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The wavelength of the laser beam used in a compact disc player is 780 \(\mathrm{nm}\) . Suppose that a diffraction grating produces first-order tracking beams that are 1.2 \(\mathrm{mm}\) apart at a distance of 3.0 \(\mathrm{mm}\) from the grating. Estimate the spacing between the slits of the grating.

Short Answer

Expert verified
The slit spacing is approximately 0.0039 mm.

Step by step solution

01

Understand the Problem

We are given the wavelength of the laser beam \( \lambda = 780 \, \mathrm{nm} \), and we need to calculate the distance between the slits of a diffraction grating. The problem states that the first-order diffraction beams are 1.2 \, \mathrm{mm} apart at a distance of 3.0 \, \mathrm{mm} from the grating.
02

Use the Diffraction Grating Formula

To find the spacing \( d \) between the slits, we can use the diffraction grating formula \( d \sin \theta = m\lambda \), where \( \theta \) is the angle of diffraction, \( m \) is the order of the maximum (in this case, \( m = 1 \)), and \( \lambda \) is the wavelength. We need to find \( \theta \) using the given information.
03

Calculate the Angle of Diffraction

Given that the first-order beams are 1.2 \, \mathrm{mm} apart at a distance of 3.0 \, \mathrm{mm}, we can use \( \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{1.2}{2} / 3.0 = 0.2 \). We assume small-angle approximation, so \( \theta \approx \sin \theta \approx \tan \theta \).
04

Solve for the Slit Spacing \( d \)

Using \( d \sin \theta = \lambda \), substituting \( \theta = 0.2 \) and \( \lambda = 780 \, \mathrm{nm} \), convert the wavelength to \( \mathrm{mm} \) as it is \( 7.8 \times 10^{-4} \, \mathrm{mm} \). Solve for \( d \): \( d = \frac{\lambda}{\sin \theta} = \frac{7.8 \times 10^{-4}}{0.2} = 3.9 \times 10^{-3} \, \mathrm{mm} \).
05

Conclude the Problem

The spacing between the slits of the diffraction grating is approximately \( 3.9 \times 10^{-3} \, \mathrm{mm} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laser Wavelength
When working with lasers in optical devices like compact disc players, the wavelength of the laser is crucial. The wavelength is essentially the distance between successive peaks of the light wave as it travels. For this problem, we have a laser wavelength of 780 nanometers (nm).
This small wavelength is ideal for reading the minute details on a disc.
The light's wavelength helps determine how light interacts with materials, in this case, the diffraction grating. Laser wavelengths are often measured in nanometers because visible light lies in the range of 400 - 700 nm.
  • For red lasers, like in this exercise, the wavelength is closer to the higher end of this range.
  • Different wavelengths correspond to different colors; red is longer and blue is shorter.
  • In optical systems, precision in the wavelength ensures better focus and clearer reading of data.
In practical applications, knowing the laser wavelength allows engineers to design appropriate components like gratings or lenses that effectively direct and utilize the laser beam.
Angle of Diffraction
The angle of diffraction is a key component when discussing diffraction gratings. It is the angle at which light emerges after striking the grating.
This angle helps determine where the light will land after being diffracted. In this specific problem, we use the small-angle approximation where the sine, tangent, and the angle itself in radians are nearly the same.
This is important in simplifying calculations when angles involved are small.
  • The angle can be calculated using basic trigonometry since we know the distances of the diffracted beams.
  • In this case, the tangent of the angle is the width of the separation of the first-order beams divided by the distance to the grating.
Knowing this angle allows us to solve for other critical parameters such as slit spacing using the diffraction formula.
First-order Beams
First-order beams are the first set of diffracted light rays after the primary beam that passes through a diffraction grating.
These beams carry important information because they are often the brightest and most distinct.
First-order beams are used in analytic applications due to their high intensity and straightforward calculations. The problem gives the distance between the first-order beams (1.2 mm) and the reference distance (3.0 mm) from the grating surface.
These metrics help in directly calculating the angle of diffraction.
  • Such order represents the first level of diffraction from the grating, where light has been bent by the smallest angle possible.
  • "Order" basically denotes how many wavelengths of path difference exist between adjacent slits for light emerging at this diffraction angle.
Using first-order beams simplifies the calculation since they give a clear picture of how far apart they are at a specific distance, which aids in estimating the slit spacing.
Slit Spacing
The distance between slits in a diffraction grating, referred to as 'slit spacing', is fundamental in determining how a light wave is diffracted.
In essence, the slit spacing affects the separation of light into its component wavelengths, colorfully arranging them.To estimate the slit spacing, the diffraction formula is used: \[ d \sin \theta = m \lambda \] where:
  • \( d \) is the slit spacing, needing calculation.
  • \( \theta \) is the angle of diffraction.
  • \( m \) is the order of the beams — here it's first-order so \( m = 1 \).
  • \( \lambda \) is the known wavelength of the laser.
Convert the laser's wavelength to the same unit (mm) as the distances, and solve for \( d \) to find the exact spacing between the slits.
Knowing this helps in a variety of applications, from CD players to spectroscopy, allowing the device to correctly interpret the light's information based on its diffracted pattern.
Well-calculated slit spacing enhances the device's ability to read data or analyze materials without error.

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Most popular questions from this chapter

In a Young's double-slit experiment, the seventh dark fringe is located 0.025 \(\mathrm{m}\) to the side of the central bright fringe on a flat screen, which is 1.1 \(\mathrm{m}\) away from the slits. The separation between the slits is \(1.4 \times 10^{-4} \mathrm{m} .\) What is the wavelength of the light being used?

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It is claimed that some professional baseball players can see which way the ball is spinning as it travels toward home plate. One way to judge this claim is to estimate the distance at which a batter can first hope to resolve two points on opposite sides of a baseball, which has a diameter of 0.0738 m. (a) Estimate this distance, assuming that the pupil of the eye has a diameter of 2.0 mm and the wavelength of the light is 550 nm in vacuum. (b) Considering that the distance between the pitcher’s mound and home plate is 18.4 m, can you rule out the claim based on your answer to part (a)?

Two diffraction gratings, A and B, are located at the same distance from the observation screens. Light with the same wavelength is used for each. The separation between adjacent principal maxima for grating A is 2.7 cm, and for grating B it is 3.2 cm. Grating A has 2000 lines per meter. How many lines per meter does grating B have? (Hint: The diffraction angles are small enough that the approximation \(\sin \theta \approx \tan \theta\) can be used.)

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