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Two stars in a binary system orbit around their center of mass. The centers of the two stars are \(7.17 \times 10^{11} \mathrm{m}\) apart. The larger of the two stars has a mass of \(3.70 \times 10^{30} \mathrm{kg},\) and its center is \(2.08 \times 10^{11} \mathrm{m}\) from the system's center of mass. What is the mass of the smaller star?

Short Answer

Expert verified
The mass of the smaller star is approximately \(1.51 \times 10^{30} \mathrm{kg}\).

Step by step solution

01

Understanding the Problem

We have two stars orbiting their common center of mass. We are given the distance between their centers, the mass of the larger star, and its distance from the center of mass. We need to find the mass of the smaller star.
02

Apply the Center of Mass Formula

The formula for the center of mass for two objects is \( M_1 \cdot d_1 = M_2 \cdot d_2 \), where \( M_1 \) and \( M_2 \) are the masses of the two objects, and \( d_1 \) and \( d_2 \) are their respective distances from the center of mass. Let the mass of the smaller star be \( M_2 \) and its distance from the center of mass be \( d_2 = 7.17 \times 10^{11} \mathrm{m} - 2.08 \times 10^{11} \mathrm{m} \).
03

Substitute Known Values

Plug in the known values into the center of mass equation: \( 3.70 \times 10^{30} \mathrm{kg} \times 2.08 \times 10^{11} \mathrm{m} = M_2 \times (7.17 \times 10^{11} \mathrm{m} - 2.08 \times 10^{11} \mathrm{m}) \).
04

Solve for Unknown Mass

Calculate the distance \( d_2 \): \( d_2 = 7.17 \times 10^{11} \mathrm{m} - 2.08 \times 10^{11} \mathrm{m} = 5.09 \times 10^{11} \mathrm{m} \). Then, solve for \( M_2 \): \[ M_2 = \frac{3.70 \times 10^{30} \times 2.08 \times 10^{11}}{5.09 \times 10^{11}} \].
05

Calculate Final Mass

Perform the calculation: \( M_2 = \frac{3.70 \times 10^{30} \times 2.08}{5.09} \). This simplifies to \( M_2 \approx 1.51 \times 10^{30} \mathrm{kg} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Center of Mass Calculation
In a binary star system, two stars orbit around a common point known as the center of mass. This point is crucial, because it represents the balance point of the two-star system based on their masses and distances. Imagine it as a seesaw balancing between two children; each child needs to weigh the same relative to their distance to keep the seesaw balanced. For stars, the center of mass is calculated using the formula:
  • \( M_1 \cdot d_1 = M_2 \cdot d_2 \)
where:
  • \( M_1 \) and \( M_2 \) are the masses of the two stars
  • \( d_1 \) and \( d_2 \) are their respective distances from the center of mass
This formula shows that the heavier mass is closer to the center of mass. By rearranging it, you can solve for an unknown—like finding the mass of a smaller star when the distance and mass of the larger star and the distance between them are known. This calculation is vital in understanding how two stars influence each other gravitationally.
Masses of Stars
The mass of a star is the amount of matter it contains and is typically measured in kilograms. In astrophysics, knowing the mass of stars is vital for understanding their life cycles, luminosity, and the gravitational forces they exert. In our binary star problem, we know the mass of the larger star as \(3.70 \times 10^{30} \mathrm{kg}\), which is a typical mass for a star.
To find the mass of the smaller star, we used the binary center of mass formula. Having calculated the distance \(d_2\) of the smaller star from the center of mass, the equation \( M_1 \times d_1 = M_2 \times d_2 \) allows us to rearrange it to solve for \( M_2 \). With enough information on the distances involved, calculating the mass becomes a straightforward arithmetic exercise. Knowing these physical properties can help astronomers classify the stars and predict their behavior over time.
Orbital Mechanics
Orbital mechanics involves the principles governing the motion of celestial bodies in space. In a binary star system, the two stars follow elliptical orbits around their collective center of mass, adhering to Kepler's Laws. The laws describe how the stars will move faster when they are closer and slower when they are further from each other.
Key elements of orbital mechanics include:
  • Gravitational Forces: Both stars exert gravitational pulls on one another, creating a delicate balance where they orbit the center of mass.
  • Angular Momentum: A conserved quantity, ensuring that as the star's distance from the center of mass changes, so does its speed. The stars maintain a constant overall system momentum.
  • Elliptical Paths: Unlike circular orbits, elliptical orbits mean that stars are sometimes closer or farther from each other, requiring careful balancing in force calculations.
Understanding these mechanics is essential for scientists who study these amazing cosmic dances, offering insights into the lifecycle of star systems and the universe at large.

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Most popular questions from this chapter

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