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Fill in the Blanks. velocity When a car moves with constant velocity, its average velocity is equal to its velocity.

Short Answer

Expert verified
Question: When a car moves with constant velocity, its average velocity is equal to its __________. Answer: constant velocity

Step by step solution

01

Understand Constant Velocity

Constant velocity means that an object is moving at a steady speed in a straight line. In this case, there is no change in the object's speed or direction, meaning there is no acceleration.
02

Understand Average Velocity

The average velocity of an object is defined as the total displacement divided by the total time taken. In mathematical terms: Average Velocity = (Final Position - Initial Position) / Total Time.
03

Fill in the Blanks

Since the car is moving with constant velocity (steady speed and in a straight line), its average velocity over time would also be the same as its constant velocity. So, we can complete the given statement as: When a car moves with constant velocity, its average velocity is equal to its (constant) velocity.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Average Velocity
Average velocity is a measure that describes the overall rate of change of an object's position. To understand average velocity, it's crucial to differentiate it from average speed. While speed simply tells you how fast an object is moving, velocity specifies both the rate and the direction of movement.

In mathematical terms, average velocity (\( \bar{v} \)) is calculated using the formula: \[ \bar{v} = \frac{\Delta x}{\Delta t} \] where \( \Delta x \) is the displacement (the change in position), and \( \Delta t \) is the total time taken for that change. Because velocity is a vector quantity, if an object returns to its starting point, its average velocity is zero, regardless of the actual path traveled.

In the context of the exercise, when a car moves with constant velocity, there are no variations in speed or direction, so the average velocity over any time period remains equal to its instantaneous velocity at any point in that period.
Speed and Velocity
Speed and velocity are two fundamental concepts used to describe motion. Speed refers to how fast an object is moving, while velocity gives this information along with the direction of the motion. This is why speed is a scalar quantity — it has magnitude only. Velocity, on the other hand, is a vector quantity — it has both magnitude and direction.

The speed of an object is calculated without regard to its direction of travel. It's the rate at which an object covers distance and is expressed as the distance traveled per unit of time, typically using the formula: \[ speed = \frac{distance}{time} \] Velocity, as discussed earlier, incorporates direction, and thus its calculation involves displacement instead of distance. The difference is critical: displacement is the shortest path between two points, while distance is the total path traveled.
Displacement
Displacement is a vector quantity that denotes an object's overall change in position. Unlike distance, which is a scalar quantity that tells how much ground an object has covered, displacement measures the shortest path from an object's initial position to its final position, taking into account the direction of travel.

In formulaic terms, displacement (\( \Delta x \)) is given by: \[ \Delta x = x_{final} - x_{initial} \] where \( x_{final} \) and \( x_{initial} \) are the final and initial positions, respectively. An essential aspect of displacement is that it can be zero even if the object has traveled a long distance — as long as the start and end points are the same.
Motion in a Straight Line
Motion in a straight line, often referred to as rectilinear motion, occurs when an object moves along a straight path without changing its direction. This type of motion simplifies the study of kinematics as it involves only one dimension.

For an object moving at constant velocity in a straight line, several properties are consistently true:
  • The object's speed doesn't change — there's no acceleration.
  • Displacement over any given time period can be easily calculated by multiplying the speed by the time.
  • The object's average velocity and instantaneous velocity are the same at any given point in time.
In the constant velocity scenario provided in the exercise, understanding motion in a straight line is crucial, as it implies that no forces are causing acceleration or deceleration in any direction, making the calculation of average velocity straightforward.

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Most popular questions from this chapter

Consider a body moving with initial velocity u. Let its velocity change to \(\mathrm{v}\), in time ' \(\mathrm{t}^{\prime}\). Then, the change in velocity is \(=\mathrm{v}-\mathrm{u}\). The change in velocity per unit time \(=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}}\) By definition, the change in velocity per unit time is acceleration, a. Thus, \(\mathrm{a}=\frac{\mathrm{v}-\mathrm{u}}{\mathrm{t}}\) or \(\mathrm{v}-\mathrm{u}=\) at \(\mathrm{v}=\mathrm{u}+\mathrm{at}\)

The rest and motion are relative. An object at rest with respect to one observer may not be at rest with respect to another observer. The same can be said about motion. For a person inside a bus, the fellow passengers are at rest but the same passengers are in motion with respect to a person standing on the ground.

The rate of change of velocity is acceleration.

Speed \(=\frac{\text { Distance travelled }}{\text { Time taken }}\) \(\Rightarrow\) distance travelled by the body \(=\) speed of the body \(\times\) time taken.

Let the distance travelled by car with \(42 \mathrm{~km} \mathrm{~h}^{-1}\) for 20 minutes be \(\mathrm{S}\), and distance travelled with 60 \(\mathrm{km} \mathrm{h}^{-1}\) for 30 minutes be \(\mathrm{S}_{2}\) \(\Rightarrow \mathrm{S}_{1}=42 \mathrm{~km} \mathrm{~h}^{-1} \times \frac{1}{3} \mathrm{~h}=14 \mathrm{~km}\) \(\Rightarrow \mathrm{S}_{2}=60 \mathrm{~km} \mathrm{~h}^{-1} \times \frac{1}{2} \mathrm{~h}=30 \mathrm{~km}\) Total distance \(\mathrm{S}=\mathrm{S}_{1}+\mathrm{S}_{2}=14+30=44 \mathrm{~km}\)

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