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A point moves with uniform acceleration and \(v_{1}, v_{2}\) and \(v_{3}\) denote the average velocities in the three successive intervals of time \(t_{1}, t_{2}\) and \(t_{3} .\) Which of the following relations is correct? a. \(\left(v_{1}-v_{2}\right):\left(v_{2}-v_{3}\right)=\left(t_{1}-t_{2}\right):\left(t_{2}+t_{3}\right)\) b. \(\left(v_{1}-v_{2}\right):\left(v_{2}-v_{3}\right)=\left(t_{1}+t_{2}\right):\left(t_{2}+t_{3}\right)\) c. \(\left(v_{1}-v_{2}\right):\left(v_{2}-v_{3}\right)=\left(t_{1}-t_{2}\right):\left(t_{1}-t_{3}\right)\) d. \(\left(v_{1}-v_{2}\right):\left(v_{2}-v_{3}\right)=\left(t_{1}-t_{2}\right):\left(t_{2}-t_{3}\right)\)

Short Answer

Expert verified
None of the provided options are correct; the proper ratio is \( \frac{t_2}{t_3} \).

Step by step solution

01

Understanding Average Velocity

Average velocity for a time interval with initial velocity \( u \) and uniform acceleration \( a \) is given by \( v = \frac{u + u + at}{2} = u + \frac{at}{2} \). Thus, for each interval, \( v_1, v_2, \) and \( v_3 \) can be expressed as follows: \[ v_1 = u + \frac{a t_1}{2}, \quad v_2 = u + \frac{a (t_1 + t_2)}{2}, \quad v_3 = u + \frac{a (t_1 + t_2 + t_3)}{2} \]
02

Calculating Differences in Velocities

Calculate the differences in velocities:\[ v_1 - v_2 = \left( u + \frac{a t_1}{2} \right) - \left( u + \frac{a (t_1 + t_2)}{2} \right) = -\frac{a t_2}{2} \] and same for next interval:\[ v_2 - v_3 = \left( u + \frac{a (t_1 + t_2)}{2} \right) - \left( u + \frac{a (t_1 + t_2 + t_3)}{2} \right) = -\frac{a t_3}{2} \]
03

Finding the Ratio of Velocity Differences

Since both differences are negative, their relationship in ratio form is \[ \frac{v_1 - v_2}{v_2 - v_3} = \frac{-\frac{a t_2}{2}}{-\frac{a t_3}{2}} = \frac{t_2}{t_3} \] This implies the velocity differences are directly proportional to the times \( t_2 \) and \( t_3 \).
04

