/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 39 The take-up reel of a cassette t... [FREE SOLUTION] | 91Ó°ÊÓ

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The take-up reel of a cassette tape has an average radius of 1.4 cm. Find the length of tape (in meters) that passes around the reel in 13 s when the reel rotates at an average angular speed of 3.4 rad/s.

Short Answer

Expert verified
0.6188 meters.

Step by step solution

01

Understand the Problem

We are given an average angular speed of 3.4 rad/s and the radius of the reel as 1.4 cm. We need to find the length of tape that passes around the reel in 13 seconds.
02

Calculate Angular Distance

To find the angular distance, multiply the angular speed by the time. This gives the total angle in radians that the reel turns through in 13 seconds:\[\text{Angular Distance} = \text{Angular Speed} \times \text{Time} = 3.4 \, \text{rad/s} \times 13 \, \text{s}\]Calculate the result to get the angular distance.
03

Convert Angular Distance to Linear Distance

Linear distance is found by multiplying the angular distance by the radius of the reel. Using the formula:\[\text{Linear Distance} = \text{Angular Distance} \times \text{Radius}\]Convert the radius from cm to meters by dividing by 100, then substitute the values to get the linear distance in meters.
04

Perform the Calculations

Now, let's perform the calculations:\[\text{Angular Distance} = 3.4 \, \text{rad/s} \times 13 \, \text{s} = 44.2 \, \text{radians}\]Convert the radius: \(1.4 \, \text{cm} = 0.014 \, \text{m}\)Finally, calculate the linear distance:\[\text{Linear Distance} = 44.2 \, \text{rad} \times 0.014 \, \text{m} = 0.6188 \, \text{m}\]
05

Conclusion

The length of tape that passes around the reel in 13 seconds is 0.6188 meters.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angular Speed
Angular speed is a crucial concept in rotational motion and physics problems involving objects that rotate. It measures how fast an object spins around a central point, and is generally expressed in radians per second (rad/s). To visualize this, imagine how quickly a disc spins, turning through an angle of one radian in one second. Angular speed thus describes how much angular displacement occurs in a given period of time.

The calculation for angular speed involves dividing the change in the rotational angle of an object by the time taken to make that rotation:
  • Formula: Angular Speed (\( \omega \)) = Angular Displacement / Time
  • Units: Radians per second (rad/s)
  • Symbol: \( \omega \)
Understanding angular speed is vital for solving problems where rotational motion is involved, as it helps link rotational and linear distances simply through the radius. By mastering this concept, you'll be able to efficiently convert between angular and linear quantifications of motion.
Linear Distance
Linear distance describes the path covered by a point on the circumference of a rotating object. It provides a direct measure of "how far" in space the object has traveled as a result of its rotational movement. This is particularly important for understanding the relationship between rotation and translation.
  • The general formula relating linear distance to angular distance is:\[ \text{Linear Distance} = \text{Angular Distance} \times \text{Radius} \]
  • Ensure units are consistent - typically, convert all measurements to meters first.
  • Linear distance is measured in meters (m).
When solving problems, it's important to first determine the angular distance (in radians), then multiply by the radius (in meters) to find how far the point on the outside of the rotating object travels. This concept links angular motion to real-world distances in physics problems, showing the practical implications of circular movement.
Problem Solving in Physics
Problem solving in physics often involves a systematic approach to break down a complex question into manageable steps. The process requires understanding the problem, identifying known quantities, and finding relationships between them.
  • Understand the Problem: Always start by carefully reading the question to grasp what is asked. Identify all given values and what needs to be found.
  • Apply Relevant Formulas: Once you know the variables, use the appropriate formulas. Like in this case, using formulas for angular speed and linear distance conversion.
  • Convert Units: Ensure all values are in the correct units before performing any calculations. In this problem, converting the radius from centimeters to meters was crucial.
  • Calculate & Conclude: Perform calculations carefully, double-check figures, and derive the final answer. Provide a conclusion that clearly answers the original question.
By following these steps, physics students can solve problems accurately and efficiently, enhancing their understanding and ability to tackle more advanced concepts with confidence.

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Most popular questions from this chapter

A child, hunting for his favorite wooden horse, is running on the ground around the edge of a stationary merry-go-round. The angular speed of the child has a constant valuc of 0.250 \(\mathrm{rad} / \mathrm{s}\) . At the instant the child spots the horse, onc-quarter of a turn away, the merry-go-round begins to move (in the direction the child is runing) with a constant angular acceleration of 0.0100 \(\mathrm{rad} / \mathrm{s}^{2}\) . What is the shortest time it takes for the child to catch up with the horse?

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A racing car, starting from rest, travels around a circular turn of radius 23.5 m. At a certain instant, the car is still accelerating, and its angular speed is 0.571 rad/s. At this time, the total acceleration (centripetal plus tangential) makes an angle of 35.0 with respect to the radius. (The situation is similar to that in Figure 8.12b.) What is the magnitude of the total acceleration?

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One type of slingshot can be made from a length of rope and a leather pocket for holding the stone. The stone can be thrown by whirling it rap- idly in a horizontal circle and releasing it at the right moment. Such a slingshot is used to throw a stone from the edge of a cliff, the point of release being 20.0 m above the base of the cliff. The stone lands on the ground below the cliff at a point X. The horizontal distance of point X from the base of the cliff (directly beneath the point of release) is thirty times the radius of the circle on which the stone is whirled. Determine the angular speed of the stone at the moment of release

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