/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 67 A dolphin leaps out of the water... [FREE SOLUTION] | 91Ó°ÊÓ

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A dolphin leaps out of the water at an angle of \(35^{\circ}\) above the horizontal. The horizontal component of the dolphin's velocity is 7.7 \({m} / {s}\) . Find the magnitude of the vertical component of the velocity.

Short Answer

Expert verified
The vertical component of velocity is \(5.4\, \text{m/s}\).

Step by step solution

01

Identify Given Information

We are given the angle of the dolphin's leap as \(35^{\circ}\) and the horizontal component of the velocity as \(7.7\, \text{m/s}\). We need to find the vertical component of the velocity.
02

Understand the Concept

For projectile motion, the horizontal component of velocity \(v_x\) can be expressed as \(v_x = v \cdot \cos(\theta)\), where \(v\) is the magnitude of the velocity and \(\theta\) is the angle of projection.
03

Relate Vertical Component

The vertical component of the velocity \(v_y\) is given by \(v_y = v \cdot \sin(\theta)\).
04

Express Velocity in Terms of Known Quantities

We have \(v_x = 7.7\, \text{m/s} = v \cdot \cos(35^{\circ})\). We can solve for \(v\) first using this equation.
05

Solve for Total Velocity

Re-arrange to find \(v\) as follows:\[ v = \frac{v_x}{\cos(35^{\circ})} = \frac{7.7}{\cos(35^{\circ})} \] Calculate \(v\) using \(\cos(35^{\circ}) \approx 0.819\).
06

Calculate Total Velocity

Using the cosine approximation:\[ v \approx \frac{7.7}{0.819} \approx 9.4\, \text{m/s} \]
07

Find the Vertical Component

Now substitute \(v\) back into the vertical component equation:\[ v_y = 9.4 \cdot \sin(35^{\circ}) \]Since \(\sin(35^{\circ}) \approx 0.573\), calculate \(v_y\).
08

Calculate Vertical Component

Using the sine approximation:\[ v_y \approx 9.4 \cdot 0.573 \approx 5.4\, \text{m/s} \]
09

Conclusion

The magnitude of the vertical component of the dolphin's velocity is \(5.4\, \text{m/s}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vertical Component of Velocity
In projectile motion, the vertical component of velocity is key to understanding how high or how far an object will travel. When an object is launched at a certain angle, its velocity is divided into horizontal and vertical components.
The vertical component, often denoted as \(v_y\), is determined using the sine function from trigonometry. Specifically, if \(v\) is the magnitude of the total velocity and \(\theta\) is the angle of projection, the vertical component can be calculated as follows:
  • \(v_y = v \cdot \sin(\theta)\)
Understanding this concept is crucial because it helps predict the motion path and landing point of the object.
The vertical component is primarily responsible for the "up and down" motion. It influences how high the object will rise and how long it will stay in the air before coming back down.
In our dolphin leap example, knowing the vertical component of velocity helps us determine how high above the water surface the dolphin can jump.
This understanding merges physics with real-world applications like sports, engineering, and even wildlife behavior.
Horizontal Component of Velocity
The horizontal component of velocity is another essential factor in projectile motion. It defines the distance traveled over time and remains constant in the absence of air resistance.
The horizontal velocity, represented as \(v_x\), is calculated using the cosine function:
  • \(v_x = v \cdot \cos(\theta)\)
Where \(v\) is the initial velocity magnitude, and \(\theta\) is the angle of launch.
This component tells us how fast the object is moving horizontally and determines how far it will land from its starting point.
In projectile motion, the horizontal component doesn't change during flight since gravity only affects the vertical motion. This fact simplifies our calculations significantly.
In our dolphin example, the given horizontal velocity helps us understand how fast the dolphin swims horizontally, which is crucial, especially if we want to calculate the total velocity using known values.
Angle of Projection
The angle of projection is the angle at which an object is launched concerning the horizontal plane. This angle plays a pivotal role in determining the trajectory and overall behavior of the projectile.
In the context of projectile motion, the angle of projection influences:
  • The maximum height reached.
  • The range or distance traveled.
  • The time the object spends in flight.
Understanding these aspects helps predict outcomes in sports, engineering projects, and wildlife motion.
Mathematically, the angle of projection integrates into both horizontal and vertical component formulas:
  • For horizontal: \(v_x = v \cdot \cos(\theta)\)
  • For vertical: \(v_y = v \cdot \sin(\theta)\)
Properly manipulating these equations allows us to dissect and understand projectile paths accurately.
In the dolphin example, having a precise angle of \(35^{\circ}\) allows accurate calculation of both the vertical and horizontal components, providing a complete picture of the dolphin’s leap dynamics.

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