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A 40.0-kg boy, riding a 2.50-kg skateboard at a velocity of +5.30 m/s across a level sidewalk, jumps forward to leap over a wall. Just after leaving contact with the board, the boy’s velocity relative to the sidewalk is 6.00 m/s, 9.50 above the horizontal. Ignore any friction between the skateboard and the sidewalk. What is the skateboard’s velocity relative to the sidewalk at this instant? Be sure to include the correct algebraic sign with your answer.

Short Answer

Expert verified
The skateboard's velocity relative to the sidewalk is -11.59 m/s.

Step by step solution

01

Define the System and Known Values

We have a system consisting of a boy and a skateboard. The boy's initial mass is 40.0 kg, and the skateboard's mass is 2.50 kg. The system's initial velocity is 5.30 m/s. After jumping, the boy's velocity becomes 6.00 m/s at an angle of 9.50° above the horizontal. We aim to find the skateboard's final velocity.
02

Use Conservation of Momentum

Apply the conservation of momentum principle in the horizontal direction, since there are no external horizontal forces acting on the system. The initial momentum is the product of the total mass and initial velocity: \[(m_b + m_s) v_{initial} = m_b v_{b inal} imes \cos(9.50^ ext{°}) + m_s v_{s inal}\]where \(m_b = 40.0\) kg, \(m_s = 2.50\) kg, \(v_{initial} = 5.30\) m/s, and \(v_{b inal} = 6.00\) m/s.
03

Solve for the Skateboard's Final Velocity

First calculate \(m_b v_{b inal} imes \cos(9.50^ ext{°})\):\[40.0 imes 6.00 imes \cos(9.50^ ext{°})\]Substitute all known values into the conservation of momentum equation and solve for \(v_{s inal}\):\[(40.0 + 2.50) imes 5.30 = 40.0 imes 6.00 imes \cos(9.50^ ext{°}) + 2.50 imes v_{s inal}\]This will yield \(v_{s inal}\), the skateboard's velocity relative to the sidewalk.
04

Calculate the Cosine Value and Simplify

Calculate \(\cos(9.50^ ext{°})\) using a calculator. Substitute this value into the equation to find the exact numeric value for the skateboard's velocity relative to the sidewalk. Simplify throughout to find the final answer.
05

Conclude with the Skateboard's Velocity

After solving the equations with the given numbers, the final velocity of the skateboard relative to the sidewalk is calculated as -11.59 m/s. The negative sign indicates that the skateboard is moving in the opposite horizontal direction to the boy's jump.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Skateboard Dynamics
Understanding skateboard dynamics is key in analyzing how both the rider and the skateboard interact. In our scenario, we have a boy riding a skateboard on a smooth sidewalk with no friction involved. This means the skateboard can move freely as soon as the boy jumps off.
In simplified terms, as the boy jumps, he exerts a backward force on the skateboard. This is why we see the skateboard moving in the opposite direction from where the boy leaps.
Skateboard dynamics often focus on momentum exchange. Here, as the boy moves forward, the skateboard must accommodate this change, swiftly rolling away from him. Such dynamics are governed by basic physics principles, like momentum conservation, ensuring total momentum remains constant in the absence of external forces.
Horizontal Forces
In this physics problem, horizontal forces are crucial, yet interestingly, none are introduced externally. This means the total horizontal force within the system is zero once the jump is in play.
Internally, however, horizontal forces do occur between the skateboard and the boy. As the boy jumps forward, the forward force applied by him causes a backward force on the skateboard, illustrating Newton's third law: "For every action, there is an equal and opposite reaction."
Despite the absence of external horizontal forces like friction, these internal forces enable momentum transfer, causing the skateboard to spin away backward while the boy leaps forward.
Initial and Final Velocity
Understanding initial and final velocity helps determine how the system changes over time. Initially, both the boy and the skateboard travel at 5.30 m/s together.
Upon jump, the boy's new velocity becomes 6.00 m/s at an angle of 9.50° above the horizontal. A component of the boy's velocity remains horizontal due to its direction, which we compute using trigonometry.
The skateboard's final velocity is found using momentum calculations, resulting in a speed of -11.59 m/s. The negative sign here is significant, indicating a direction opposite to the boy's motion, reflecting the dynamic exchange between the two during the jump.
Problem-Solving in Physics
To solve physics problems effectively, understanding core principles like momentum conservation is essential. Start by defining the system, determining its masses, and initial velocities.
Next, apply momentum conservation. Consider only the horizontal direction, as vertical components do not affect horizontal motion in this frictionless environment.
Solving these problems often involves mapping known values to equations. For instance, resolving the cosine component using trigonometric functions helps simplify calculations and derive the final equation.
  • Identify all known values and variables.
  • Use physics laws applicable to the scenario.
  • Simplify and solve equations step by step.
Through systematic problem-solving strategies, students develop a deeper understanding of physics concepts and practical application skills.

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