Chapter 9: Problem 20
A charged particle moves with velocity \(\vec{v}=a \hat{i}+d f\) in a magnetic field \(\bar{B}=A \hat{i}+D \hat{j}\). The force acting on the particle has magnitude \(F .\) Then. a. \(F=0\), if \(a D=d A\). b. \(F=0\), if \(a D=-d A\). c. \(F=0\), if \(a A=-d D\). d. \(F \mu\left(a^{2}+b^{2}\right)^{1 / 2} \times\left(A^{2}+D^{2}\right)^{1 / 2}\)
Short Answer
Step by step solution
Understand the Lorentz Force
Determine the Cross Product
Find the Magnitude of the Force
Determine when the Force is Zero
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross Product
- Place unit vectors \( \hat{i}, \hat{j}, \hat{k} \) at the top row of a matrix.
- Insert the components of the velocity vector \( \vec{v} = a \hat{i} + d \hat{k} \) in the second row.
- Put the components of the magnetic field vector \( \vec{B} = A \hat{i} + D \hat{j} \) in the third row.
Magnetic Field
Charged Particle
Velocity Vector
- \( a \): Component in the \( \hat{i} \) direction
- \( d \): Component in the \( \hat{k} \) (vertical) direction