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ssm The Bohr model can be applied to singly ionized helium He \(^{+}(Z=2) .\) Using this model, consider the series of lines that is produced when the electron makes a transition from higher energy levels into the \(n_{\mathrm{f}}=4\) level. Some of the lines in this series lie in the visible region of the spectrum \((380-750 \mathrm{nm}) .\) What are the values of \(n_{1}\) for the energy levels from which the electron makes the transitions corresponding to these lines?

Short Answer

Expert verified
The initial energy levels are \( n_i = 6, 5 \) for visible spectrum transitions to \( n_f = 4 \).

Step by step solution

01

Understanding the Bohr Model for Helium Ion

In the Bohr model, the energy of an electron in a given orbit of a hydrogen-like ion is given by the formula: \( E_n = -13.6 \frac{Z^2}{n^2} \) eV, where \( Z \) is the atomic number (2 for He\(^+\)) and \( n \) is the principal quantum number. We need to find from which initial energy levels \( n_i \) the electron falls to \( n_f = 4 \) to produce light in the visible spectrum.
02

Calculating Energy Levels

For transitions that end at \( n_f = 4 \), the initial energy levels \( n_i \) are greater than 4. Use the energy difference formula: \( \Delta E = E_{n_i} - E_{n_f} \), where \( E_{n_i} = -13.6 \frac{Z^2}{n_i^2} \) and \( E_{n_f} = -13.6 \frac{Z^2}{n_f^2} \).
03

Convert Energy to Wavelength

The wavelength \( \lambda \) of the emitted photon can be found using \( \Delta E = \frac{hc}{\lambda} \), where \( h \) is Planck's constant and \( c \) is the speed of light. This formula allows us to calculate \( \lambda \) for each transition from \( n_i \) to \( n_f = 4 \).
04

Determining Visible Transitions

Calculate \( \lambda \) for different \( n_i \) values greater than 4 and check if the wavelength falls within the visible range (380 nm to 750 nm). Adjust \( n_i \) until the wavelengths for transitions to \( n_f = 4 \) fall within the visible spectrum.
05

Finding the Initial Energy Levels

Through calculations, it can be determined that the visible spectral lines occur from transitions where \( n_i = 6, 5 \) to \( n_f = 4 \). These produce wavelengths that fall within the visible range.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Singly Ionized Helium
A singly ionized helium atom, denoted as He\(^+\), is a helium atom that has lost one of its electrons. This makes it very similar to a hydrogen atom, but with one key difference: it has two protons in its nucleus, meaning its atomic number, \(Z\), is 2. The extra proton compared to hydrogen results in a stronger nuclear force acting on the electron, influencing the energy levels of the atom. In educational problems like this one, helium is often used to explore concepts because of its simplicity and similarity to hydrogen systems. This makes it easier to apply concepts like the Bohr model to helium for deeper understanding.
Energy Levels
Energy levels are specific states where electrons exist in an atom. According to the Bohr model, these levels are quantized, meaning electrons can only reside in specific, discrete levels. The energy of these levels is determined by the formula: \[ E_n = -13.6 \frac{Z^2}{n^2} \text{ eV} \] where \(E_n\) is the energy in electron volts, \(Z\) is the atomic number, and \(n\) is the principal quantum number that defines each energy level. For a singly ionized helium atom (He\(^+\)), \(Z = 2\). The energy levels are more tightly spaced than in a hydrogen atom due to the added nuclear charge. These levels determine the electron's behavior, such as the transitions where electrons jump from a higher energy level to a lower one, emitting or absorbing light in the process.
Visible Spectrum
The visible spectrum is the part of the electromagnetic spectrum that can be seen by the human eye. It spans wavelengths approximately from 380 nm to 750 nm. When an electron in an atom transitions from a higher energy state to a lower one, it emits light at a specific wavelength. This wavelength depends on the energy difference between the two states. If this wavelength lies within the range of the visible spectrum, the light emitted is visible to us. In the context of the Bohr model applied to helium, when electrons transition to the \(n_f = 4\) level, some of these transitions emit light in the visible spectrum. This can be calculated using the energy difference between levels and converting it to wavelength using Planck's constant and the speed of light. These transitions are visually represented as lines in the atom's emission spectrum.
Electron Transition
Electron transitions refer to the movement of electrons between energy levels in an atom. In the Bohr model, each transition results in the emission or absorption of a photonic quanta, also known as light. The starting point of a transition is known as the initial energy level, \(n_i\), and the endpoint is the final energy level, \(n_f\). The formula for the energy difference \(\Delta E\) between these levels is: \[ \Delta E = \frac{hc}{\lambda} \] where \(h\) is Planck's constant, \(c\) is the speed of light, and \(\lambda\) is the wavelength of emitted light. When discussing electron transitions in singly ionized helium, we are often interested in how these transitions correspond to visible light. For example, an electron falling to the \(n_f = 4\) level from levels such as \(n_i = 5\) or \(6\) produces wavelengths in the visible spectrum, allowing these transitions to be observed with the naked eye. Understanding these transitions is key to grasping how elements emit unique spectral lines that can be used in chemical analysis and astrophysics.

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Most popular questions from this chapter

In the ground state, the outermost shell (n 1) of helium (He) is filled with electrons, as is the outermost shell (n 2) of neon (Ne). The full outermost shells of these two elements distinguish them as the first two so-called 鈥渘oble gases.鈥 Suppose that the spin quantum number \(m_{s}\) had three possible values, rather than two. If that were the case, which elements would be (a) the first and (b) the second noble gases? Assume that the possible values for the other three quantum numbers are unchanged, and that the Pauli exclusion principle still applies.

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