/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 95 ssm A \(55-\mathrm{kg}\) bungee ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

ssm A \(55-\mathrm{kg}\) bungee jumper has fallen far enough that her bungee cord is beginning to stretch and resist her downward motion. Find the force (magnitude and direction) exerted on her by the bungee cord at an instant when her downward acceleration has a magnitude of 7.6 \(\mathrm{m} / \mathrm{s}^{2}\) Ignore the effects of air resistance.

Short Answer

Expert verified
The force exerted by the bungee cord is 121 N upward.

Step by step solution

01

Understand the Forces Acting

The bungee jumper is subjected to two main forces: her weight (gravity) acting downward and the force of the bungee cord acting upward. The net force is what causes her acceleration.
02

Calculate the Gravitational Force

The gravitational force (weight) can be calculated using the formula: \[ F_g = m \cdot g \]where \( m = 55 \text{ kg} \) is the mass of the bungee jumper, and \( g = 9.8 \text{ m/s}^2 \) is the acceleration due to gravity. Thus,\[ F_g = 55 \times 9.8 = 539 \text{ N} \] downwards.
03

Determine the Net Force

The net force \( F_{net} \) required to produce a downward acceleration \( a = 7.6 \text{ m/s}^2 \) can be found using Newton's second law:\[ F_{net} = m \cdot a \]Substituting the given values:\[ F_{net} = 55 \times 7.6 = 418 \text{ N} \] downward.
04

Calculate the Bungee Force

Let \( F_b \) be the force exerted by the bungee cord, which acts upwards. Since the net force is the difference between the downward gravitational force and the upward bungee force, we have:\[ F_{net} = F_g - F_b \]This can be rearranged to find \( F_b \):\[ F_b = F_g - F_{net} = 539 - 418 = 121 \text{ N} \] upward.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gravitational Force
Gravitational force is a fundamental concept in physics, often simply referred to as weight. It is the force with which the Earth pulls a mass towards its center. For the bungee jumper, this force acts continuously downward throughout her fall. The strength of the gravitational force can be calculated using the formula: \[ F_g = m \times g \] Here, \( m \) represents the mass of the object (in this case, the bungee jumper), and \( g \) is the acceleration due to gravity, typically valued at \( 9.8 \text{ m/s}^2 \). For a bungee jumper with a mass of \( 55 \text{ kg} \), the gravitational force can be calculated as \( 539 \text{ N} \) downwards. This calculation confirms that gravity exerts a considerable downward force, which begins to be counteracted by the bungee cord as the jumper reaches further into the jump.
Net Force
The net force is the overall force acting on an object after accounting for all individual forces. It is simply the vector sum of all forces involved. In this scenario, the net force is crucial because it determines the bungee jumper's acceleration according to Newton’s Second Law: \[ F_{net} = m \times a \] For our jumper, with an acceleration of \( 7.6 \text{ m/s}^2 \) downwards, the net force is calculated to be \( 418 \text{ N} \) downward. The net force here tells us how much of the gravitational pull is actually contributing to the jumper's acceleration, as opposed to being offset by the opposing force of the bungee cord. This value indicates how effectively the bungee cord is working to slow down the fall as it begins to stretch.
Bungee Cord Force
The bungee cord force is a counteracting force that opposes gravitational pull as it stretches. This force acts upwards, opposing the weight of the jumper. In this exercise, finding the bungee cord force is essential to understanding how it alters the net force acting on the jumper. The calculations show: * Gravitational force: \( 539 \text{ N} \) downward * Net force: \( 418 \text{ N} \) downward Using the formula: \[ F_{b} = F_{g} - F_{net} \] We find that \( F_{b} = 121 \text{ N} \) upward. This indicates that the bungee cord exerts a substantial force to counter gravitational pull, reducing the acceleration and contributing to the safety and thrill of the bungee jump.
Downward Acceleration
Downward acceleration is a key aspect of the motion of a bungee jumper. It describes how quickly a person is speeding up in the downward direction. Initially, the jumper accelerates under gravity, but as the bungee cord stretches, it begins to influence this acceleration. Newton's Second Law helps in understanding this concept through the formula: \[ a = \frac{F_{net}}{m} \] For our bungee jumper, despite the gravitational force being \( 539 \text{ N} \), the actual acceleration experienced is \( 7.6 \text{ m/s}^2 \) downward, due to the opposing force of the bungee cord. Thus, while the gravitational force constantly encourages acceleration, the force from the bungee cord works against it, steadily decreasing the rate at which the jumper speeds downward. This balance ensures that the velocity and motion during the fall are safe and thrilling.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

ssm mm A rocket of mass \(4.50 \times 10^{5} \mathrm{kg}\) is in flight. Its thrust is directed at an angle of \(55.0^{\circ}\) above the horizontal and has a magnitude of \(7.50 \times 10^{6} \mathrm{N}\) . Find the magnitude and direction of the rocket's acceleration. Give the direction as an angle above the horizontal.

A car is towing a boat on a trailer. The driver starts from rest and accelerates to a velocity of \(+11 \mathrm{m} / \mathrm{s}\) in a time of 28 \(\mathrm{s}\) . The combined mass of the boat and trailer is 410 \(\mathrm{kg}\) . The frictional force acting on the trailer can be ignored. What is the tension in the hitch that connects the trailer to the car?

A \(1.14 \times 10^{4}\) -kg lunar landing craft is about to touch down on the surface of the moon, where the acceleration due to gravity is 1.60 \(\mathrm{m} / \mathrm{s}^{2}\) . At an altitude of 165 \(\mathrm{m}\) the craft's downward velocity is 18.0 \(\mathrm{m} / \mathrm{s}\) . To slow down the craft, a retrorocket is firing to provide an upward thrust. Assuming the descent is vertical, find the magnitude of the thrust needed to reduce the velocity to zero at the instant when the craft touches the lunar surface.

ssm At an airport, luggage is unloaded from a plane into the three cars of a luggage carrier, as the drawing shows. The acceleration of the carrier is 0.12 \(\mathrm{m} / \mathrm{s}^{2}\), and friction is negligible. The coupling bars have negligible mass. By how much would the tension in each of the coupling bars \(A\), \(B\), and \(C\) change if 39 \(\mathrm{kg}\) of luggage were removed from car 2 and placed in (a) car 1 and (b) car 3? If the tension changes, specify whether it increases or decreases.

ssm A \(1380-\mathrm{kg}\) car is moving due east with an initial speed of 27.0 \(\mathrm{m} / \mathrm{s}\) . After 8.00 \(\mathrm{s}\) the car has slowed down to 17.0 \(\mathrm{m} / \mathrm{s}\) . Find the magnitude and direction of the net force that produces the deceleration.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.