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An automobile has wheels of diameter \(64 \mathrm{~cm}\). What is the centripetal acceleration of a point on the rim of this wheel when the automobile is traveling at \(95 \mathrm{~km} / \mathrm{h}\) ?

Short Answer

Expert verified
Centripetal acceleration is approximately 2176.35 m/s².

Step by step solution

01

Convert the Speed to Meters per Second

The speed of the automobile is given as \(95 \mathrm{~km/h}\). To convert this to meters per second, use the conversion factor: \[ 1 \mathrm{~km/h} = \frac{1}{3.6} \mathrm{~m/s} \]Thus, \[ 95 \mathrm{~km/h} \times \frac{1}{3.6} = 26.39 \mathrm{~m/s} \]
02

Calculate the Wheel's Radius

Given the diameter of the wheel is \(64 \mathrm{~cm}\), first convert this to meters by dividing by 100 (since 100 cm = 1 m): \[ \text{Diameter in meters} = \frac{64}{100} = 0.64 \mathrm{~m} \]The radius \( r \) is half of the diameter: \[ r = \frac{0.64}{2} = 0.32 \mathrm{~m} \]
03

Use the Formula for Centripetal Acceleration

The formula for centripetal acceleration \( a_c \) is given by: \[ a_c = \frac{v^2}{r} \]where \( v = 26.39 \mathrm{~m/s} \) and \( r = 0.32 \mathrm{~m} \).
04

Substitute Values into Centripetal Acceleration Formula

Substitute the values for \( v \) and \( r \) into the formula:\[a_c = \frac{(26.39)^2}{0.32} \approx \frac{696.4321}{0.32} \approx 2176.35 \mathrm{~m/s}^2\]
05

Conclusion

The centripetal acceleration of a point on the rim of the wheel is approximately \(2176.35 \mathrm{~m/s}^2\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newtonian Mechanics
Newtonian Mechanics is a fundamental part of physics that focuses on the motion of objects and the forces that cause these motions. This concept was established by Sir Isaac Newton and includes three pivotal laws of motion. In the context of centripetal acceleration, Newton's Second Law becomes highly relevant. This law states that the acceleration of an object is proportional to the net force acting upon it and inversely proportional to its mass: \[ F = ma \]Understanding centripetal force, which is needed for an object to move in a circular path, is essential. This force always points towards the center of the circle and maintains the circular motion. Without this force, an object would continue in a straight line, as per Newton's First Law of inertia. For instance, in an automobile, the wheels generate centripetal force to change the direction of motion and create acceleration towards the center of the circular path.
Kinematic Equations
Kinematic Equations are utilized to describe the motion of objects. They relate quantities such as displacement, velocity, acceleration, and time. These equations, however, primarily deal with linear motion. For rotational or circular motion, the concepts still apply, but the variables are adapted to reflect the circular path.Centripetal acceleration is a concept that arises in circular motion and can be described by the equation:\[ a_c = \frac{v^2}{r} \]where \(v\) is the linear velocity and \(r\) is the radius of the circle. This kinematic equation shows how the velocity of an object moving in a circle and the radius of that circle determine the acceleration experienced at the edge of the wheel. It's crucial to realize that centripetal acceleration does not alter the speed of the object but only changes its direction.
Unit Conversion
Unit Conversion is an important aspect of physics to ensure that calculations are accurate and meaningful. It involves changing a quantity expressed in one kind of unit to another while maintaining the same value. In our exercise, converting speed from kilometers per hour (km/h) to meters per second (m/s) is essential because most formulas in physics, including centripetal acceleration, require standard SI units (meters and seconds).To convert \(95 \text{ km/h}\) to \(\text{m/s}\), we use the conversion factor:\[ 1\text{ km/h} = \frac{1}{3.6}\text{ m/s} \]This conversion helps to simplify and properly solve equations with consistent units, thereby avoiding miscalculations due to unit discrepancies. Remembering common conversion factors can save time and reduce errors during problem solving.
Rotational Motion
Rotational Motion occurs when an object turns or spins around a central axis. It has components like torque, angular velocity, and angular acceleration; however, one key aspect is centripetal acceleration, which is the acceleration that prompts an object to follow a circular path.In the case of our exercise, the automobile's wheel experiences rotational motion. A point on the rim of the wheel undergoes circular motion, and its centripetal acceleration is calculated using:\[ a_c = \frac{v^2}{r} \]This formulates the relationship between the linear velocity of the automobile and the radius of the wheel, effectively linking linear motion concepts with rotational dynamics. Rotational motion is crucial in situations like driving, where wheel dynamics play a significant role in controlling the vehicle's movement and helps in understanding the forces acting on moving objects.

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