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A wire with conductivity \(\sigma\) carries current \(I\). The current is increasing at the rate \(d I / d t\) a. Show that there is a displacement current in the wire equal to \(\left(\epsilon_{0} / \sigma\right)(d I / d t)\) b. Evaluate the displacement current for a copper wire in which the current is increasing at \(1.0 \times 10^{6} \mathrm{A} / \mathrm{s}\)

Short Answer

Expert verified
The displacement current for a copper wire in which the current is increasing at \(1.0 \times 10^{6} A/s\) is \(1.48 \times 10^{-18} A\)

Step by step solution

01

Derive displacement current

Start with the formula for displacement current \(I_d =\epsilon_0 d(\sigma E)/dt\). Assuming Wire is long and uniform, the electric field E can be written as \(E = I/\sigma\). Substituting this in, we get \(I_d = \epsilon_0 d(I/\sigma)/dt = (\epsilon_0/\sigma)dI/dt\)
02

Find conductivity for copper

We know the current is increasing at \(1.0 \times 10^{6} A/s\). We need to find the conductivity \(\sigma\) for Copper. The electrical conductivity of copper is approximately \(5.96 \times 10^7 S/m\)
03

Calculate displacement current for copper wire

We can use the formula we derived in step 1 and the conductivity value from step 2 to calculate the displacement current. Use \(I_d = (\epsilon_0 / \sigma) (dI / dt)\). Substituting in given values we get, \(I_d = \frac{(8.85 \times 10^{-12} F/m)}{(5.96 \times 10^7 S/m)} \times 1.0 \times 10^{6} A/s = 1.48 \times 10^{-18} A\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrical Conductivity
Electrical conductivity, symbolized as \(\sigma\), is a measure of a material's ability to allow the flow of electric current. It is defined as the reciprocal of the electrical resistivity \(\rho\), which represents how strongly a material opposes the flow of electric current. Thus, \(\sigma = 1/\rho\).

The ability of electrons to move through a material is what facilitates conductivity. In metals such as copper or silver, the atoms have free electrons in the outer shell which can easily move when an electric potential is applied, making these materials excellent conductors with high \(\sigma\) values.

For students examining the movement of current in a conductor like copper wire, understanding \(\sigma\) is crucial. In practical terms, as \(\sigma\) increases, the material allows more current to pass through it for a given electric field intensity. This heavily influences the calculation of concepts such as displacement current within the material, which is a vital component of understanding how changing electric fields affect the environment within and outside the conductor.
Maxwell's Equations
Maxwell's equations form the foundation upon which classical electromagnetic theory is built. These equations describe how electric charges and currents produce electric and magnetic fields, and vice versa. There are four equations that make up this set:

  • \(abla \cdot \vec{E} = \frac{\rho}{\epsilon_0}\)
  • \(abla \cdot \vec{B} = 0\)
  • \(abla \times \vec{E} = -\frac{\partial \vec{B}}{\partial t}\)
  • \(abla \times \vec{B} = \mu_0\vec{J} + \mu_0\epsilon_0\frac{\partial \vec{E}}{\partial t}\)
The last equation introduces the concept of displacement current \(\vec{I}_d\), which is essential when considering the scenario where a current-carrying conductor is present. It allows the incorporation of a time-varying electric field (the rate of change of the electric field), which produces a magnetic field even in regions where there are no physical charge carriers (currents).

Underlying the exercise in question, one of Maxwell's equations has been applied to derive the displacement current \(I_d\) in a wire with changing current. Students grappling with this concept should recognize that this term was introduced by Maxwell to address discrepancies in the original Ampère's Law when dealing with fields in a vacuum or insulating materials where no actual current flows.
Rate of Change of Current
The rate of change of current is represented mathematically by the derivative \(\frac{dI}{dt}\), where \(I\) is the current and \(t\) is time. This concept is vital in understanding how electromagnetic fields evolve over time. In a circuit, if the current changes, this time-dependent behavior directly affects the magnetic field associated with the current.

In the exercise, this time-varying aspect of current is the central point of study. The displacement current (different from the actual current in conductors) can be interpreted as a form of 'effective' current produced by the changing electric field in a region of space and is given a mathematical form by multiplying the rate of change of current with the vacuum permittivity \(\epsilon_0\) and inversely with the conductivity \(\sigma\).

An accelerated rate of change of current, as seen with large \(\frac{dI}{dt}\) values, would suggest a more significant displacement current. This relationship becomes especially interesting in materials with high conductivity, such as copper, where the actual current flows easily, and changes in it can lead to noticeable effects in the surrounding electromagnetic field.

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