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Vector \(\vec{A}=3 \hat{\imath}+\hat{\jmath}\) and vector \(\vec{B}=3 \hat{\imath}-2 \hat{\jmath}+2 \hat{k}\)a. What is the cross product \(\vec{A} \times \vec{B} ?\) b. Show vectors \(\vec{A}, \vec{B},\) and \(\vec{A} \times \vec{B}\) on a three- dimensional coordinate system.

Short Answer

Expert verified
a. The cross product \(\vec{A} \times \vec{B} = -2\hat{\imath} - 6\hat{\jmath} - 9\hat{k}\). b. The vectors can be visualized by plotting points at the coordinated and connecting to the origin with directional arrows.

Step by step solution

01

Compute Cross Product

The cross product of two vectors can be calculated using the formula: \[ \vec{A} \times \vec{B} = \left( AyBz - AzBy , AzBx - AxBz , AxBy - AyBx \right) \] Here, \(A_i\) and \(B_i\) represent the components of vectors \(A\) and \(B\) in the \(i^{th}\) direction. Given, \( \vec{A} = 3 \hat{\imath} + \hat{\jmath} \) (i.e., \( A_x = 3, A_y = 1, A_z = 0 \)) and \( \vec{B} = 3\hat{\imath} - 2\hat{\jmath} + 2\hat{k} \) (i.e., Bx = 3, By = -2, Bz = 2). Substituting these values in the formula: \[ \vec{A} \times \vec{B} = \left( 1*2 - 0*(-2) , 0*3 - 3*2 , 3*(-2) - 1*3 \right) = (-2, -6, -9) \]. Therefore, \[ \vec{A} \times \vec{B} = -2\hat{\imath} - 6\hat{\jmath} - 9\hat{k} \].
02

Sketching Vectors

To visualize vectors in a 3D system, use the xyz-axes where \(\hat{\imath}\), \(\hat{\jmath}\) and \(\hat{k}\) represent the x, y and z-axes respectively. For vector \(\vec{A}\), plot a point at (3,1,0). For vector \(\vec{B}\), plot a point at (3, -2, 2). For the cross product vector \(\vec{A} \times \vec{B}\), plot a point at (-2, -6, -9). Connect these points to the origin using arrows, ensuring you properly indicate the direction of the vectors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Components
Vectors are mathematical objects that have both magnitude and direction. In three-dimensional space, any vector can be broken down into three parts, often called components. These components correspond to the vector's influence along the x, y, and z axes.

For example, in the original exercise, vector \( \vec{A} = 3 \hat{\imath} + \hat{\jmath} \) has two components as it is missing the k component, which means there is no movement along the z-axis (i.e., \( A_z = 0 \)). The components of \( \vec{A} \) are:
  • \( A_x = 3 \)
  • \( A_y = 1 \)
  • \( A_z = 0 \)
Meanwhile, vector \( \vec{B} = 3\hat{\imath} - 2\hat{\jmath} + 2\hat{k} \) has all three components:
  • \( B_x = 3 \)
  • \( B_y = -2 \)
  • \( B_z = 2 \)
The components are crucial in calculating operations like the cross product, as they allow us to apply formulas component-wise, simplifying the process. Understanding each component's role will significantly improve grasping vector mathematics, particularly in physics and engineering applications.
Three-Dimensional Coordinate System
The three-dimensional coordinate system is an extension of the two-dimensional plane, introduced to represent any point in space using three values: \( x \), \( y \), and \( z \). This is crucial when dealing with vectors in 3D, as it allows us to represent them in relation to three perpendicular axes.

The x-axis, y-axis, and z-axis facilitate visualization and calculation in three-dimensional space, forming a framework in which vectors can be plotted. Each axis represents one of the directions a vector can move:
  • \( \hat{\imath} \) represents the x-direction.
  • \( \hat{\jmath} \) represents the y-direction.
  • \( \hat{k} \) represents the z-direction.

The meeting point of these axes is called the origin, denoted as \((0,0,0)\). When we place a vector on this system, the vector's components tell us how far to move along each axis from the origin. For instance, a vector \( (3, -2, 2) \) would extend 3 units along the \( x \)-axis, move back 2 units along the \( y \)-axis, and ascend 2 units up the \( z \)-axis.

Recognizing how this system works is essential for performing operations like the cross product correctly, which involves evaluating interactions entirely based on these components' placement in 3D space.
Vector Visualization
Visualizing vectors involves representing them graphically in a three-dimensional space, which helps us better understand and predict their effects and interactions.

To sketch vectors like \( \vec{A} \), \( \vec{B} \), and their cross product \( \vec{A} \times \vec{B} \), we use the 3D coordinate system, following these steps:

1. **Plot the Vectors:** Start at the origin and extend the vector based on its components. For example, vector \( \vec{A} = (3,1,0) \) would go 3 units along the \( x \)-axis and 1 unit along the \( y \)-axis, without any movement in the \( z \)-direction.

2. **Indicate Direction:** Use arrows to indicate the vector's direction, ensuring clarity in which way the vector acts in the space.

3. **Cross Product Vector:** After calculating the cross product, \( \vec{A} \times \vec{B} = (-2, -6, -9) \), represent it similar to the original vectors. This vector starts at the origin and illustrates a distinct direction resulting from the orthogonal interaction of \( \vec{A} \) and \( \vec{B} \).

By visualizing vectors, you bridge the gap between abstract numerical concepts and tangible interpretations, allowing a more intuitive grasp of cross products and other vector operations. This approach not only aids in mathematical comprehension but also in practical application scenarios.

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Most popular questions from this chapter

The tune-up specifications of a car call for the spark plugs to be tightened to a torque of \(38 \mathrm{N} \mathrm{m}\). You plan to tighten the plugs by pulling on the end of a \(25-\mathrm{cm}-\) long wrench. Because of the cramped space under the hood, you'll need to pull at an angle of \(120^{\circ}\) with respect to the wrench shaft. With what force must you pull?

Consider the vector \(\vec{C}=3 \hat{\imath}\) What is a vector \(\vec{D}\) such that \(\vec{C} \times \vec{D}=\overrightarrow{0} ?\) b. What is a vector \(\vec{E}\) such that \(\vec{C} \times \vec{E}=6 \hat{k} ?\) c. What is a vector \(\vec{F}\) such that \(\vec{C} \times \vec{F}=-3 \hat{\jmath} ?\)

An 8.0 -cm-diameter, \(400 \mathrm{g}\) sphere is released from rest at the top of a 2.1 -m-long, \(25^{\circ}\) incline. It rolls, without slipping, to the bottom. a. What is the sphere's angular velocity at the bottom of the incline? b. What fraction of its kinetic energy is rotational?

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A solid sphere of radius \(R\) is placed at a height of \(30 \mathrm{cm}\) on a \(15^{\circ}\) slope. It is released and rolls, without slipping, to the bottom. a. From what height should a circular hoop of radius \(R\) be released on the same slope in order to cqual the sphere's speed at the bottom? b. Can a circular hoop of different diameter be released from a height of \(30 \mathrm{cm}\) and match the sphere's speed at the bottom? If so, what is the diameter? If not, why not?

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