/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 Two sources produce electromagne... [FREE SOLUTION] | 91Ó°ÊÓ

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Two sources produce electromagnetic waves. Source B produces a wavelength that is three times the wavelength produced by source A. Each photon from source A has an energy of \(2.1 \times 10^{-18} \mathrm{J}\) . What is the energy of a photon from source B?

Short Answer

Expert verified
Photons from Source B have an energy of \(0.7 \times 10^{-18} \, ext{J}\).

Step by step solution

01

Understand the relationship between energy and wavelength

The energy of a photon is related to its wavelength by the equation \( E = \frac{hc}{\lambda} \), where \( E \) is the photon energy, \( h \) is Planck's constant \( (6.626 \times 10^{-34} \text{ J}\cdot\text{s}) \), \( c \) is the speed of light \( (3 \times 10^8 \text{ m/s}) \), and \( \lambda \) is the wavelength of the photon.
02

Analyze the given information

Source A's photons have a wavelength \( \lambda_A \), and their energy is \(2.1 \times 10^{-18} \, ext{J}\). Source B produces photons with wavelength \( \lambda_B = 3 \lambda_A \). We need to find the energy of photons from source B.
03

Relate the energies to the wavelengths

Since wavelength and energy are inversely proportional \( E \propto \frac{1}{\lambda} \), if source B has a wavelength that is three times greater than source A, the energy will be a third of that of source A's photons, i.e., \( E_B = \frac{E_A}{3} \).
04

Calculate the energy for source B

Given \( E_A = 2.1 \times 10^{-18} \, ext{J} \), the energy of a photon from source B will be \( E_B = \frac{2.1 \times 10^{-18} \, ext{J}}{3} = 0.7 \times 10^{-18} \, ext{J} \).
05

Finalize the solution

Confirm that using the relationship between wavelengths and photon energy, the calculation is complete and result meets conditions given in the problem.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electromagnetic Waves
Electromagnetic waves are disturbances in electric and magnetic fields that propagate through space. Unlike mechanical waves, they do not require a medium to travel. This means they can travel through a vacuum, such as space, which is why we can observe light from distant stars.
These waves cover a spectrum that includes radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. Each type of wave within this spectrum has its own unique frequency and wavelength, which determines its energy level and the potential applications or phenomena it can be involved in.
Electromagnetic waves are generated by accelerating charges, such as electrons. When these charges change speed or direction, they produce oscillating electric and magnetic fields that propagate outward as electromagnetic waves.
  • Radio waves have the longest wavelength and lowest energy.
  • Gamma rays have the shortest wavelength and highest energy.
Understanding electromagnetic waves helps us delve into various physical phenomena like photon energy, which is a crucial concept in understanding light's interaction with matter.
Wavelength
Wavelength is a key property of waves, particularly electromagnetic waves. It is defined as the distance between consecutive crests (or troughs) of a wave. Essentially, it is a measure of how stretched or compressed a wave is.
Wavelength is usually denoted by the Greek letter lambda (\( \lambda \)) and is typically measured in meters (m).
In the context of electromagnetic waves, the wavelength determines the wave's type, color (in the visible spectrum), and its energy. The relationship between wavelength and energy is an inverse one - as wavelength increases, energy decreases.
  • Longer wavelength means lower frequency and lower energy.
  • Shorter wavelength means higher frequency and higher energy.
This inverse relationship explains why waves produced by source B, which have a wavelength three times that of source A, have a photon energy that is one-third. This is because the energy of a photon is inversely proportional to its wavelength.
Planck's Constant
Planck's constant is a fundamental quantity in quantum mechanics, crucial in the study of electromagnetic radiation. It is symbolized as \( h \) and has a value of \( 6.626 \times 10^{-34} \text{ J}\cdot\text{s} \).
This constant is significant because it relates the energy of a photon to its frequency through the equation \( E = h \cdot f \), where \( E \) is the energy, and \( f \) is the frequency of the photon.
Another important expression where Planck's constant plays a pivotal role is in the equation \( E = \frac{h \cdot c}{\lambda} \) that describes photon energy as a function of wavelength.
Planck's constant effectively quantifies the amount of energy that is carried by a single quantum, or photon, of electromagnetic waves. As a fundamental constant, it underpins many quantum phenomena and highlights the particle nature of light in addition to its wave characteristics.
  • It helps bridge classical and quantum physics, particularly explaining phenomena like black body radiation and the photoelectric effect.
Speed of Light
The speed of light is a constant and fundamental aspect of the universe. Notably, it is the speed at which electromagnetic waves propagate through a vacuum. Denoted by the symbol \( c \), its value is approximately \( 3 \times 10^8 \text{ m/s} \).
This speed is crucial in the equations that describe the behavior of electromagnetic waves, such as the photon energy equation \( E = \frac{hc}{\lambda} \).
One of the essential roles of the speed of light is in determining how fast information can travel across the universe. It is a limit that underpins much of our understanding of physics and the structure of space-time.
The speed of light is pivotal in Einstein's theory of relativity, where it defines the relationship between time and space.
  • In the context of the problem, it helps quantify the energy carried by photons based on their wavelength.
  • Plays a significant role in determining the behavior of electromagnetic waves across different media.
Understanding the speed of light allows us to grasp the scale and dynamics of the universe, from the transmission of light from the Sun to Earth, to the fundamental limits of communication across cosmic distances.

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Most popular questions from this chapter

The work function of a metal surface is \(4.80 \times 10^{-19} \mathrm{J}\) . The maximum speed of the electrons emitted from the surface is \(v_{\mathrm{A}}=7.30 \times 10^{5} m/s\) when the wavelength of the light is \(\lambda_{\mathrm{A}} .\) However, a maximum speed of \(v_{\mathrm{B}}=5.00 \times 10^{5} m / s\)is observed when the wavelength is \(\lambda_{\mathrm{B}}\) . Find the wavelengths \(\lambda_{\mathrm{A}}\) and \(\lambda_{\mathrm{B}}\) .

In a Young's double-slit experiment that uses electrons, the angle that locates the first-order bright fringes is \(\theta_{\mathrm{A}}=1.6 \times 10^{-4}\) degrees when the magnitude of the electron momentum is \(p_{\mathrm{A}}=1.2 \times 10^{-22} \mathrm{kg} \cdot \mathrm{m} / \mathrm{s}\) . With the same double slit, what momentum magnitude \(p_{\mathrm{B}}\) is necessary so that an angle of \(\theta_{\mathrm{B}}=4.0 \times 10^{-4}\) degrees locates the first-order bright fringes?

An owl has good night vision because its eyes can detect a light intensity as small as \(5.0 \times 10^{-13} W/m^{2}\) . What is the minimum number of photons per second that an owl eye can detect if its pupil has a diameter of 8.5 mm and the light has a wavelength of 510 nm?

The kinetic energy of a particle is equal to the energy of a photon. The particle moves at 5.0% of the speed of light. Find the ratio of the photon wavelength to the de Broglie wavelength of the particle.

A glass plate has a mass of 0.50 \(\mathrm{kg}\) and a specific heat capacity of 840 \(\mathrm{J} /\left(\mathrm{kg} \cdot \mathrm{C}^{\circ}\right) .\) The wavelength of infrared light is \(6.0 \times 10^{-5} m\) , while the wavelength of blue light is \(4.7 \times 10^{-7} \mathrm{m}\) . Find the number of infrared photons and the number of blue photons needed to raise the temperature of the glass plate by \(2.0 \mathrm{C}^{\prime},\) assuming that all the photons are absorbed by the glass.

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