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ssm A volleyball is spiked so that its incoming velocity of 4.0 m/s is changed to an outgoing velocity of 21 m/s. The mass of the volley- ball is 0.35 kg. What impulse does the player apply to the ball?

Short Answer

Expert verified
The player applies an impulse of 5.95 kg·m/s to the ball.

Step by step solution

01

Identify Given Values

We have the mass of the volleyball \( m = 0.35 \text{ kg} \), the initial velocity \( v_i = 4.0 \text{ m/s} \), and the final velocity \( v_f = 21 \text{ m/s} \).
02

Understand Impulse

Impulse \( J \) given to an object is equal to the change in momentum. It is calculated using the equation \( J = \Delta p = m \cdot (v_f - v_i) \).
03

Substitute Values into the Impulse Equation

Using the equation for impulse, substitute the known values: \( J = 0.35 \times (21 - 4) \).
04

Calculate the Impulse

Compute the result: \( J = 0.35 \cdot 17 = 5.95 \text{ kg}\cdot\text{m/s} \).
05

Review Units and Answer

Ensure the units are consistent; since impulse is momentum, the units \( \text{kg} \cdot \text{m/s} \) are correct. The impulse applied to the volleyball is 5.95 kg·m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Momentum
Momentum in physics refers to the quantity of motion an object has. It is a vector quantity, which means it has both magnitude and direction. The momentum of an object is calculated by the formula:\[ p = m imes v \]where \( p \) symbolizes momentum, \( m \) is the mass of the object, and \( v \) is its velocity. This means that an object's momentum is directly proportional to both its mass and its velocity.

For example, if a volleyball with a mass of 0.35 kg is moving at a velocity of 4.0 m/s, its initial momentum is given by:\[ p_{ ext{initial}} = 0.35 imes 4.0 = 1.4 ext{ kg} imes ext{m/s} \]

Understanding momentum helps us to quantify the motion of the object and how much force is required to change that motion.
Velocity Change
Velocity change is a critical concept when considering the motion of objects. It describes how quickly and in what direction an object's velocity alters. The change in velocity is a vector that points from the initial velocity towards the final velocity, with its magnitude being the difference between the two.
To compute the change in velocity, you subtract the initial velocity from the final velocity:\[ \Delta v = v_f - v_i \]where \( v_i \) is the initial velocity and \( v_f \) is the final velocity. When a volleyball is spiked and its velocity changes from 4.0 m/s to 21 m/s, the change in velocity is:\[ \Delta v = 21 - 4 = 17 ext{ m/s} \]
This value indicates that the velocity has increased by 17 m/s in the direction specified by the spiking.
Mass and Velocity
Mass and velocity together determine the motion of an object. Mass is a measure of how much matter is in an object, while velocity describes the speed of the object in a specific direction.

An object's overall momentum is influenced by both its mass and velocity, as captured in the momentum formula \( p = m imes v \). In practical situations, such as sports, knowing the mass and velocity helps predict how the object will move.
In our volleyball example, the mass of the ball is 0.35 kg, and its velocity changes significantly due to the player's spike. Both these factors profoundly affect the ball's trajectory and the forces involved when it interacts with the player's hand.
Physics Equations
Physics equations are mathematical relationships that allow us to predict and understand the behavior of physical systems. One of the essential equations related to impulse and momentum is the impulse-momentum theorem which states that the impulse applied to an object is equal to the change in its momentum. This is expressed as:\[ J = \Delta p = m imes \(v_f - v_i\) \]
In the context of our exercise, the impulse \( J \) is calculated using the mass of the volleyball and the change in its velocity. Substituting the given values, it simplifies to:\[ J = 0.35 imes (21 - 4) = 5.95 ext{ kg} imes ext{m/s} \]
This computation helps us understand how much force over time (impulse) the player applied to achieve the volleyball's change in motion.

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Most popular questions from this chapter

mmh A 0.015-kg bullet is fired straight up at a falling wooden block that has a mass of 1.8 kg. The bullet has a speed of 810 m/s when it strikes the block. The block originally was dropped from rest from the top of a building and has been falling for a time t when the collision with the bullet occurs. As a result of the collision, the block (with the bullet in it) reverses direction, rises, and comes to a momentary halt at the top of the building. Find the time t.

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When jumping straight down, you can be seriously injured if you land stiff- legged. One way to avoid injury is to bend your knees upon landing to reduce the force of the impact. A 75-kg man just before contact with the ground has a speed of 6.4 m/s. (a) In a stiff-legged landing he comes to a halt in 2.0 ms. Find the average net force that acts on him during this time. (b) When he bends his knees, he comes to a halt in 0.10 s. Find the average net force now. (c) During the landing, the force of the ground on the man points upward, while the force due to gravity points downward. The average net force acting on the man includes both of these forces. Taking into account the directions of the forces, find the force of the ground on the man in parts (a) and (b).

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