/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 75 A quarterback throws a pass that... [FREE SOLUTION] | 91Ó°ÊÓ

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A quarterback throws a pass that is a perfect spiral. In other words, the football does not wobble, but spins smoothly about an axis passing through cach end of the ball. Suppose the ball spins at \(7,7 \mathrm{rev} / \mathrm{s}\). In addition, the ball is thrown with a linear speed of \(19 \mathrm{~m} / \mathrm{s}\) at an angle of \(55^{\circ}\) with respect to the ground. If the ball is caught at the same height at which it left the quarterback's hand, how many revolutions has the ball made while in the air?

Short Answer

Expert verified
The ball makes approximately 24.49 revolutions.

Step by step solution

01

Find Time of Flight

The ball is thrown at a speed of \(19 \text{ m/s}\) at an angle of \(55^\circ\). To find the time of flight, we first calculate the vertical component of the initial velocity. This is done using \(v_{y} = v \cdot \sin(\theta)\), which gives:\[ v_{y} = 19 \cdot \sin(55^\circ) \approx 15.57 \text{ m/s} \]Since the ball is caught at the same height, the time up equals the time down. The total time of flight \(T\) is given by:\[ T = \frac{2v_{y}}{g} = \frac{2 \times 15.57}{9.8} \approx 3.18 \text{ seconds} \]
02

Calculate Total Revolutions

The football spins at a rate of \(7.7 \text{ rev/s}\). To determine the total number of revolutions during the time of flight, multiply the rotation rate by the time:\[ \text{Total revolutions} = 7.7 \times 3.18 \approx 24.49 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rotational Kinematics
Rotational kinematics is the branch of physics that deals with the motion of objects that rotate about an axis. In our exercise, the football rotates smoothly without any wobbling, which means it's in perfect rotational motion. Think about how you spin a top; the spin without wobbling is similar to what happens with the football.
To delve deeper, consider that any rotating object will have several key parameters such as angular displacement, angular velocity, and angular acceleration. For the football, we are primarily interested in its angular velocity, or how fast it spins. It's crucial to differentiate between the linear motion (like the ball being thrown) and the rotational motion (the ball spinning about its axis).
The study of rotational kinematics helps us understand phenomena such as gyroscopic stability, which is why the football can maintain its spin with a definite orientation during its flight.
Angular Velocity
Angular velocity refers to how fast an object spins around its axis. In the context of our spinning football, the angular velocity is given as 7.7 revolutions per second. This rate tells us how many complete rotations the ball does in a second.
In calculations, we can use the formula for angular velocity, which is often denoted as \( \omega \). It is the change in angular displacement per unit of time. For the football, we are focusing on the number of revolutions it makes while in the air which is directly influenced by its angular velocity.
Another interesting thing to note is the conversion between revolutions per second to radians per second because 1 revolution equals \( 2\pi \) radians. Understanding angular velocity is key to calculating how objects rotate over time.
Time of Flight
The time of flight in projectile motion is the total time an object is in the air from launch until it lands. In our example, we found that the football remains in the air for approximately 3.18 seconds. This is calculated by examining the vertical component of the initial velocity.
To find this, we considered the projectile motion equations. Specifically, the vertical component is used because it affects the time the football is airborne. The upward and downward journey times are equal only if the starting and ending heights are the same.
Remember, for projects launched at an angle, breaking the velocity into vertical and horizontal components helps in understanding how long and how far an object will travel.
Vertical Component of Velocity
The vertical component of velocity is crucial in determining the projectile’s behavior in the air. For the football, we calculated it using the formula \( v_{y} = v \cdot \sin(\theta) \), where \( v \) is the initial velocity and \( \theta \) is the launch angle.
The vertical component tells us how fast the object is moving up or down. In our problem, we found it to be approximately 15.57 m/s. This initial vertical speed determines how high and quickly the object will rise or fall.
  • The higher this component, the longer the object spends in the air.
  • Gravity acts to decrease this speed, eventually reversing it.
Breaking velocity into components allows us to solve complex projectile problems by analyzing vertical and horizontal motions separately.

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Most popular questions from this chapter

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