/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 A golf ball rolls off a horizont... [FREE SOLUTION] | 91Ó°ÊÓ

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A golf ball rolls off a horizontal cliff with an initial speed of 11.4 m/s. The ball falls a vertical distance of 15.5 m into a lake below. (a) How much time does the ball spend in the air? (b) What is the speed v of the ball just before it strikes the water?

Short Answer

Expert verified
(a) The ball spends approximately 1.78 seconds in the air. (b) The speed just before impact is about 20.84 m/s.

Step by step solution

01

Analyze the Vertical Motion

To find the time the ball spends in the air, we need to focus on its vertical motion. The ball falls a vertical distance of 15.5 m under the influence of gravity alone. We can use the equation for free fall: \[ s = ut + \frac{1}{2}gt^2 \]where \( s = 15.5 \) m is the vertical distance, \( u = 0 \) m/s is the initial vertical velocity (since it rolls off horizontally), and \( g = 9.81 \) m/s² is the acceleration due to gravity.
02

Solve for Time in the Air

Substitute the known values into the free fall equation and solve for \( t \):\[ 15.5 = 0 \cdot t + \frac{1}{2} \cdot 9.81 \cdot t^2 \]\[ 15.5 = 4.905t^2 \]\[ t^2 = \frac{15.5}{4.905} \]\[ t^2 \approx 3.16 \]\[ t \approx \sqrt{3.16} \approx 1.78 \] secondsThis time, \( t \approx 1.78 \) seconds, is the duration the ball spends in the air.
03

Analyze the Horizontal Motion

Since the ball moves horizontally with a constant speed of 11.4 m/s and there is no horizontal acceleration, the horizontal motion equation is not needed to find the time, as horizontal and vertical motions are independent.
04

Determine the Final Vertical Speed Component

To find the vertical speed component just before hitting the water, use the formula:\[ v_y = u + gt \]Where \( u = 0 \) m/s, \( g = 9.81 \) m/s², and \( t = 1.78 \) seconds:\[ v_y = 0 + 9.81 \times 1.78 \approx 17.46 \] m/s.
05

Determine the Speed of the Ball Just Before Impact

The speed of the ball just before it strikes the water is the vector sum of its horizontal and vertical speed components. Use the Pythagorean theorem:\[ v = \sqrt{v_x^2 + v_y^2} \]where \( v_x = 11.4 \) m/s and \( v_y \approx 17.46 \) m/s.\[ v = \sqrt{11.4^2 + 17.46^2} \]\[ v = \sqrt{130.56 + 304.1316} \]\[ v = \sqrt{434.6916} \]\[ v \approx 20.84 \] m/s.Thus, the speed just before impact is approximately 20.84 m/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Free Fall
Free fall is when an object moves only under the influence of gravitational force. There are no other forces acting on it, which means that the motion is completely vertical. In the case of our golf ball, once it leaves the cliff, it is in free fall.
  • The initial vertical speed is 0 m/s because the ball starts falling horizontally.
  • The gravitational acceleration, denoted as \( g \), is 9.81 m/s².
In free fall, the vertical distance fallen \( s \) can be calculated using the equation: \[ s = ut + \frac{1}{2}gt^2 \]Here, \( s \) is the distance fallen, \( u \) is the initial vertical speed (0 m/s for free fall), \( g \) is gravitational acceleration, and \( t \) is time. Since it is rolling off horizontally, our focus is on the gravity pulling it down, thus making the calculations simple yet effective for finding the time of descent.
Horizontal and Vertical Motion
Projectile motion involves both horizontal and vertical components, yet they operate independently. This is a critical understanding in physics problems, allowing one to solve for one dimension without influencing the other.
  • Horizontal motion: The object maintains a constant speed, given at 11.4 m/s here, because there is no force causing horizontal acceleration.
  • Vertical motion: Governed by free fall, starts from rest in terms of speed and is influenced only by gravity.
Even though these components are independent, they occur simultaneously. To calculate how long the ball is in the air, you use vertical motion equations. To find how far it travels horizontally, you use the time of flight and horizontal speed.
Speed Calculation
Determining the resulting speed just before an impact or at any given point involves combining horizontal and vertical speed components.
  • Vertical speed is computed using: \[ v_y = u + gt \] Where \( u \) is the initial vertical speed (0 m/s here) and \( t \) is the time spent falling.
  • The horizontal speed remains constant at 11.4 m/s.
The combined speed, or the velocity just before the object strikes, is found by applying the Pythagorean theorem:\[ v = \sqrt{v_x^2 + v_y^2} \]Where \( v_x \) is the horizontal speed and \( v_y \) is the vertical speed just before impact. Understanding this helps in visualizing how speed vectors work to combine different motion directional speeds into a unified measure.
Physics Equations
Physics equations describe how objects move, offering a blueprint for solving motion problems. In projectile motion, several key physics equations are used to unravel the problem.
  • The equation \( s = ut + \frac{1}{2}gt^2 \) applies to vertical motion, allowing you to calculate the time in the air and understand how gravity acts over time.
  • For horizontal motion, the formula \( x = vt \) isn't necessary to find the flight's duration but helps determine horizontal displacement.
  • Velocity computation is unified through: \[ v = \sqrt{v_x^2 + v_y^2} \]This shows how different components of speed come together for a full picture of motion.
These equations empower you to split complex motion into simpler, more manageable parts, ultimately leading toward solutions comprehensively tied to forces and movement principles.

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