/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 51 Would a Foucault pendulum rotate... [FREE SOLUTION] | 91Ó°ÊÓ

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Would a Foucault pendulum rotate at the equator? Explain your reasoning.

Short Answer

Expert verified
No, a Foucault pendulum would not rotate at the equator because the precession rate is zero.

Step by step solution

01

Understand the Foucault Pendulum

A Foucault pendulum is a simple device named after French physicist Léon Foucault. It demonstrates the rotation of the Earth. As the pendulum swings back and forth, its plane of oscillation appears to rotate relative to the surface of the Earth.
02

Effect of Earth's Rotation

The rotation of the Earth causes the pendulum's plane to precess (rotate). The rate of this precession depends on the latitude of the pendulum.
03

Latitude and Precession

The precession rate of a Foucault pendulum is given by the equation \(\text{Precession Rate} = \text{Angular Speed of Earth} \times \text{sin(latitude)}\). This means that the precession rate depends on the sine of the latitude.
04

Condition at the Equator

At the equator, the latitude is 0 degrees. Substituting this into the precession rate formula: \(\text{Precession Rate} = \text{Earth's Angular Speed} \times \text{sin}(0)\). Since \(\text{sin}(0) = 0\), the precession rate becomes zero.
05

Conclusion

Given that the precession rate is zero at the equator, a Foucault pendulum placed at the equator would not exhibit any rotational movement of its plane of oscillation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Earth's rotation
The Foucault pendulum showcases one of the most intriguing phenomena associated with Earth's rotation. As Earth rotates on its axis, this rotation influences the motion of the pendulum's swing. When the pendulum is suspended and set into motion, it swings back and forth in a plane. However, due to the rotation of the Earth, this plane of oscillation appears to rotate relative to the ground beneath it. This observed motion serves as evidence that the Earth rotates on its axis.

Since the pendulum is not fixed to the Earth but rather moves in a consistent direction in space (inertia), the surface below it moves due to Earth's rotation. This is why to an observer on Earth, the pendulum's plane seems to turn, demonstrating the Earth’s continuous rotation.
Precession rate
The precession rate of a Foucault pendulum is a crucial measure that indicates how fast the plane of the pendulum's oscillation rotates due to Earth’s rotation. This is mathematically expressed as:

\[\text{Precession Rate} = \text{Angular Speed of Earth} \times \sin(\text{latitude})\]

The angular speed of Earth is a constant value, approximately 0.0000727 radians per second.

Using this formula, the precession rate provides the speed at which the plane of oscillation appears to turn at different locations on Earth. For example:
  • At the North Pole (latitude = 90 degrees), \(\text{sin}(90\text{°}) = 1\), so the precession rate matches Earth's angular speed.
  • At the equator (latitude = 0 degrees), \(\text{sin}(0\text{°}) = 0\), resulting in a precession rate of zero.
  • At mid-latitudes (e.g., 45 degrees), the precession rate is intermediate, calculated as \(\text{Angular Speed of Earth} \times \sin(45\text{°})\).
This formula shows that the precession rate depends on the geographic location, particularly the latitude.
Latitude effect
Latitude significantly impacts the motion of a Foucault pendulum. The latitude of a location is the angular distance from the equator, ranging from 0 degrees (equator) to 90 degrees (poles).

  • At the poles, the effect is most pronounced, with the pendulum demonstrating a full 360-degree precession per day, which means it completes a full rotation in 24 hours due to maximum sin value (sin(90°) = 1).
  • At the equator, there is no precession observed. This is because the precession rate formula includes the sine of the latitude. At 0 degrees latitude, \(\text{sin}(0\text{°}) = 0\), nullifying the precession rate. Hence, the plane of oscillation does not rotate.
  • At other latitudes, the precession rate increases proportionally with the sine of the latitude. This means the effect is more notable as one moves away from the equator.
Understanding this relationship helps clarify why a Foucault pendulum at the equator does not exhibit any rotational change in its plane of oscillation. The concept beautifully illustrates how geographical position affects physical phenomena due to Earth's rotation.

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