Analyzing Options for Correct Ratio

None of the given options directly match the ratio \( \frac{t_2}{t_3} \) we've derived from the process. However, rewriting option a) gives:\( \left(t_{1} - t_{2}\right) : \left(t_{2} + t_{3}\right) \) This doesn't match our derived ratio with \( \frac{t_2}{t_3} \). The correct relation involves a direct reduction of t's, Changing parameters to closer forms doesn't result directly with standard choices provided.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Velocity
Average velocity in the context of uniform acceleration is an essential concept to grasp, especially when faced with problems involving motion in physics. When an object moves with uniform acceleration, its velocity changes at a constant rate. Average velocity describes the object's velocity over a given time interval. It is the sum of the initial velocity and final velocity, divided by two. In mathematical terms:
\[ v = \frac{u + u + at}{2} = u + \frac{at}{2} \]
  • Here, \(u\) represents the initial velocity.
  • \(a\) is the acceleration, which is constant.
  • \(t\) is the time duration for which the object has been accelerating.
For three successive intervals, these average velocities become:
  • \( v_1 = u + \frac{a t_1}{2} \)
  • \( v_2 = u + \frac{a (t_1 + t_2)}{2} \)
  • \( v_3 = u + \frac{a (t_1 + t_2 + t_3)}{2} \)
Each of these equations helps in understanding how the average velocity changes over different intervals of motion.
Velocity Differences
When assessing changes in velocity over time intervals, the differences between the average velocities for successive intervals come into play. Velocity difference tells us how much the average velocity has changed from one interval to the next, indicating acceleration's role in the object's movement. To calculate the differences:
For the first interval into the second:
  • \( v_1 - v_2 = \left( u + \frac{a t_1}{2} \right) - \left( u + \frac{a (t_1 + t_2)}{2} \right) = -\frac{a t_2}{2} \)
For the second interval into the third:
  • \( v_2 - v_3 = \left( u + \frac{a (t_1 + t_2)}{2} \right) - \left( u + \frac{a (t_1 + t_2 + t_3)}{2} \right) = -\frac{a t_3}{2} \)
Both the differences are negative, emphasizing that the velocities decrease through each stage—an effect of the consistent uniform acceleration. These values shed light on how each time period contributes to the total change in motion.
Time Intervals
Time intervals play a crucial role when evaluating motion under uniform acceleration. Each interval, marked by \( t_1, t_2, \) and \( t_3 \), signifies a separate part of the overall journey, contributing to changes in velocity as seen in the earlier sections.
Uniform acceleration means the rate of change of velocity remains constant across these intervals. This constancy allows us to relate velocity differences directly to their respective time intervals. As we discovered from calculating velocity differences:
  • In the ratio \( \frac{v_1 - v_2}{v_2 - v_3} = \frac{t_2}{t_3} \), the velocity differences are directly proportional to the durations of the intervals that define those differences.
Understanding how time intervals impact velocity change helps in forming a more detailed perspective on an object's movement. Each interval is a piece of the larger motion puzzle, and knowing the relationships between velocity differences and time intervals is key to deciphering motion under uniform acceleration.

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Most popular questions from this chapter

If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is a. inversely proportional to the square root of the displacement b. inversely proportional to the displacement c. directly proportional to the displacement d. directly proportional to the square root of the displacement

Two trains \(A\) and \(B, 100 \mathrm{~m}\) and \(60 \mathrm{~m}\) long, are moving in opposite directions on parallel tracks. The velocity of shorter train in 3 times that of the longer one. If the trains take 4 s to cross each other, the velocities of the trains are a. \(V_{A}=10 \mathrm{~m} / \mathrm{s}, V_{B}=30 \mathrm{~m} / \mathrm{s}\) b. \(V_{A}=2.5 \mathrm{~m} / \mathrm{s}, V_{B}=7.5 \mathrm{~m} / \mathrm{s}\) c. \(V_{A}=20 \mathrm{~m} / \mathrm{s}, V_{B}=60 \mathrm{~m} / \mathrm{s}\) d. \(V_{A}=5 \mathrm{~m} / \mathrm{s}, V_{B}=15 \mathrm{~m} / \mathrm{s}\)

Between two stations a train starting from rest first accelerates uniformly, then moves with constant velocity and finally retards uniformly to come to rest. If the ratio of the time taken be \(1: 8: 1\) and the maximum speed attained be \(60 \mathrm{~km} / \mathrm{h}\), then what is the average speed over the whole journey? a. \(48 \mathrm{~km} / \mathrm{h}\) b. \(52 \mathrm{~km} / \mathrm{h}\) c. \(54 \mathrm{~km} / \mathrm{h}\) d. \(56 \mathrm{~km} / \mathrm{h}\)

If two balls of same density but different masses are dropped from a height of \(100 \mathrm{~m}\), then (neglect air resistance) a. both will come together on the earth b. both will come late on the earth c. first will come first and second after that d. second will come first and first after that

A body sliding on a smooth inclined plane requires \(4 \mathrm{~s}\) to reach the bottom, starting from rest at the top. How much time does it take to cover one fourth the distance starting from rest at the top? a. \(1 \mathrm{~s}\) b. \(2 \mathrm{~s}\) c. \(4 \mathrm{~s}\) d. \(16 \mathrm{~s}\)

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