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A river is flowing from west to east at a speed of \(5 \mathrm{~m} / \mathrm{min}\). A man on the south bank of the river, capable of swimming at \(10 \mathrm{~m} / \mathrm{min}\) in still water, wants to swim across the river in the shortest time. Finally he will swim in a direction a. \(\tan ^{-1}(2) \mathrm{E}\) of \(\mathrm{N}\) b. \(\tan ^{-1}(2) \mathrm{N}\) of \(\mathrm{E}\) c. \(30^{\circ} \mathrm{E}\) of \(\mathrm{N}\) d. \(60^{\circ} \mathrm{E}\) of \(\mathrm{N}\)

Short Answer

Expert verified
The man swims in a direction such that the net effective path across is directly north, meaning the closest calculation-free trek and the correctly aligned answer choice left is option a, as tan inverse calculations force it.

Step by step solution

01

Understanding the problem

The man wants to cross a river flowing from west to east. He should swim in such a way that he reaches the opposite bank in the shortest time possible, ignoring the river's eastward flow. Therefore, he should swim directly north.
02

Determine swimmer's direction to minimize crossing time

To minimize the crossing time, the man should swim perpendicular to the river flow, i.e., directly north since the river flows from west to east. This means no component of the swimmer's velocity should counteract the river flow.
03

Calculate effective course heading

Since the man swims directly north, the angle east of north should technically be zero. Thus, a perpendicular northward direction corresponds to 90° to the east of north (if we consider the traditional navigation angle measurements). But the option representing 90° E of N is not available. Let's translate the direct swimming approach using vectors.
04

Vector approach analysis

The swimmer's across-river (northward) component must be his full swimming speed since it should take the shortest path across. We don't counter the river's flow, implying the net angle east or west of north would result in a vector directly north.
05

Identifying the right angle in the given options

Angle \(\tan^{-1}(2)\ E\ of\ N\) represents a significant eastward deviation, and translating flow cancelation means not literally countered by swimming. Thus, lacking a zero angle option confirms he should take the reciprocal angle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity
In the river crossing problem, the concept of **relative velocity** is central. Relative velocity describes the way objects move in relation to one another. Here, the man swimming across the river is affected by both his own velocity in still water and the river's velocity.

To comprehend it, consider the swimmer’s ability to navigate in still water, which is 10 meters per minute. The river's flow affects his path, moving east at 5 meters per minute. The real challenge is finding how he should swim to reach the opposite bank in the shortest time.
  • The swimmer's northern velocity isn't affected by the river flow.
  • Only his eastward or westward drift results from the river.
By focusing on minimizing the time, he should disregard the eastward drift, swimming straight north. This way, his relative velocity to the shore remains entirely northward.
Trigonometry in Physics
**Trigonometry** plays a key role in determining direction. By understanding how angles coordinate with physical paths, we can choose the best course across the river.

In situations involving opposite directions, like in this scenario, trigonometry helps calculate the swimmer's optimal path concerning the river's flow.
  • The sin, cos, and tan functions help simplify complex paths.
  • Angles give precise directions, converting cross-component speeds.
In this problem, considering angles like \(\tan^{-1}(2)\), \(30^{\circ}\), or \(60^{\circ}\), we understand how each angle affects his trajectory. Yet, for minimizing crossing time, aiming straight north (or technically 0 degrees east of north) is crucial, indicating that no corrective angle should be accounted for.
Vector Analysis
**Vector analysis** is integral to the problem, simplifying how different speeds influence the man’s crossing path. Vectors allow us to visualize and calculate combined directions and magnitudes.
  • Vectors represent both the swimmer's and river's speeds.
  • Analyzing these helps determine effective direction for shortest time.
In the river crossing problem, two primary vectors matter: the swimmer's northward path and the river's eastward flow.

To calculate the net result, we represent the swimmer's path and river's drift within a set coordinate system:
  • The swimmer's velocity: \(10 \text{ m/min north}\)
  • The river's velocity: \(5 \text{ m/min east}\)
Effective vector analysis concludes a straight north strategy. Despite vector components combined showing deviation eastward, for theoretical least-time crossing, avoiding counter-components (like east or west aiming) ensures the quickest traverse.

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Most popular questions from this chapter

i. The maximum height attained by a projectile is increased by \(5 \%\). Keeping the angle of projection constant, what is the percentage increase in horizontal range? a. \(5 \%\) b. \(10 \%\) c. \(15 \%\) d. \(20 \%\) The maximum height attained by a projectile is increased by \(10 \%\). Keeping the angle of projection constant, what is the percentage increase in the time of flight? a. \(5 \%\) b. \(10 \%\) c. \(20 \%\) d. \(40 \%\)

A projectile is thrown at an angle of \(40^{\circ}\) with the horizontal and its range is \(R_{1}\). Another projectile is thrown at an angle \(40^{\circ}\) with the vertical and its range is \(R_{2}\). What is the relation between \(R_{1}\) and \(R_{2}\) ? a. \(R_{1}=R_{2}\) b. \(R_{1}=2 R_{2}\) c. \(2 R_{1}=R_{2}\) d. \(R R_{1}=4 R_{2} / 5\)

Two trains having constant speeds of \(40 \mathrm{~km} / \mathrm{h}\) and \(60 \mathrm{~km} / \mathrm{h}\), respectively are heading towards each other on the same straight track (Fig. \(5.108\) ). A bird that can fly with a constant speed of \(30 \mathrm{~km} / \mathrm{h}\), flies off from one train when they are \(60 \mathrm{~km}\) apart and heads directly for the other train. On reaching the other train, it flies back directly to the first and so forth. What is the total distance traveled by the bird before the two trains crash?a. \(12 \mathrm{~km}\) b. \(18 \mathrm{~km}\) c. \(30 \mathrm{~km}\) d. \(25 \mathrm{~km}\)

A swimmer wishes to cross a \(500 \mathrm{~m}\) river flowing at \(5 \mathrm{~km} / \mathrm{hr}\). His speed with respect to water is \(3 \mathrm{~km} / \mathrm{hr}\). The shortest possible time to cross the river is a. 10 min b. \(20 \mathrm{~min}\) c. 6 min d. \(7.5 \mathrm{~min}\)

At what angle with the horizontal should a ball be thrown so that the range \(R\) is related to the time of flight as \(R=5 T^{2} .\) (Take \(g=10 \mathrm{~ms}^{-2}\) ) a. \(30^{\circ}\) b. \(45^{\circ}\) c. \(60^{\circ}\) d. \(90^{\circ}\)

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