/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 105 You are driving an automobile at... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You are driving an automobile at a steady speed of \(90 \mathrm{~km} / \mathrm{h}\) along a straight highway. Ahead of you is a 10-m-long truck traveling at a steady specd of \(60 \mathrm{~km} / \mathrm{h}\). You decide to pass this tracks, and you switch into the passing lane when \(40 \mathrm{~m}\) behind the truck. (a) What is your speed in the reference frame of the truck? (b) How long do you take to pass the oruck, starting \(40 \mathrm{~m}\) behind the truck and coding \(40 \mathrm{~m}\) ahead of the truck? (Hint) Calculate this time in the reference frame of the truck.)

Short Answer

Expert verified
(a) 30 km/h (b) Approximately 10.8 seconds.

Step by step solution

01

Understanding the Problem

You are driving at a speed of 90 km/h while the truck is moving at 60 km/h. You're initially 40 m behind the truck and want to finish 40 m ahead after passing. We need to calculate the passing time and understand speed in the truck's reference frame.
02

Calculate Relative Speed

The speed of your car in the reference frame of the truck is found by subtracting the truck's speed from your speed. \[\text{Relative Speed} = 90 \text{ km/h} - 60 \text{ km/h} = 30 \text{ km/h}\]
03

Convert Relative Speed to Meters per Second

Convert the relative speed from km/h to m/s since the distances involved are in meters. Use the conversion factor 1 km/h = 0.27778 m/s.\[\text{Relative Speed} = 30 \times 0.27778 = 8.33 \text{ m/s}\]
04

Calculate the Total Passing Distance

The total passing distance is the sum of the distance initially behind the truck, the truck's length, and the distance after passing. \[= 40 \text{ m} + 10 \text{ m} + 40 \text{ m} = 90 \text{ m}\]
05

Calculate Passing Time in the Truck's Reference Frame

Using the relative speed, calculate the passing time. Use the formula \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\).\[\text{Time} = \frac{90 \text{ m}}{8.33 \text{ m/s}} \approx 10.8 \text{ seconds}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Reference Frame
Understanding the concept of a reference frame is fundamental in physics, particularly when analyzing motion. A reference frame, simply put, is a viewpoint held by an observer as they watch an object's movement. This is like imagining yourself looking at the world through different glasses, each giving a unique view of the same situation. In the context of the exercise, the truck serves as a reference frame.

When you view speed or motion relative to the truck, you are essentially measuring how fast or slow the object (in this case, the automobile) appears from the truck's perspective. This approach allows us to have a clear sense of how two objects move in relation to each other. In situations where multiple objects are moving, choosing different reference frames can simplify calculations significantly, giving clarity to how movements compare.
Relative Speed
Relative speed is a crucial concept when studying motion between two objects. In simple terms, it tells us how fast one object is moving compared to another. To find this, you subtract the speed of one object from the speed of the other.

In this exercise, you are moving at 90 km/h, and the truck moves at 60 km/h. Thus, the relative speed of your car with respect to the truck is 30 km/h. This means that from the truck's viewpoint, you seem to be moving away at 30 km/h.

Typically, speeds are given in kilometers per hour (km/h) or meters per second (m/s). Transforming the units to suit the context (like meters per second when dealing with distances in meters) helps make calculations more straightforward. The conversion can be done using the factor: 1 km/h is approximately 0.27778 m/s.
Passing Time Calculation
Passing time calculation involves determining how long it takes for one object to completely overtake another. This requires understanding both the relative speed and the total distance involved in overtaking.

Let us break down the task. Here, you are 40 meters behind the truck and wish to end up 40 meters ahead of it, passing its 10 meters of length in the process. Thus, the total passing distance becomes 40 meters + 10 meters + 40 meters, equaling 90 meters.
  • Total Distance to cover while passing: 90 meters.
  • Relative Speed: 8.33 m/s (which we calculated by converting 30 km/h).
The time to pass the truck can be calculated using the formula: \(\text{Time} = \frac{\text{Distance}}{\text{Speed}}\). By applying this, we find: \(\text{Time} = \frac{90 \text{ m}}{8.33 \text{ m/s}} \approx 10.8\) seconds.

This shows that, within just under 11 seconds, you would successfully pass the truck while moving at your relative speed in its reference frame.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An automohile with a drualcen driver at the wheel travelu round and round a traffic circlc at \(30 \mathrm{~km} / \mathrm{h}\). The automobile talues 80 s to go once around the circle. At \(t=0\), the automobile is at the east of the truffic circle; at \(t=20 \mathrm{kit}\) is at the north; at \(t=40 \mathrm{~s}\) it is at the west, cte. What are the components of the velocity of the automohile at \(t=0, t=10\) s, \(t=\) \(20 \mathrm{~s}, t=30 \mathrm{~s}_{1}\) and \(\ell=40 \mathrm{~m}\) The \(\mathrm{Naxis}\) pointy castwand and the y axis points northward.

A hattelebip steming at \(45 \mathrm{~km} / \mathrm{h}\) fires u gun at right angles to the longitudinal axis of the ship. The cicvation angle of the gun is \(30^{\prime}\), and the muzde velncity of the shot is \(720 \mathrm{~m} / \mathrm{s}\) the gravitational acccieration in \(9.8 \mathrm{~m} / \mathrm{s}^{2}\), What is the range of thin abot in therefcrence frame of the grocnd? Prctend that there is no air retistaroc.

'Two foothall players are initially \(15 \mathrm{~m}\) apart. The firot player (a rerciver) runn perpendicular to the line joining the two players at a contant ipeed of \(8.0 \mathrm{~m} / \mathrm{s}\). Affer two ticconds, the wecond player (the quarterback) thrims the hall with a horimontal omponcnt vclocity of \(20 \mathrm{~m} / \mathrm{s}\). In what hotizontal directicn and with what vertical launch ungle should the quarterback throw so that the hull reaches the same -pot the receivcr will be? At what time will the ball be caught?

An audio compuct didk (CD) player is rotating at an anguilar velocity of \(32.5\) radians per second when playing a tracle at a radius of \(4.0 \mathrm{~cm}\). What is the finear speed at that radius? What is the rotation rate in revolutions per minute?

With itr engine cut oft, a matl airplane plidcs dowmward at an angle of \(15^{\circ}\) below the horixontal at a ppecd of \(240 \mathrm{lcm} / \mathrm{h}\). (a) What are the horizontal and the vertical cotnponents of its velocity? (b) If the airylanc is initially at a height of \(2000 \mathrm{~m}\) above the ground, how long does it take to crash into the ground?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.