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A blinp motoring at a constant altirude tus a velocity component of \(15 \mathrm{~km} / \mathrm{h}\) in the north direction and a velocity component of \(15 \mathrm{~km} / \mathrm{h}\) in the eust dircetion. What is the speed of the blimp? What in the dircction of motion of the blimp?

Short Answer

Expert verified
Speed: 21.21 km/h. Direction: 45 degrees east of north.

Step by step solution

01

Understand the Problem

We need to find the speed and direction of a blimp moving at constant velocity with components of 15 km/h north and 15 km/h east. Speed is the magnitude of the velocity vector, and the direction is the angle of the velocity vector with the north direction.
02

Calculate the Speed

The speed of the blimp is the magnitude of its velocity vector. This can be found using the Pythagorean theorem because the north and east components form a right-angled triangle. The formula for speed (magnitude of velocity) is given by \( v = \sqrt{v_{north}^2 + v_{east}^2} \). Substituting the values, \( v = \sqrt{15^2 + 15^2} = \sqrt{225 + 225} = \sqrt{450} \approx 21.21 \text{ km/h} \).
03

Calculate the Direction

The direction can be found by calculating the angle made by the velocity vector with the north direction using the tangent function. The formula to find the angle \( \theta \) is \( \theta = \tan^{-1} \left( \frac{v_{east}}{v_{north}} \right) \). Substituting the values, \( \theta = \tan^{-1} \left( \frac{15}{15} \right) = \tan^{-1}(1) = 45^{\circ} \). Thus, the direction is 45 degrees east of north.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnitude Calculation
When we talk about finding the speed of an object that is moving in two different directions, we're really talking about finding the magnitude of its velocity vector. Imagine a blimp flying both north and east at the same time. The velocity components in the north and east directions can be visualized as the two sides of a right triangle. The blimp's actual speed, which is the hypotenuse of this triangle, is the magnitude of its velocity.
To calculate this magnitude, use the Pythagorean theorem, which tells us that the square of the length of the hypotenuse (here, the speed) equals the sum of the squares of the other two sides (the velocity components). Thus, the formula is:
  • \( v = \sqrt{v_{north}^2 + v_{east}^2} \)
For a blimp with velocities of 15 km/h north and 15 km/h east, the speed is
  • \( v = \sqrt{15^2 + 15^2} = \sqrt{450} \approx 21.21 \text{ km/h} \)
This gives us the blimp's overall speed, calculated by combining its movements in both directions.
Direction of Motion
Figuring out which direction an object is moving involves finding the angle its path makes with a known line, like the north direction. For a blimp moving north and east, we want to determine the angle of its path from north. This direction is determined using the inverse tangent (arctan or \( \tan^{-1} \)) of the ratio of the eastward velocity to the northward velocity.
Here's the formula used:
  • \( \theta = \tan^{-1} \left( \frac{v_{east}}{v_{north}} \right) \)
When both velocities are equal, as in our example where both are 15 km/h, the angle is:
  • \( \theta = \tan^{-1}(1) = 45^{\circ} \)
Therefore, the direction of motion of the blimp is at an angle of 45 degrees east of north, forming a perfect diagonal between the north and east directions.
Pythagorean Theorem
The Pythagorean theorem is a fundamental part of mathematics used to calculate distances and understand relations in right-angled triangles. In vector addition, it becomes crucial for finding the magnitude of a vector when given its components. The theorem states that for a right triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
In our context, this theorem helps in finding the speed of a blimp traveling at velocity components in perpendicular directions like north and east. Specifically, if \( v_{north} \) and \( v_{east} \) are the legs of the triangle, the Pythagorean theorem gives:
  • \( c^2 = a^2 + b^2 \)
Translating this to vectors, the speed \( v \) is:
  • \( v = \sqrt{v_{north}^2 + v_{east}^2} \)
This theorem is a powerful tool that allows us to combine the perpendicular components of velocity to find an object's resultant speed in a straightforward manner.

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Most popular questions from this chapter

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