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A helicopter, starting from rest, accelerates straight up from the roof of a hospital. The lifting force does work in raising the helicopter. An 810-kg helicopter rises from rest to a speed of 7.0 m/s in a time of 3.5 s. During this time it climbs to a height of 8.2 m. What is the average power generated by the lifting force?

Short Answer

Expert verified
The average power generated by the lifting force is approximately 24,382 watts.

Step by step solution

01

Understanding Power

Power is the rate at which work is done or energy is transferred within a system. It can be calculated using the formula for average power:\[ P = \frac{W}{\Delta t} \]where \( P \) is power, \( W \) is work done, and \( \Delta t \) is the time interval.
02

Calculating Work Done

The work done on the helicopter can be calculated as the sum of the change in kinetic energy and the change in gravitational potential energy. The formulas to calculate these are:- Kinetic Energy: \( KE = \frac{1}{2} m v^2 \), where \( m \) is mass and \( v \) is velocity.- Potential Energy: \( PE = mgh \), where \( g \) is the acceleration due to gravity and \( h \) is the height.Calculate the initial and final energies and then subtract the initial from the final to find the work done:Change in kinetic energy:\[ \Delta KE = \frac{1}{2} \times 810 \times 7.0^2 - \frac{1}{2} \times 810 \times 0^2 = 19845 \, \text{J} \]Change in potential energy:\[ \Delta PE = 810 \times 9.81 \times 8.2 = 65490.36 \, \text{J} \]Total work done:\[ W = \Delta KE + \Delta PE = 19845 + 65490.36 = 85335.36 \, \text{J} \]
03

Calculating Average Power

Substitute the total work done and time interval into the power formula to find the average power:\[ P = \frac{85335.36}{3.5} = 24381.53 \, \text{W} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Work and Energy
Work and energy are fundamental concepts in physics that describe the transfer and transformation of energy. Work is done when a force causes an object to move in the direction of the force. The amount of work can be calculated by multiplying the force applied by the distance over which the force is exerted. Energy, on the other hand, is the capacity to do work. It can exist in various forms, such as kinetic energy, potential energy, and more.

Understanding the relationship between work and energy is crucial for solving physics problems. In our helicopter example, the lifting force does work on the helicopter, allowing it to gain both speed (kinetic energy) and height (potential energy). Thus, calculating work helps us determine how energy is changing and being utilized in the system.
Kinetic Energy
Kinetic energy is the energy an object possesses due to its motion. When an object is moving, it can have kinetic energy. The faster an object moves, the more kinetic energy it has. The formula for calculating kinetic energy is given by: \[ KE = \frac{1}{2} mv^2 \] where \( m \) is mass and \( v \) is velocity.

In our helicopter problem, the helicopter starts from rest and accelerates to a speed of 7.0 m/s. Initially, its kinetic energy is zero since its velocity is zero. As it accelerates, its kinetic energy increases. This change in kinetic energy is a part of the total work done on the helicopter, and it's important to compute this to understand how energy is being transformed as the helicopter gains speed.
Gravitational Potential Energy
Gravitational potential energy is the energy an object possesses that is associated with its position relative to a reference point, usually the ground. An object placed at a height above the ground has the potential to fall due to gravity, thereby possessing potential energy. The formula to calculate gravitational potential energy is:
\( PE = mgh \) where \( m \) is mass, \( g \) is the acceleration due to gravity (approximately 9.81 m/s² on Earth), and \( h \) is the height above the reference point.

For the helicopter, as it climbs to a height of 8.2 meters, its gravitational potential energy increases. This increase represents another part of the work done by the lifting force, as energy is converted from work into potential energy as the helicopter elevates.
Average Power
Average power is a measure of how quickly work is done or energy is transformed within a time period. It helps us understand the rate at which energy is being used or converted in a system. The formula for calculating average power is:
\[ P = \frac{W}{\Delta t} \] where \( W \) is the total work done, and \( \Delta t \) is the time interval over which the work is done.

In the helicopter scenario, we determine the average power by dividing the total work done (sum of changes in kinetic and potential energy) by the time taken, which is 3.5 seconds. Calculating average power gives insight into the intensity of energy usage, showing us how efficiently the helicopter's engine is converting energy within the time frame.
Physics Problem-Solving
Physics problem-solving involves systematic approaches to understand and solve various scenarios, often by applying key concepts and formulas. Here, it's important to:
  • Analyze the problem statement and understand what is given and what needs to be found.
  • Identify applicable physics principles such as work-energy principles.
  • Use the relevant equations to perform calculations step by step.
  • Verify the units and ensure the calculations logically align.
In this helicopter example, we employ the concepts of kinetic energy, potential energy, and power to systematically assess how the helicopter's motion translates into energy management. Good problem-solving skills in physics allow students to break complex problems into manageable parts and find solutions efficiently. By understanding each component—work, energy transformations, and power calculation—you enhance your capability to tackle and solve physics problems.

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Most popular questions from this chapter

A sled is being pulled across a horizontal patch of snow. Friction is negligible. The pulling force points in the same direction as the sled’s displacement, which is along the x axis. As a result, the kinetic energy of the sled increases by 38%. By what percentage would the sled’s kinetic energy have increased if this force had pointed \(62^{\circ}\) above the x axis?

A person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed \(25.0^{\circ}\) above the snow. The tension in the rope is 94.0 N. (a) How much work is done on the toboggan by the tension force? (b) How much work is done if the same tension is directed parallel to the snow?

A fighter jet is launched from an aircraft carrier with the aid of its own engines and a steam-powered catapult. The thrust of its engines is \(2.3 \times 10^{5} \mathrm{N}\) . In being launched from rest it moves through a distance of 87 \(m\) and has a kinetic energy of \(4.5 \times 10^{7} J\) at lift-off. What is the work done on the jet by the catapult?

The brakes of a truck cause it to slow down by applying a retarding force of \(3.0 \times 10^{3} N\) to the truck over a distance of 850 \(m\) . What is the work done by this force on the truck? Is the work positive or negative? Why?

Under the influence of its drive force, a snowmobile is moving at a constant velocity along a horizontal patch of snow. When the drive force is shut off, the snowmobile coasts to a halt. The snowmobile and its rider have a mass of 136 kg. Under the influence of a drive force of 205 N, it is moving at a constant velocity whose magnitude is 5.50 m/s. The drive force is then shut off. Find (a) the distance in which the snowmobile coasts to a halt and (b) the time required to do so.

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