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A centrifuge is a device in which a small container of material is rotated at a high speed on a circular path. Such a device is used in medical laboratories, for instance, to cause the more dense red blood cells to settle through the less dense blood serum and collect at the bottom of the container. Suppose the centripetal acceleration of the sample is \(6.25 \times 10^{3}\) times as large as the acceleration due to gravity. How many revolutions per minute is the sample making, if it is located at a radius of 5.00 \(\mathrm{cm}\) from the axis of rotation?

Short Answer

Expert verified
The sample is making around 10576 revolutions per minute.

Step by step solution

01

Understand the given values and formula

We have the centripetal acceleration of the sample, which is \(6.25 \times 10^3 g\), where \(g = 9.81 \, \text{m/s}^2\). The radius \(r\) is given as \(5.00 \, \text{cm} = 0.05 \, \text{m}\). We need to find the revolutions per minute (rpm). The formula for centripetal acceleration \(a_c\) is \(a_c = \frac{v^2}{r}\), where \(v\) is the velocity.
02

Calculate the centripetal acceleration

The centripetal acceleration is given as \(a_c = 6.25 \times 10^3 g\). Substituting \(g = 9.81 \, \text{m/s}^2\), we get:\[ a_c = 6.25 \times 10^3 \times 9.81 = 61312.5 \, \text{m/s}^2 \]
03

Express velocity in terms of centripetal acceleration

Using the formula \(a_c = \frac{v^2}{r}\), solve for \(v\):\[ v^2 = a_c \times r \]\[ v^2 = 61312.5 \times 0.05 \, \text{m} = 3065.625 \, \text{m}^2/\text{s}^2 \]\[ v = \sqrt{3065.625} \approx 55.35 \, \text{m/s} \]
04

Convert velocity to angular velocity

The formula to relate linear velocity \(v\) with angular velocity \(\omega\) is \(v = \omega r\). We solve for \(\omega\):\[ \omega = \frac{v}{r} = \frac{55.35}{0.05} = 1107 \, \text{rad/s} \]
05

Convert angular velocity to revolutions per minute

Convert \(\omega\) from radians per second to revolutions per minute. We know:\[ 1 \text{ revolution} = 2\pi \text{ radians} \] and \[1 \text{ minute} = 60 \text{ seconds} \].\[ \text{Revolutions per second} = \frac{1107}{2\pi} \approx 176.27 \]\[ \text{Revolutions per minute} = 176.27 \times 60 \approx 10576.2 \]
06

Final answer and rounding

After rounding, the number of revolutions per minute is approximately 10576 rpm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Centrifuge
A centrifuge is an essential tool used in various scientific fields, particularly in medical laboratories. It works on the principle of centripetal force, involving the rapid rotation of a sample around a fixed axis. This motion creates a strong force directed towards the center of the rotation, which effectively separates substances of different densities within a mixture. For example, in blood samples, denser red blood cells are forced to the bottom of the container, separating them from the less dense serum.

This separation process is crucial for various analyses, allowing scientists to study specific components of a sample with greater ease. Centrifuges can vary in size and speed, accommodating different types of samples and requirements. The high speed of rotation is particularly important because it increases the centripetal force exerted on the sample, resulting in more efficient separation.
Revolutions per Minute
Revolutions per minute (rpm) is a unit of rotational speed that quantifies how many full rotations an object makes in one minute. This measurement is widely used in many applications, including the operation of centrifuges. Understanding rpm is crucial for ensuring that the device operates efficiently and safely.

When calculating rpm, the relationship between angular velocity and linear velocity is key. A device like a centrifuge typically has a motor that spins at a specified rpm, ensuring the contents inside achieve the necessary separation. Knowing the rpm allows scientists to adjust the speed for specific experimental requirements, ensuring optimal conditions for sample analysis.

This unit not only tells us how fast the load is spinning but also helps in predicting the efficiency and results of the separation process. Adjusting the rpm can significantly impact how well the various components within a sample are separated.
Angular Velocity
Angular velocity is an important concept in rotational motion, describing how quickly an object rotates around a particular point or axis. It is usually represented by the symbol \(\omega\), and is measured in radians per second (rad/s). In the context of a centrifuge, angular velocity reveals how fast the centrifuge's rotor is spinning.

To find the angular velocity, we use the relation \(v = \omega r\), where \(v\) is the linear velocity and \(r\) is the radius of the circle along which the rotation occurs. This relationship helps us convert between linear and rotational dynamics, which is essential for calculations involving rpm or the specific requirements of a centrifuge.

Angular velocity connects directly to the forces experienced by the sample inside a centrifuge. Higher angular velocities mean stronger centripetal forces, leading to quicker and more thorough separation of the sample components. Adjusting the angular velocity allows scientists to control the precision and speed of separation, thereby tailoring the centrifuge's performance to the specific needs of various experiments.

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Most popular questions from this chapter

A car is safely negotiating an unbanked circular turn at a speed of 21 m/s. The road is dry, and the maximum static frictional force acts on the tires. Suddenly a long wet patch in the road decreases the maximum static frictional force to one-third of its dry-road value. If the car is to continue safely around the curve, to what speed must the driver slow the car?

A satellite circles the earth in an orbit whose radius is twice the earth's radius. The earth's mass is \(5.98 \times 10^{24} \mathrm{kg},\) and its radius is \(6.38 \times 10^{6} \mathrm{m} .\) What is the period of the satellite?

A satellite is in a circular orbit around an unknown planet. The satellite has a speed of \(1.70 \times 10^{4} \mathrm{m} / \mathrm{s},\) and the radius of the orbit is \(5.25 \times 10^{6} \mathrm{m} .\) A second satellite also has a circular orbit around this same planet. The orbit of this second satellite has a radius of \(8.60 \times 10^{6} \mathrm{m} .\) What is the orbital speed of the second satellite?

The National Aeronautics and Space Administration (NASA) studies the physiological effects of large accelerations on astronauts. Some of these studies use a machine known as a centrifuge. This machine consists of a long arm, to one end of which is attached a chamber in which the astronaut sits. The other end of the arm is connected to an axis about which the arm and chamber can be rotated. The astronaut moves on a circular path, much like a model airplane flying in a circle on a guideline. The chamber is located 15 m from the center of the circle. At what speed must the chamber move so that an astronaut is subjected to 7.5 times the acceleration due to gravity?

Multiple-Concept Example 7 reviews the concepts that play a role in this problem. Car A uses tires for which the coefficient of static friction is 1.1 on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is 25 m/s. Car B uses tires for which the coefficient of static friction is 0.85 on the same curve. What is the maximum speed at which car B can negotiate the curve?

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