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A gas cylinder holds 0.10 mol of \(O_{2}\) at \(150^{\circ} \mathrm{C}\) and a pressure of 3.0 atm. The gas expands adiabatically until the volume is doubled. What are the final (a) pressure and (b) temperature?

Short Answer

Expert verified
The final pressure and temperature of the gas after adiabatic expansion are approximately \(1.35 atm\) and \(296^{\circ}C\), respectively.

Step by step solution

01

Understand Physics of Adiabatic Processes

An adiabatic change occurs without any heat exchange. For such processes, the heat capacity ratio (\(γ\)) can be used, which is 1.4 for diatomic gases like Oxygen. The adiabatic change formula is \(P V^γ = C\), where \(P\) is pressure, \(V\) is volume, \(γ\) is the heat capacity ratio and \(C\) is a constant.
02

Calculation of Constant \(C\)

From the provided initial conditions, calculate value of \(C\) using the formula above. Substituting the initial values \(P_{1} = 3.0 atm\), \(V_{1} = 1\) (assuming initial volume to be 1), and \(γ = 1.4\), we get: \(C = P_{1} V_{1}^γ = 3.0 atm\).
03

Calculation of Final Pressure \(P_{2}\)

The volume is doubled (i.e. \(V_{2} = 2.0\)). Substitute \(C\), \(V_{2}\) and \(γ\) into the adiabatic change formula to solve for \(P_{2}\): \(P_{2} = C / V_{2}^γ = 1.35 atm\)
04

Calculation of Final Temperature \(T_{2}\)

Use the ideal gas law in the form of \(P_{1}V_{1}/T_{1} = P_{2}V_{2}/T_{2}\) to solve for \(T_{2}\). Substituting the known values and converting temperatures to Kelvin (initial temperature \(T_{1} = 150^{\circ}C = 423K\)), we get: \(T_{2} = P_{2}V_{2}T_{1}/(P_{1}V_{1}) = 569K\). Convert final temperature back to Celsius if needed, yielding \(T_{2} = 296^{\circ}C\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The Ideal Gas Law is a fundamental equation that relates the pressure, volume, and temperature of an ideal gas through a constant, often referred to as the Universal Gas Constant. This constant is the same for all ideal gases and is denoted by the symbol R. The equation of the Ideal Gas Law is expressed as \( PV = nRT \), where P represents the pressure of the gas, V is the volume, n is the amount of substance (in moles), R is the universal gas constant, and T is the absolute temperature (in kelvins).

In the context of the exercise, we saw the use of the Ideal Gas Law in calculating the final temperature of the gas after adiabatic expansion. It ensures that we can link physical properties of a system under the assumption that we are dealing with an ideal gas scenario where the particles neither attract nor repel each other and occupy no volume themselves, which simplifies calculations tremendously.
Heat Capacity Ratio
The heat capacity ratio, also known as the adiabatic index or gamma (\(\gamma\)), is a dimensionless quantity that represents the ratio of a gas's specific heat at constant pressure (\(C_p\)) to its specific heat at constant volume (\(C_v\)). Its value is crucial in adiabatic processes as it comes into play when there is no heat exchange with the surroundings. For diatomic gases such as oxygen (\(O_2\)), the heat capacity ratio is typically around 1.4.

In adiabatic processes, the heat capacity ratio allows us to predict how the pressure and temperature of a gas will change with volume. For example, as in our solution example, when the volume of a gas is increased adiabatically, the temperature and pressure drop, which can be quantitatively calculated using the adiabatic equation \( PV^\gamma = Constant \). Understanding the role of \(\gamma\) assists in predicting and controlling the behavior of gases in a range of scientific and engineering applications.
Thermodynamics
Thermodynamics is a branch of physics that deals with the relationships between heat and other forms of energy. In particular, it describes how thermal energy is converted to and from other forms of energy and how it affects matter. The laws of thermodynamics govern the principles of energy conservation, entropy, and the inherent directionality of heat transfer.

Adiabatic processes are thermodynamic processes that occur without any heat transfer between a system and its environment. This means that any work done by or on the system will result in a change in the system's internal energy, which then leads to changes in properties like temperature and pressure. The example provided in the exercise illustrates how thermodynamics principles apply to real-world situations, such as understanding the behavior of an expanding gas that does not exchange heat with its surroundings.

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Most popular questions from this chapter

A \(2000 \mathrm{cm}^{3}\) container holds 0.10 mol of helium gas at \(300^{\circ} \mathrm{C}\) How much work must be done to compress the gas to \(1000 \mathrm{cm}^{3}\) at (a) constant pressure and (b) constant temperature? (c) Show and label both processes on a single \(p V\) diagram.

\(14 \mathrm{g}\) of nitrogen gas at \(\mathrm{STP}\) are compressed in an isochoric process to a pressure of 20 atm. What are (a) the final temperature, (b) the work done on the gas, (c) the heat input to the gas, and (d) the pressure ratio \(p_{\max } / p_{\min } ?\) (e) Show the process on a \(p V\) diagram, using proper scales on both axes.

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\(n\) moles of an ideal gas at temperature \(T_{1}\) and volume \(V_{1}\) expand isothermally until the volume has doubled, In terms of \(n\) \(T_{1},\) and \(V_{1},\) what are (a) the final temperature, (b) the work done on the gas, and (c) the heat energy transferred to the gas?

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