/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 89 A body of mass \(M\) is resting ... [FREE SOLUTION] | 91Ó°ÊÓ

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A body of mass \(M\) is resting on a rough horizontal plane surface, the coefficient of friction being equal to \(\mu .\) At \(t=0\) a horizontal force \(F=F_{0} t\) starts acting on it, where \(F_{0}\) is a constant. Find the time \(T\) at which the motion starts? a. \(\mu M g / F_{0}\) b. \(M g / \mu F_{0}\) c. \(\mu F_{0} / M g\) d. None of these

Short Answer

Expert verified
The motion starts at time \( T = \frac{\mu M g}{F_{0}} \), matching option (a).

Step by step solution

01

Understanding the Forces Involved

When an object is at rest on a horizontal surface with friction, the maximum static friction force can be given by the formula \( F_{\text{friction}} = \mu M g \), where \( \mu \) is the coefficient of friction, \( M \) is the mass of the object, and \( g \) is the acceleration due to gravity.
02

Determine the Condition for Motion

The object will start moving when the applied force \( F \) exceeds the maximum static friction force. Since the applied force is given by \( F = F_{0} t \), motion starts the moment \( F_{0} t = \mu M g \).
03

Solve for Time \( T \)

To find the time \( T \) when motion starts, set \( F_{0} T = \mu M g \) and solve for \( T \) by dividing both sides by \( F_{0} \), giving us \( T = \frac{\mu M g}{F_{0}} \).
04

Match with Options

Compare \( T = \frac{\mu M g}{F_{0}} \) with the given options. This matches option (a), which is \( \mu M g / F_{0} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

static friction
Static friction is a type of friction that acts between surfaces that are not moving relative to each other. In simple terms, it is the force keeping an object at rest when someone tries to push it. Imagine trying to push a heavy piece of furniture across a rug. The difficulty you encounter at first is due to static friction. It
  • opposes the applied force up to a certain limit before sliding starts,
  • is dependent on the nature of the surfaces in contact,
  • is proportional to the normal force, which is the perpendicular force exerted by a surface on the object resting on it.
The maximum static friction force can be calculated using the equation \( F_{\text{friction}} = \mu M g \). Here, \( \mu \) is the coefficient of static friction, \( M \) is the mass of the object, and \( g \) represents the acceleration due to gravity. This equation is critical when determining when a stationary object will begin to move under the influence of an increasing force.
Newton's laws of motion
Newton's laws of motion form the foundation for understanding the mechanics behind motion and friction. These laws can be outlined as follows:
  • The First Law, often called the law of inertia, states that an object at rest will stay at rest, and an object in motion will stay in motion at a constant velocity unless acted upon by a net external force.
  • The Second Law provides the relationship between force, mass, and acceleration: \( F = ma \). This tells us that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
  • The Third Law of Motion expresses that for every action, there is an equal and opposite reaction. This is crucial in interactions involving friction, as the surface pushing back with equal force is a direct result of this law.
When assessing the motion of an object, Newton's laws help explain:
  • why an object at rest does not move until the applied force exceeds static friction,
  • how the force applied contributes to the start of movement.
Understanding these laws provides a complete picture of why and how a body transitions from a state of rest to motion under the influence of forces.
applied force
Applied force is a straightforward yet central concept in mechanics. It refers to the force that is directly applied to an object by another object or person. In this exercise, it's represented as \( F = F_0 t \), meaning the force increases over time—a common scenario in real world applications where forces are not necessarily constant, such as the gradual increase of pressure from pushing harder on a stationary object. This approach allows us to analyze how gradually escalating forces affect the transition from static to dynamic friction.
  • This applied force must surpass static friction to set the object in motion.
  • Once the applied force exceeds \( F_{\text{friction}} = \mu M g \), movement begins, marking the switch from static to kinetic friction.
Studying applied force helps us understand the relationship between the increasing force over time and the moment the object begins to move.

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Most popular questions from this chapter

Mark out the most appropriate statement. a. The normal force is the same thing as the weight. b. The normal force is different from the weight, but always has the same magnitude. c. The normal force is different from the weight, but the two form an action- reaction pair according to the Newton's third law. d. The normal force is different from the weight, but the two may have same magnitude in certain cases.

A triangular prism of mass \(M\) with a block of mass \(m\) placed on it is released from rest on a smooth inclined olane of inclination \(\theta\). The block does not slip on the prism. Then a. The acceleration of the prism is \(g \cos \theta\). b. The acceleration of the prism is \(g \tan \theta\). c. The minimum coefficient of friction between the block and the prism is \(\mu_{\operatorname{mia}}=\cot \theta\). d. The minimum coefficient of friction between the block and the prism is \(\mu_{\min }=\tan \theta\).

An object moving with a constant acceleration in a noninertial frame a. must have non-zero net force acting on it. b. may have zero net force acting on it. c. may have no force acting on it. d. this situation is practically impossible. (The pseudo force acting on the object has also to be considered)

Three light strings are connected at the point \(P .\) A weight \(W\) is suspended from one of the strings. End \(A\) of string AP and end \(B\) of string \(P B\) are fixed as shown. In equilibrium \(P B\) is horizontal and \(P A\) makes an angle of \(60^{\circ}\) with the horizontal. If the tension in \(P B\) is \(30 \mathrm{~N}\) then the tension in \(P A\) and weight \(W\) are respectively given by a. \(60 \mathrm{~N} ; 30 \mathrm{~N}\) b. \(60 / \sqrt{3} \mathrm{~N} ; 30 / \sqrt{3} \mathrm{~N}\) c. \(60 \mathrm{~N} ; 30 \sqrt{3} \mathrm{~N}\) d. \(60 \sqrt{3} \mathrm{~N}: 30 \sqrt{3} \mathrm{~N}\)

A horizontal force of \(25 \mathrm{~N}\) is necessary to just hold a block stationary against a wall the coefficient of friction between the block and the wall is \(0.4\). The weight of the block is a. \(2.5 \mathrm{~N}\) b. \(20 \mathrm{~N}\) c. \(10 \mathrm{~N}\) d. \(5 \mathrm{~N}\)

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