Chapter 1: Problem 12
A cenain charge ' \(Q\) ' is to be divided into two parts \(q\) and \(Q-q\). What is the relationship of ' \(Q\) ' to ' \(q\) ' if the two parts. placed at a given distance ' \(r\) ' apart are to have maximum Coulomb repulsion? a. \(q=\frac{Q}{2}\) b. \(q=\frac{Q}{3}\) c. \(q=\frac{2 Q}{2}\) d. \(q=\frac{Q}{4}\)
Short Answer
Step by step solution
Understanding the Problem
Coulomb's Law
Expressing Force to Maximize
Finding Maximum Using Derivative
Solving for q
Double-checking the Result
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coulomb's Law
- \( F = k \frac{q_1 q_2}{r^2} \)
- Where \( F \) is the force of attraction or repulsion.
- \( k \) is Coulomb's constant, which is roughly \( 8.9875 \times 10^9 \text{ N m}^2/\text{C}^2 \).
- The force is attractive if the charges are opposite and repulsive if they are alike.
Charge Distribution
- It helps in predicting forces between charges, as explored through the Coulomb's Law application.
- Allows us to optimize the configuration for maximum or minimum force, which is essential in many applications such as improving efficiency in electrical circuits.
- Gives insight into the behavior of charged objects in different mediums and contexts.