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The captain of a plane wishes to proceed due west. The cruising speed of the plane is 245 m/s relative to the air. A weather report indicates that a 38.0-m/s wind is blowing from the south to the north. In what direction, measured with respect to due west, should the pilot head the plane?

Short Answer

Expert verified
The plane should head approximately 8.94° south of west to counteract the wind.

Step by step solution

01

Understand the Given Problem

The plane wants to travel due west but faces a wind blow from the south to the north. We need to find the angle at which the plane should head to compensate for the wind's effect and still move west relative to the ground.
02

Set Up the Reference System

Assume a coordinate system where west is along the negative x-axis and north is along the positive y-axis. The wind velocity can be represented as a vector \( \vec{v}_{wind} = 38 \text{ m/s}\) in the positive y-direction.
03

Define the Plane's Velocity Components

The speed of the plane is \( 245 \text{ m/s} \) relative to the air. Let \( \theta \) be the angle with respect to due west (negative x-axis). The plane’s velocity relative to the air can be broken down into components: \( v_{x} = 245 \cos(\theta) \) and \( v_{y} = 245 \sin(\theta) \).
04

Apply Vector Addition

The ground velocity of the plane (\( \vec{v}_{ground} \)) is the vector sum of the plane's velocity and the wind's velocity. Since we want the resultant ground velocity to be directly west (only in the x-direction), \( \vec{v}_{ground} \) can be written as: \( v_{x} = 245 \cos(\theta) \) and \( v_{y} - 38 = 0 \), where \( v_{y} = 245 \sin(\theta) \).
05

Solve for \( \theta \)

Since \( v_{y} - 38 = 0 \), we have \( 245 \sin(\theta) = 38 \). Solving for \( \theta \), we get \( \sin(\theta) = \frac{38}{245} \). Hence, \( \theta = \arcsin\left( \frac{38}{245} \right) \).
06

Calculate the Angle \( \theta \)

Calculate \( \theta \) using a calculator: \( \theta \approx \arcsin(0.1551) \). Therefore, \( \theta \approx 8.94^\circ \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Relative Velocity and Its Implications in Navigation
The concept of relative velocity is fundamental in understanding how different velocities influence each other. When you're dealing with objects moving through mediums like air or water, their speeds aren't absolute—they're relative. This is particularly important in navigation, especially for aircraft.
In the scenario where a plane desires to travel due west, but there's a wind blowing from the south to the north, we need to determine the actual path the plane must take. The pilot must account for both the plane's speed relative to the air and the wind's speed. This combined effect determines the plane's velocity relative to the ground, known as the ground speed.
  • **Relative velocity in navigation:** It's the vector sum of the vehicle's velocity and the medium's velocity.
  • **Goal:** Achieve a target direction, like due west, which requires compensating for any extra directional forces (wind).
This explains why the plane deviates slightly from the direct path we might initially imagine it should take.
Understanding Trigonometric Functions in Vector Problems
Trigonometric functions are mathematical tools that link angles to sides of triangles. This connection is very useful in breaking down and reconstructing vectors, especially in navigation problems.
For our navigation problem, the angle (\( \theta \)) that the plane must head is determined using the sine function. The reason for this is that sine, cosine, and tangent functions allow us to decompose any directional force into perpendicular components (x and y axes in a 2-D plane).
  • **The role of sine and cosine:** These functions help break down the plane's velocity into a westward (x-direction) and a northward (y-direction) component.
  • **Formulas:** - \( v_{x} = 245 \cos(\theta) \) describes the component along the x-axis. - \( v_{y} = 245 \sin(\theta) \) describes the component along the y-axis.
To solve for \( \theta \), we use the inverse sine function: \( \theta = \arcsin \left( \frac{38}{245} \right) \). This step is crucial, as it helps the pilot adjust course to offset the wind's effect.
Airplane Navigation in the Presence of Wind
Crafting a flight path for an airplane requires careful navigation skills, especially when dealing with winds. The pilot must understand how vectors and wind affect the trajectory. In this problem, the plane's cruising speed and wind speed are two key vectors that must be combined using vector addition.
The pilot seeks to negate the wind's northward push while traveling due west. Hence, understanding the relationship between airspeed, wind, and ground speed is crucial.
  • **Plane's effective velocity:** The resultant vector from the plane's thrust and the wind's force.
  • **Heading correction:** Adjustments in heading are vital to ensure westward travel, compensating for wind's influence.
  • **Practical example:** Pilots often use flight computers and instruments that measure wind velocity to make these corrections in real time.
Navigational accuracy depends significantly on accurately calculating the necessary heading angle using both empirical data and mathematical modeling.

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