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The distance between adjacent slits of a certain diffraction grating is \(1.250 \times 10^{-5} \mathrm{m}\) . The grating is illuminated by monochromatic light with a wavelength of \(656.0 \mathrm{nm},\) and is then heated so that its temperature increases by 100.0 \(\mathrm{C}^{\circ} .\) Determine the change in the angle of the seventh order principal maximum that occurs as a result of thermal expansion of the grating. The cofficient of linear expansion for the diffaction grating is \(1.30 \times 10^{-4}\left(\mathrm{C}^{9}\right)^{-1} .\) Be sure to include the proper algebraic sign with your answer: \(+\) if the angle increases, - if the angle decreases.

Short Answer

Expert verified
The angle decreases by approximately \(-0.05^\circ\).

Step by step solution

01

Calculate Initial Angle

Firstly, we need to determine the initial angle for the seventh-order maximum by using the diffraction grating formula: \( d \sin\theta = m\lambda \), where \( d \) is the distance between slits, \( m \) is the order of the maximum, and \( \lambda \) is the wavelength of the light. Given \( d = 1.250 \times 10^{-5} \) m, \( m = 7 \), and \( \lambda = 656.0 \) nm = \( 656.0 \times 10^{-9} \) m, we solve for \( \sin\theta \):\[ \sin\theta = \frac{7 \times 656.0 \times 10^{-9}}{1.250 \times 10^{-5}}. \]
02

Calculate Initial \( \theta \)

Continuing from Step 1, compute \( \sin\theta \):\[ \sin\theta = \frac{4592.0 \times 10^{-9}}{1.250 \times 10^{-5}} = 0.36736. \]Then find \( \theta \) using the inverse sine function:\[ \theta = \sin^{-1}(0.36736) \approx 21.57^\circ. \]
03

Determine the Change in Linear Spacing from Expansion

Calculate the change in the distance \( d \) due to thermal expansion. The change in spacing \( \Delta d \) is given by:\[ \Delta d = \alpha \cdot \Delta T \cdot d, \]where \( \alpha = 1.30 \times 10^{-4} \mathrm{C}^{-1} \) is the coefficient of linear expansion, and \( \Delta T = 100.0 \mathrm{C}^{\circ} \). Substitute the known values:\[ \Delta d = 1.30 \times 10^{-4} \cdot 100 \cdot 1.250 \times 10^{-5} = 1.625 \times 10^{-8} \text{ m}. \]
04

Calculate New Slit Spacing

The new distance between slits \( d' \) is the original distance plus the change due to expansion:\[ d' = d + \Delta d = 1.250 \times 10^{-5} + 1.625 \times 10^{-8} = 1.251625 \times 10^{-5} \text{ m}. \]
05

Calculate New Angle for the Seventh-Order Maximum

Using the new slit spacing \( d' \), calculate the new angle \( \theta' \) for the seventh-order maximum using the same diffraction formula:\[ \sin\theta' = \frac{7 \times 656.0 \times 10^{-9}}{1.251625 \times 10^{-5}}. \]Then solve for \( \theta' \):\[ \sin\theta' = \frac{4592.0 \times 10^{-9}}{1.251625 \times 10^{-5}} = 0.36692. \]\[ \theta' = \sin^{-1}(0.36692) \approx 21.52^\circ. \]
06

