/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 What is the smallest object a mi... [FREE SOLUTION] | 91Ó°ÊÓ

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What is the smallest object a microscope user can see with a 1.0-numerical- aperture objective if she uses light with a wavelength of \(500 \mathrm{nm} ?\)

Short Answer

Expert verified
The smallest object that can be seen under the microscope is 250 nm.

Step by step solution

01

Identify given values

Identify and write down the given values from the question. Here the wavelength \(\lambda = 500 nm = 500 \times 10^{-9} m\) and the numerical aperture NA = 1.0.
02

Insert values into formula

The formula for resolution \(d\) is given by \(d =\frac{\lambda}{2NA}\). Plug in the given values of \(\lambda\) and NA into the equation. Thus get \(d =\frac{500 \times 10^{-9} m}{2 \times 1.0}\)
03

Calculate

Calculate \(\frac{500 \times 10^{-9} m}{2 \times 1.0} = 250 \times 10^{-9} m\) or \(250 nm\)
04

Interpret the result

The calculated value \(250 nm\) indicates the resolution of the microscope. This is the smallest object that the microscope user can see.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Numerical Aperture
The numerical aperture (NA) of a microscope objective lens is a critical factor in determining the resolution of the microscope. The NA is essentially a measure of the lens's ability to gather light and resolve fine specimen detail at a fixed distance. It is defined as:\[NA = n \cdot \sin(\theta)\]where:
  • \(n\) is the refractive index of the medium between the lens and the specimen, typically air or oil.
  • \(\theta\) is the half-angle of the maximum cone of light that can enter or exit the lens.

A higher NA indicates better resolving power of the microscope. It allows more light to be captured from the specimen, resulting in a clearer and more detailed image. For instance, an NA of 1.0 as used in the exercise means the objective has a good capacity to resolve fine details. High NA lenses are essential for seeing very small structures with great clarity.
Wavelength of Light
In microscopes, the wavelength of light used for illumination is crucial in determining the resolution. Resolution refers to the ability of a microscope to distinguish two points as separate entities, and it is inversely proportional to the wavelength of the light used. Shorter wavelengths provide better resolution.
Typical visible light wavelengths range from about 400 nm (nanometers) to 700 nm. Blue light, around 450 nm, and green light, around 500 nm (as in the exercise), are often used in microscopy because they offer a balance between high resolution and confortable viewing.
The use of light with a wavelength of 500 nm, as given in the exercise, is quite common because the green region of the spectrum is highly visible to the human eye and provides a decent resolution for most microscopy applications. When using a microscope, adjusting the wavelength can affect how detailed the image appears.
Resolution Limit
The resolution limit of a microscope is the smallest distance between two points that the microscope can distinguish as separate. It defines the level of detail visible in the microscope image and depends on both the numerical aperture and the wavelength of light used.
The formula for calculating the resolution limit \(d\) is:\[d = \frac{\lambda}{2 \cdot NA}\]where \(\lambda\) is the wavelength of light and \(NA\) is the numerical aperture. In the exercise, substituting \(\lambda = 500 \times 10^{-9} m\) and \(NA = 1.0\) gives:\[d = \frac{500 \times 10^{-9} m}{2 \times 1.0} = 250 \times 10^{-9} m\]This calculation shows the resolution limit is 250 nm, meaning objects smaller than this cannot be resolved or seen clearly under the microscope. It's important for microscope users to choose the right combination of light wavelength and numerical aperture to achieve the resolution needed for their observations.

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Most popular questions from this chapter

A scientist needs to focus a helium-neon laser beam \((\lambda=633 \mathrm{nm})\) to a \(10-\mu \mathrm{m}\) -diameter spot \(8.0 \mathrm{cm}\) behind the lens. a. What focal-length lens should she use? b. What minimum diameter must the lens have?

Two lightbulbs are \(1.0 \mathrm{m}\) apart. From what distance can these light- bulbs be marginally resolved by a small telescope with a 4.0 -cm-diameter objective lens? Assume that the lens is diffraction limited and \(\lambda=600 \mathrm{nm}\).

A 1.0 -cm-tall object is \(2.5 \mathrm{cm}\) to the left of a diverging lens with a focal length of \(-2.5 \mathrm{cm} .\) A converging lens with a focal length of \(5.0 \mathrm{cm}\) is distance \(d\) to the right of the first lens. a. For what value of \(d\) is the image at infinity? b. Draw a ray diagram of this situation. c. What is the angular size of the image as seen by looking through the converging lens? d. What is the angular magnification of this two-lens magnifier?

A microscope with an objective of focal length \(1.6 \mathrm{mm}\) is used to inspect the tiny features of a computer chip. It is desired to resolve two objects only 400 nm apart. What minimum-diameter objective is needed if the microscope is used in air with light of wavelength 550 nm?

A 15 -cm-focal-length converging lens is \(20 \mathrm{cm}\) to the right of a 7.0 -cm-focal-length converging lens. A 1.0 -cm-tall object is distance \(L\) to the left of the first lens. a. For what value of \(L\) is the final image of this two-lens system halfway between the two lenses? b. What are the height and orientation of the final image?

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