/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 37 An object is \(40 \mathrm{cm}\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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An object is \(40 \mathrm{cm}\) in front of a concave mirror with a focal length of \(20 \mathrm{cm} .\) Use ray tracing to locate the image. Is the image upright or inverted?

Short Answer

Expert verified
The image is located 40 cm in front of the mirror on the same side as the object and is inverted.

Step by step solution

01

Identify Known Values

Before we begin ray tracing, let's identify our known values. The object distance \(d_o\) from the mirror is 40 cm (keep in mind that this value is typically negative for a real object in mirror problems) and the focal length \(f\) is 20 cm (also negative since the focus is on the same side as the object for a concave mirror).
02

Find Image Distance Using Mirror Equation

According to the mirror equation: \(\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\) where \(d_i\) is the image distance. Solving for \(d_i\), we get \(d_i = \frac{1}{(\frac{1}{f} - \frac{1}{d_o})} = \frac{1}{(\frac{1}{-20cm} - \frac{1}{-40cm})} = -40cm\). The negative sign indicates that the image is real and located on the same side of the mirror as the object.
03

Determine Image Orientation

The real image formed by a concave mirror is always inverted. This can also be confirmed by the magnification equation, \(m = -\frac{d_i}{d_o}\), which yields \(m = \frac{40cm}{40cm} = -1\), confirming an inverted image (since magnification is negative).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ray Tracing in Mirrors
Ray tracing is a visual method used to determine the characteristics of an image formed by reflection in a mirror. To perform ray tracing with a concave mirror, you draw lines from a point on the object to the mirror and then reflect them according to the following rules:
  • A ray parallel to the principal axis reflects through the focal point.
  • A ray through the focal point reflects parallel to the principal axis.
  • A ray directed towards the center of curvature of the mirror reflects back on itself.
By drawing at least two of these principal rays and finding their intersection point after reflection, one can locate the image. If the rays actually intersect, the image is real and can be projected; if they only appear to intersect when extended behind the mirror, the image is virtual and cannot be projected. In our exercise, ray tracing would show that the reflected rays intersect at a point, indicating that the image is real and located on the same side as the object.
Mirror Equation
The mirror equation is a mathematical relationship that connects the object distance (\(d_o\)), the image distance (\(d_i\)), and the focal length (\(f\)) of a mirror. The formula is expressed as \[\frac{1}{f} = \frac{1}{d_o} + \frac{1}{d_i}\] By rearranging this equation, you can solve for the unknown quantity when the other two are known. In concave mirrors, the focal length is negative, which must be kept in mind when inserting values into the equation. The mirror equation provides a precise quantitative measure of where the image will form and is a fundamental concept in understanding optics.
Image Distance
Image distance (\(d_i\)) is the distance between the image and the mirror along the principal axis. It is a crucial value in determining where the image forms in relation to the mirror. In the exercise, we used the mirror equation to calculate the image distance, which turned out to be \-40\,cm\. The negative value indicates that the image is formed on the same side as the object, which is a characteristic of a real image in concave mirrors. Since the absolute values of the object distance and the image distance are equal, the size of the image will be the same as that of the object.
Image Orientation in Mirrors
Image orientation refers to whether the image is upright or inverted relative to the object. In concave mirrors, the image can be either depending on the object's distance from the mirror. If the object is inside the focal length, the image is virtual, upright, and magnified. However, if the object is outside the focal length, as in our exercise, the image is real, inverted, and can be magnified, reduced, or the same size, based on the object's distance. Using the magnification formula \(m = -\frac{d_i}{d_o}\), we can determine that the negative sign of the magnification indicates an inverted image. For our problem, since the magnification is -1, the image is inverted and the same size as the object.

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