmic ray travels \(60 \mathrm{km}\) through the earth's atmosphere in \(400 \mu s,\) as measured by experimenters on the ground. How long does the journey take according to the cosmic ray?

An astronaut travels to a star system 4.5 ly away at a speed of 0.9c. Assume that the time needed to accelerate and decelerate is negligible. a . How long does the journey take according to Mission Control on earth? b. How long does the journey take according to the astronaut? c. How much time elapses between the launch and the arrival of the first radio message from the astronaut saying that she has arrived?

A very fast pole vaulter lives in the country. One day, while practicing, he notices a 10.0 -m-long barn with the doors open at both ends. He decides to run through the barn at \(0.866 c\) while carrying his 16.0 -m-long pole. The farmer, who sees him coming, says. "Ahal!This guy's pole is length contracted to \(8.0 \mathrm{m}\) There will be a short interval of time when the pole is entirely inside the barn. If I'm quick, I can simultaneously close both barn doors while the pole vaulter and his pole are inside." The pole vaulter, who sees the farmer beside the barn, thinks to himself, "That farmer is crazy. The barn is length contracted and is only \(5.0 \mathrm{m}\) long. My 16.0 -m-long pole cannot fit into a \(5.0-\mathrm{m}-\) long barn. If the farmer closes the doors just as the tip of my pole reaches the back door, the front door will break off the last \(11.0 \mathrm{m}\) of my pole."

In an attempt to reduce the extraordinarily long travel times for voyaging to distant stars, some people have suggested traveling at close to the speed of light. Suppose you wish to visit the red giant star Betelgeuse, which is 430 ly away, and that you want your \(20,000 \mathrm{kg}\) rocket to move so fast that you age only 20 years during the round trip. a. How fast must the rocket travel relative to earth? b. How much energy is needed to accelerate the rocket to this speed? c. Compare this amount of energy to the total energy used by the United States in the year \(2005,\) which was roughly \(1.0 \times 10^{20} \mathrm{J}.\)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.