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A thin, rigid, uniform rod has a mass of 2.00 kg and a length of 2.00 m. (a) Find the moment of inertia of the rod relative to an axis that is perpendicular to the rod at one end. (b) Suppose all the mass of the rod were located at a single point. Determine the perpendicular distance of this point from the axis in part (a), such that this point particle has the same moment of inertia as the rod does. This distance is called the radius of gyration of the rod.

Short Answer

Expert verified
(a) The moment of inertia of the rod is 2.67 kg⋅m². (b) The radius of gyration is approximately 1.16 m.

Step by step solution

01

Understanding the Moment of Inertia

The moment of inertia (I) is a measure of an object's resistance to changes in its rotation around an axis. For a rod of mass M and length L, the formula for the moment of inertia about an axis perpendicular to the rod at one end is given by: \[ I = \frac{1}{3} M L^2 \]
02

Substitute Values into the Formula

Substitute the given mass (M = 2.00 kg) and length (L = 2.00 m) into the formula:\[ I = \frac{1}{3} \times 2.00 \times (2.00)^2 \] Simplifying this expression gives:\[ I = \frac{1}{3} \times 2.00 \times 4.00 = \frac{8.00}{3} \approx 2.67 \, \text{kg}\cdot\text{m}^2 \]
03

Calculate the Radius of Gyration

The radius of gyration (k) is the distance from the axis at which point all of the mass of the body can be considered to be concentrated to produce the same moment of inertia as the actual distribution of mass. The formula to calculate radius of gyration is: \[ I = M k^2 \] Rearranging for k, we have: \[ k = \sqrt{\frac{I}{M}} \]
04

Substitute Values to Find Radius of Gyration

Use the moment of inertia calculated in Step 2 (\( I = 2.67 \, \text{kg}\cdot\text{m}^2 \)) and the mass (M = 2.00 kg) to find k:\[ k = \sqrt{\frac{2.67}{2.00}} \] \[ k = \sqrt{1.335} \approx 1.16 \, \text{m} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radius of gyration
The radius of gyration is a concept that helps us understand how mass is distributed in a rotating body. Imagine if the entire mass of an object were concentrated at a single point. The radius of gyration is the distance from the axis at which this concentrated mass would have the same moment of inertia as the actual object. This simplifies complex mass distributions into an easier form for calculation. We can think of it like this:
  • It partly represents the distribution of mass around the axis. A larger radius of gyration means the mass is more spread out.
  • This concept helps in understanding and calculating the rotational dynamics of objects more easily.
To find the radius of gyration, you can use the formula:\[ k = \sqrt{\frac{I}{M}} \]Here, \( I \) is the moment of inertia and \( M \) is the mass. By using this formula, we translate a distributed mass into a point mass that effectively behaves the same in terms of rotational resistance.
Rigid body dynamics
Rigid body dynamics explores how objects move when forces and torques are applied. In this discipline, we do not consider any deformation in the body, assuming it remains entirely solid during motion. This approximation simplifies the analysis of rotational motion, particularly for objects like the uniform rod. When studying rigid bodies, keep these ideas in mind:
  • The object's shape does not change. All the distances between any two given points on it remain the same throughout motion.
  • It is crucial in engineering and physics due to its practical applications in system mechanics.
In rigid body dynamics, the concepts of torque and moment of inertia become vital. Torque acts as a force into this rotating motion, and moment of inertia is the measure of how much the body resists angular acceleration. Together, they tell us how objects like a rod move and react in rotational systems.
Rotational motion
Rotational motion is a type of motion where an object spins around a specific line known as the axis of rotation. For the uniform rod, when determining its moment of inertia, we consider its motion about an axis at one end. Key elements of rotational motion you need to understand include:
  • Angular velocity, which describes how fast an object rotates.
  • Angular acceleration, which measures how the rotation speed changes over time.
  • Moment of inertia, which gives insights into how the mass is distributed relative to the axis.
This type of motion can be found everywhere, from wheels and planets to simple machines like the rod. Besides, it greatly simplifies complex linear motions where each part of the object could be moving differently across the axis. Understanding rotational motion helps in designing and analyzing mechanical systems where movement around a pivot point or axis is crucial.
Uniform rod
A uniform rod is characterized by having a constant mass distribution throughout its length, meaning every segment of the rod weighs the same. This makes it easier to calculate properties like center of mass and moment of inertia. When looking at a uniform rod:
  • The mass is evenly distributed, so calculations involving mass distribution become straightforward.
  • The rod's geometric properties simplify the analysis of various motion and force dynamics placed upon it.
Considering its applications, uniform rods are fundamental in many structural and mechanical designs. For instance, in the calculation of the moment of inertia, knowing the rod is uniform allows us to use specific formulas to find the moment of inertia with respect to rotational movements around different axes.

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Most popular questions from this chapter

The steering wheel of a car has a radius of 0.19 m, and the steering wheel of a truck has a radius of 0.25 m. The same force is applied in the same direction to each steering wheel. What is the ratio of the torque produced by this force in the truck to the torque produced in the car?

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A uniform board is leaning against a smooth vertical wall. The board is at an angle above the horizontal ground. The coefficient of static friction between the ground and the lower end of the board is 0.650. Find the smallest value for the angle , such that the lower end of the board does not slide along the ground.

Two disks are rotating about the same axis. Disk A has a moment of inertia of 3.4 \(\mathrm{kg} \cdot \mathrm{m}^{2}\) and an angular velocity of \(+7.2 \mathrm{rad} / \mathrm{s}\) . Disk \(\mathrm{B}\) is rotating with an angular velocity of \(-9.8 \mathrm{rad} / \mathrm{s}\) . The two disks are then linked together without the aid of any external torques, so that they rotate as a single unit with an angular velocity of \(-2.4 \mathrm{rad} / \mathrm{s}\) . The axis of rotation for this unit is the same as that for the separate disks. What is the moment of inertia of disk \(\mathrm{B} ?\)

A clay vase on a potter's wheel experiences an angular acceleration of 8.00 \(\mathrm{rad} / \mathrm{s}^{2}\) due to the application of a \(10.0-\mathrm{N} \cdot \mathrm{m}\) net torque. Find the total moment of inertia of the vase and potter's wheel.

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