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An aircraft carrier is moving to the north at a constant 25 mph on a windless day. A plane requires a speed relative to the air of 125 mph to take off. How fast must the plane be traveling relative to the deck of the aircraft carrier to take off if the plane is headed (a) north? (b) South?

Short Answer

Expert verified
The plane must travel at 100 mph relative to the deck when heading north and 150 mph when heading south.

Step by step solution

01

Understand the problem

Determine the required speed of the plane relative to the air, which is 125 mph. The carrier is moving north at 25 mph.
02

Determine speed relative to the deck when heading north

When the plane heads north, the speed of the plane relative to the air is the sum of the speed of the plane relative to the deck and the speed of the carrier. Therefore, the equation is: \[ v_p = v_d + v_c \]Substitute the known values: \[ 125 = v_d + 25 \]Solve for the speed relative to the deck, \( v_d \): \[ v_d = 125 - 25 \]\[ v_d = 100 \text{ mph} \]
03

Determine speed relative to the deck when heading south

When the plane heads south, the speed of the plane relative to the air is the difference between the speed of the plane relative to the deck and the speed of the carrier. Therefore, the equation is: \[ v_p = v_d - v_c \]Substitute the known values: \[ 125 = v_d - 25 \]Solve for the speed relative to the deck, \( v_d \): \[ v_d = 125 + 25 \]\[ v_d = 150 \text{ mph} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Velocity Addition
Velocity addition is a key concept in relative motion. It involves combining velocities from different reference frames to understand the overall motion. For example, if an aircraft carrier is moving north at 25 mph, and a plane needs to reach 125 mph relative to the air to take off, how fast should it go relative to the deck? When heading north, the plane's speed includes both its speed relative to the deck and the carrier's speed. The relationship can be written as: v_p = v_d + v_c where \( v_p \) is the plane's required velocity (125 mph), \( v_d \) is the velocity relative to the deck, and \( v_c \) is the carrier's velocity (25 mph). Solving this equation gives the plane's speed relative to the deck as 100 mph.
Relative Speed
Relative speed is the speed of an object as observed from another moving object. It is critical in problems involving motion from different perspectives. In our example, if the plane heads south against the carrier's northward motion, the relative speed becomes the difference between the plane's required speed and the carrier's speed. The equation is: v_p = v_d - v_c Given \( v_p \) is still 125 mph, and \( v_c \) is 25 mph, solving for \( v_d \) gives the relative speed of the plane to be 150 mph. This difference highlights how speeds can vary depending on the reference frame.
Aircraft Carrier Dynamics
Understanding aircraft carrier dynamics helps answer questions like how an aircraft takes off from a moving platform. Here, the carrier moves at 25 mph north. The plane needs 125 mph relative to the air to take off. Therefore, when heading north, the plane's ground speed must account for the carrier's motion. It reaches the needed airspeed by combining its deck speed (100 mph) with the carrier's speed. Conversely, when heading in the opposite direction (south), the plane has to work against the carrier's northward motion, resulting in a higher required deck speed of 150 mph to achieve the same airspeed.
Problem-Solving in Physics
Problem-solving in physics often involves breaking down complex scenarios into simpler steps. Start by understanding the problem's requirements. Here, the plane needs 125 mph to take off, and the carrier moves at 25 mph. Then use known equations for relative motion to find unknowns. For northward motion: v_p = v_d + v_c Solving for \( v_d \), we find it must be 100 mph. For southward motion: v_p = v_d - v_c Solving for \( v_d \), it's 150 mph. Practice these steps for a clear comprehension of motion principles.

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