/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 A rod is lying on the top of a t... [FREE SOLUTION] | 91Ó°ÊÓ

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A rod is lying on the top of a table. One end of the rod is hinged to the table so that the rod can rotate freely on the tabletop. Two forces, both parallel to the tabletop, act on the rod at the same place. One force is directed perpendicular to the rod and has a magnitude of 38.0 N. The second force has a magnitude of 55.0 N and is directed at an angle with respect to the rod. If the sum of the torques due to the two forces is zero, what must be the angle ?

Short Answer

Expert verified
The angle \( \theta \) is approximately 43.2 degrees.

Step by step solution

01

Understand Torque

Torque is the measure of the force that can cause an object to rotate around an axis. Torque depends on the force applied, the distance from the pivot (or axis of rotation), and the angle at which the force is applied. It's calculated as \[ \tau = rF \sin \theta \]where \( \tau \) is the torque, \( r \) is the distance from the pivot, \( F \) is the force applied, and \( \theta \) is the angle between the force vector and the lever arm.
02

Set Up Torque Equations

We have two forces acting on the rod leading to two torques: 1. Torque from the first force (38.0 N) is \( \tau_1 = r \cdot 38.0 \sin 90^\circ = r \cdot 38.0\). This is because the force is perpendicular to the rod. 2. Torque from the second force (55.0 N) is \( \tau_2 = r \cdot 55.0 \sin \theta \). Since the sum of the torques is zero, we have:\[ \tau_1 - \tau_2 = 0 \] which implies \[ r \cdot 38.0 - r \cdot 55.0 \sin \theta = 0 \]
03

Simplify the Equation

Since the distance \( r \) is the same and non-zero, it can be canceled from the equation, simplifying to:\[ 38.0 - 55.0 \sin \theta = 0 \]
04

Solve for the Angle

Rearrange the simplified equation to solve for \( \sin \theta \):\[ \sin \theta = \frac{38.0}{55.0} \]Now, calculate \( \theta \) using the inverse sine function:\[ \theta = \sin^{-1} \left( \frac{38.0}{55.0} \right) \]
05

Calculate \( \theta \)

Use a calculator to determine \( \theta = \sin^{-1} \left( \frac{38.0}{55.0} \right) \) which results in \( \theta \approx 43.2^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Dynamics
Rotational dynamics is the study of how objects rotate and the forces that cause these rotations. When a force is applied to an object at a distance from its center of rotation, it can cause the object to spin or rotate. This spinning motion is influenced by the magnitude of the force, the distance from the pivot point where the force is applied (also called the lever arm), and the angle at which the force is applied. This concept is crucial in understanding the behavior of rotating objects, like wheels or in our case, a hinged rod.
In the context of our exercise, the rod can rotate freely around one fixed end. The dynamics of how the rod rotates depend on how forces are applied to it. By understanding rotational dynamics, we can calculate the angle needed for two forces to keep the rod balanced so that it does not rotate.
Force Vectors
Force vectors are quantities that have both magnitude and direction. In physics, they are used to represent forces acting on an object. The direction of the vector is important because it determines the way the force affects the object's motion or rotation. Forces can be decomposed into components, often using trigonometry, to better analyze the effect each force will have on the system.
In the original problem, we have two forces acting on the rod. One force is perpendicular with a magnitude of 38.0 N, meaning it acts straight across the rod. The other force is 55.0 N, but it acts at an angle relative to the rod. By understanding these vector qualities, we can determine the resultant torque and how these forces interact to maintain equilibrium.
Equilibrium
Equilibrium occurs when all the forces and torques acting on an object are balanced, meaning the object is in a state of rest or moves with constant velocity. In rotational dynamics, this involves the sum of all torques—the rotational counterparts of forces—being zero. If the torques acting on an object cancel each other out, the object won't spin or rotate.
For the rod problem, the condition for equilibrium is that the sum of the torques due to the two forces is zero. By setting the torques to cancel each other—one torque positive and the other negative—we ensure that the rod remains in a stable, non-rotating condition.
Angle Calculation
Angle calculation involves using mathematical tools to determine the precise angles at which forces must act for stability or any desired movement. Often, this involves trigonometric functions like sine, cosine, or tangent, especially when dealing with forces acting at angles.
In the exercise, after setting up the torque equilibrium equation and simplifying, we find that:
  • The sine function is used to resolve the second force at an angle into a component that contributes to torque.
  • We solve for the angle using the inverse sine function: \[\theta = \sin^{-1}\left(\frac{38.0}{55.0}\right)\]
  • Calculating this gives the necessary angle \(\theta\) for equilibrium, which is approximately 43.2 degrees.
Understanding and applying these calculations are key to solving problems involving forces at angles and maintaining equilibrium in rotational dynamics.

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Most popular questions from this chapter

A solid cylindrical disk has a radius of 0.15 m. It is mounted to an axle that is perpendicular to the circular end of the disk at its center. When a 45-N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 120 \(\mathrm{rad} / \mathrm{s}^{2} .\) What is the mass of the disk?

A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 438 N and have a center of gravity that is 1.28 m above the floor. His upper legs weigh 144 N and have a center of gravity that is 0.760 m above the floor. Finally, his lower legs and feet together weigh 87 N and have a center of gravity that is 0.250 m above the floor. Relative to the floor, find the location of the center of gravity for his entire body.

A uniform board is leaning against a smooth vertical wall. The board is at an angle above the horizontal ground. The coefficient of static friction between the ground and the lower end of the board is 0.650. Find the smallest value for the angle , such that the lower end of the board does not slide along the ground.

Starting from rest, a basketball rolls from the top of a hill to the bottom, reaching a translational speed of 6.6 m/s. Ignore frictional losses. (a) What is the height of the hill? (b) Released from rest at the same height, a can of frozen juice rolls to the bottom of the same hill. What is the translational speed of the frozen juice can when it reaches the bottom?

Two thin rectangular sheets (0.20 m 0.40 m) are identical. In the first sheet the axis of rotation lies along the 0.20-m side, and in the second it lies along the 0.40-m side. The same torque is applied to each sheet. The first sheet, starting from rest, reaches its final angular velocity in 8.0 s. How long does it take for the second sheet, starting from rest, to reach the same angular velocity?

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