Determine the Change in Angle

Finally, calculate the change in angle \( \Delta\theta \):\[ \Delta\theta = \theta' - \theta = 21.52^\circ - 21.57^\circ = -0.05^\circ. \]The negative sign indicates a decrease in angle.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Angle Change
In the context of a diffraction grating, the angle change refers to the variation in the angle at which light is diffracted due to changes in grating parameters. When discussing diffraction, particularly for a prism or grating, the angle of diffraction changes when either the wavelength of light or the spacing of the grating components changes. Here, we consider the angle between the incoming light and the diffraction grating line which shifts due to adjustments in slit spacing caused by thermal expansion. Calculating the angle change is vital for applications relying on precise optical arrangements, as even a small deviation in angle can significantly impact the resulting light dispersion. This exercise required calculating the extent of angle change when the grating is affected by thermal expansion.
Thermal Expansion
Thermal expansion is a physical property where the size of an object changes in response to temperature variations. It is quite common in solids, including diffraction gratings, and is determined by the material's coefficient of linear expansion.
  • As temperature rises, the material expands, leading to an increase in the distance between elements like the slits of the grating.
  • This expansion affects the properties of materials such as metals, plastics, and ceramics used in scientific instruments and everyday objects.
In the exercise, the grating expands due to a temperature increase of 100°C, which is consistent with most materials that expand slightly with heat. To calculate how much each material expands, the initial size, temperature change, and linear expansion coefficient must be considered. Understanding thermal expansion helps predict material behavior in various environments, ensuring both safety and performance.
Diffraction Formula
The diffraction grating formula is a fundamental equation used to describe and calculate the angles at which light of different wavelengths is diffracted. The formula is expressed as:\[d \sin \theta = m\lambda \]where:
  • \(d\) is the distance between adjacent slits.
  • \(\theta\) is the angle of diffraction.
  • \(m\) is the order of the diffracted maximum, an integer value.
  • \(\lambda\) is the wavelength of the light used.
This equation is a cornerstone in optical engineering, allowing for precise calculations of how light is diffracted at specific angles. In the exercise, this formula is used to determine both the initial and changed angles of diffraction due to thermal expansion. It shows that the relative change in slit distance directly impacts the angles, emphasizing the interplay between physical changes and optical outcomes.
Linear Expansion Coefficient
The linear expansion coefficient, denoted as \( \alpha \), quantifies how much a material will expand per unit length per degree change in temperature. This constant is critical when calculating changes in dimensions caused by temperature fluctuations in engineering and physics.
  • The value of \( \alpha \) varies between materials, with metals typically having higher coefficients than ceramics or polymers.
  • In the given exercise, the coefficient is \(\alpha = 1.30 \times 10^{-4} \, \text{C}^{-1} \), specific to the grating material.
This coefficient allows us to calculate the change in the slit distance as a function of temperature, which directly influences the angle of diffraction of light. Accurate predictions using \(\alpha\) ensure that devices and systems that involve precise measurements, like spectrometers and lasers, maintain their required specifications despite thermal influences.

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Most popular questions from this chapter

A flat screen is located 0.60 m away from a single slit. Light with a wavelength of 510 nm (in vacuum) shines through the slit and produces a diffraction pattern. The width of the central bright fringe on the screen is 0.050 m. What is the width of the slit?

A soap film \((n=1.33)\) is 465 nm thick and lies on a glass plate \((n=1.52) .\) Sunlight, whose wavelengths (in vacuum) extend from 380 to \(750 \mathrm{nm},\) travels through the air and strikes the film perpendicularly. For which wavelength(s) in this range does destructive interference cause the film to look dark in reflected light?

Violet light (wavelength \(=410 \mathrm{nm} )\) and red light (wave length \(=660 \mathrm{nm}\) ) lie at opposite ends of the visible spectrum. (a) For each wavelength, find the angle \(\theta\) that locates the first-order maximum produced by a grating with 3300 lines/cm. This grating converts a mixture of all colors between violet and red into a rainbow-like dispersion between the two angles. Repeat the calculation above for \((\mathbf{b})\) the second order maximum and \((\mathbf{c})\) the third-order maximum. (d) From your results, decide whether there is an overlap between any of the "rainbows" and, if so, specify which orders overlap.

Point A is the midpoint of one of the sides of a square. On the side opposite this spot, two in-phase loudspeakers are located at adjacent corners, as in Figure 27.41. Standing at point A you hear a loud sound because of constructive interference between the identical sound waves coming from the speakers. As you walk along the side of the square toward either empty corner, the loudness diminishes gradually to nothing and then increases again until you hear a maximally loud sound at the corner. If the length of each side of the square is 4.6 m, find the wavelength of the sound waves.

Light of wavelength 410 nm (in vacuum) is incident on a diffraction grating that has a slit separation of \(1.2 \times 10^{-5} \mathrm{m} .\) The distance between the grating and the viewing screen is 0.15 \(\mathrm{m} .\) A diffraction pattern is produced on the screen that consists of a central bright fringe and higher-order bright fringes (see the drawing). (a) Determine the distance \(y\) from the central bright fringe to the second-order bright fringe. (Hint: The diffraction angles are small enough that the approximation \(\tan \theta \approx \sin \theta\) can be used.) (b) If the entire apparatus is submerged in water \(\left(n_{\text { water }}=1.33\right),\) what is the distance \(y ?\)

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