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A ground-based observer measures a rocket ship to have a length of \(60 \mathrm{m}\). If the rocket was traveling at \(50 \%\) of the speed of light when the measurement was made, what length would the rocket have if brought to rest?

Short Answer

Expert verified
Approximately 69.28 meters.

Step by step solution

01

Identify Given Data

The given data includes the measured length of the rocket, which is 60 m, and its speed, which is 50 % of the speed of light (c).
02

Recall Length Contraction Formula

Use the length contraction formula, which is \[ L = L_0 \times \sqrt{1 - \left(\frac{v}{c}\right)^2} \], where \(L\) is the contracted length, \(L_0\) is the proper length, \(v\) is the velocity of the moving object, and \(c\) is the speed of light.
03

Plug in the Values

Given that the contracted length \(L\) is 60 m and \(v = 0.5c\), substitute these values into the equation: \[ 60 = L_0 \sqrt{1 - \left(\frac{0.5c}{c}\right)^2} = L_0 \sqrt{1 - 0.25}\].
04

Solve for Proper Length

Simplify the equation to solve for \(L_0\): \[ 60 = L_0 \sqrt{0.75}\] Thus, \L_0 = \frac{60}{\sqrt{0.75}}.\ Calculate \(\sqrt{0.75}\) which is approximately 0.866. Therefore, \[ L_0 = \frac{60}{0.866} ≈ 69.28 \text{m} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

special relativity
Special relativity is a theory proposed by Albert Einstein that describes the physics of moving objects at high speeds, particularly those close to the speed of light. This theory revolutionized our understanding of space, time, and energy. One of the key ideas in special relativity is that the laws of physics are the same for all observers, regardless of their motion.
Another essential concept is that the speed of light, denoted as c, is constant and the same for all observers, no matter their velocity.
Special relativity has many fascinating effects, like time dilation, where time slows down for moving objects, and length contraction, where objects appear shorter in the direction of motion to a stationary observer.
proper length
The proper length, denoted as \(L_0\), is the length of an object measured in the object's rest frame. This means the measurement is taken when the object is not moving relative to the observer. Proper length is the true length because it isn't subject to effects like length contraction.
In the context of the given problem, when the rocket is brought to rest, the length measured (69.28 meters) is its proper length. It shows the actual dimensions of the rocket without the distortions caused by its high-speed travel.
Lorentz factor
The Lorentz factor, symbolized as \( \gamma \), is a crucial element of special relativity. It is defined as \[ \gamma = \frac{1}{\sqrt{1 - \left(\frac{v}{c}\right)^{2}}} \], where \(v \) is the velocity of the moving object and \(c \) is the speed of light. This factor accounts for the relativistic effects that become significant at high speeds.
For length contraction: \[ L = L_0 \times \frac{1}{\gamma} \] In our exercise, the rocket's speed is 0.5c, making the Lorentz factor approximately 1.155. Understanding this factor is essential for calculating effects like length contraction and time dilation.
speed of light
The speed of light, denoted as \(c\), is a fundamental constant of nature, valued at approximately 299,792,458 meters per second (m/s). It serves as the cosmic speed limit, meaning no object with mass can reach or exceed this speed. All electromagnetic waves, including light, travel at this speed in a vacuum.
In special relativity, the speed of light is crucial in forming the equations that describe relativistic effects. For instance, the rocket travels at 50% of the speed of light (0.5c), influencing how its length is perceived by a ground-based observer. This speed is a fundamental part of calculating the Lorentz factor and how much length contraction occurs.

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